Jacque
I believe that the engine can start processing the second call before the first
is finished after I did a little experiment:
One card, button1, button2 and a field
Both buttons with this script:
on mouseUp
oneOrTwo
end mouseUp
A card script with
on oneOrTwo
put "one" & return after Field "Field"
wait 50 with messages
put "two" & return after Field "Field"
end oneOrTwo
Clicking on the buttons in quick succession gives one, one, two, two.
I found out that you don’t even need two buttons. Hitting one button twice
quickly will give the same effect.
Regards
Peter
> On 23 Jan 2015, at 11:26, J. Landman Gay <jac...@hyperactivesw.com> wrote:
>
> Suppose I have a long handler that includes a few "wait with messages" so
> that users can continue interacting with the stack while it runs. The user
> does something that calls the long handler while it is still running from a
> previous instance. Assume there is no flag in the script to prevent that.
>
> Does the engine queue the second call until the long handler finishes, and
> then send the message from the second call (serial responses)?
>
> Or does the engine run two instances of the long handler simultaneously? If
> so, what happens to the values of the variables?
>
> Or something else?
>
> I've never allowed this to happen before but I find myself in a position
> where simultaneous calls would be the best way to handle things.
>
> --
> Jacqueline Landman Gay | jac...@hyperactivesw.com
> HyperActive Software | http://www.hyperactivesw.com
>
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