On Sun, Dec 7, 2014 at 7:47 AM, Geoff Canyon <gcan...@gmail.com> wrote:
> If the object in question is inside a group, you'd have to recurse your > way out, or you could use: > > put word -5 to -1 of the long id of btn 1 > > or if you prefer: > > put word -5 to -1 of the long name of btn 1 > > (the second would use the name of the card) for just the stack use: > > put word -2 to -1 of the long id of btn 1 > I wasn't thinking about substacks (durhh). I also didn't account for the different number of words in a card name if the card has a name vs. just an id. So if you want a reference to the containing stack (meaning the substack if there is one) then you'd need: function owningStack pID if word -5 of pID is "stack" then return word -5 to -1 of pID else return word -2 to -1 of pID end owningStack For the card id: function owningCardID pID if word -5 of pID is "stack" then return word -9 to -1 of pID else return word -6 to -1 of pID end owningCardID And for the card name: function owningCardName pID if word -5 of pID is "stack" then put -8 into S else put -5 into S if word S of pID is "id" then return word S-1 to -1 of pID else return word S to -1 of pID end owningCardName _______________________________________________ use-livecode mailing list use-livecode@lists.runrev.com Please visit this url to subscribe, unsubscribe and manage your subscription preferences: http://lists.runrev.com/mailman/listinfo/use-livecode
