The question was
Determine the minimum number of coins for change.
so the correct answer here would be 2 coins (3+3) rather than 6 coins
(1+1+...)
That's what makes this a more challenging case, but probably without as
elegant an answer ...
-- Alex.
On 31/01/2013 13:54, dunb...@aol.com wrote:
Paul.
As six pennies. As long as you have a "1", you should be OK.
Craig Newman
-----Original Message-----
From: Paul D. DeRocco <pdero...@ix.netcom.com>
To: 'How to use LiveCode' <use-livecode@lists.runrev.com>
Sent: Thu, Jan 31, 2013 12:57 am
Subject: RE: Coding challenge
From: Mark Wieder
Now how would you do it if the available coin values were:
40,30,10,4,3,1
That's a more interesting problem, but probably a less
interesting coding
test, because I think it would involve a more brute force
approach, less
elegance.
I'm missing something. Why would that be different?
How would you represent 6?
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