4 and 2 1's? Isn't the test to produce the  result with the least amount of 
coins? This would still work. The idea is to try and fit the largest coin value 
into the remainder each time, until the remainder is zero. 

Bob


On Jan 31, 2013, at 5:54 AM, dunb...@aol.com wrote:

> Paul.
> 
> 
> As six pennies. As long as you have a "1", you should be OK.
> 
> 
> 
> 
> Craig Newman
> 
> 
> 
> 
> -----Original Message-----
> From: Paul D. DeRocco <pdero...@ix.netcom.com>
> To: 'How to use LiveCode' <use-livecode@lists.runrev.com>
> Sent: Thu, Jan 31, 2013 12:57 am
> Subject: RE: Coding challenge
> 
> 
>> From: Mark Wieder
>> 
>>> Now how would you do it if the available coin values were:
>> 
>>>        40,30,10,4,3,1
>> 
>>> That's a more interesting problem, but probably a less 
>>> interesting coding
>>> test, because I think it would involve a more brute force 
>>> approach, less
>>> elegance.
>> 
>> I'm missing something. Why would that be different?
> 
> How would you represent 6?
> 
> -- 
> 
> Ciao,               Paul D. DeRocco
> Paul                mailto:pdero...@ix.netcom.com 
> 
> 
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