Me again Jerry

Changed the setup so that the pellets landing outside the big circle were 
ignored and just kept going until I had 1000 within the circles in a completely 
random pattern without Trig. Now the ratio in the smaller circle is 25% or ¼ 
like the area comparison would suggest. 

You do understand math much better than I do obviously!

Kelly

> On 2Sep, 2020, at 10:10 PM, Dev <d...@porta.ca> wrote:
> 
> Hi Jerry
> 
> I just tried that because I’m no math wizard and need to see things. When 
> shooting a random shotgun blast of 1000 pellets into the centre of a target 
> square that contained the large circle and small circles, the ratio worked 
> out to around  0.2 - not 0.25. It seems the corners outside the big circle 
> receive about 20% of the shots, the inner circle gets another 20% and the 
> outer circle gets 60%. So I don’t understand your thought about ¼.
> 
> Kelly
> 
>> On 2Sep, 2020, at 9:43 PM, Jerry Jensen via use-livecode 
>> <use-livecode@lists.runrev.com> wrote:
>> 
>> Additional thought:
>> If you just used random x and y, then ignored points outside the larger 
>> circle, you would see that  1/4 of the points would be in the smaller circle.
>> 
>> No trig or integrals involved.
>> .Jerry
>> 
>>> On Sep 2, 2020, at 8:27 PM, Jerry Jensen via use-livecode 
>>> <use-livecode@lists.runrev.com> wrote:
>>> 
>>> 1/2 is the right answer.
>>> 
>>> Take your drawing of the circles. Cut a verrrryy thin radial slice from the 
>>> center to the outside circle. So thin that it is just a line. 
>>> 
>>> Now think of how likely a random point on that line will be in the part of 
>>> the line that was in the smaller circle. The part that was from the smaller 
>>> circle is HALF as long as the entire line.
>>> 
>>> Now add up all the possible positions of that line. Why would that change 
>>> the answer?
>>> 
>>> Congratulations, you understand integrals!
>>> .Jerry
>>> 
>>>> On Sep 2, 2020, at 7:38 PM, Roger Guay via use-livecode 
>>>> <use-livecode@lists.runrev.com> wrote:
>>>> 
>>>> Your chance to be Genius du Jour:
>>>> 
>>>> If I construct 2 concentric circles, one being half the radius of the 
>>>> larger, then simple math shows that the smaller circle has an area ¼ the 
>>>> area of the larger.
>>>> Now if I generate a random point within the radius of the larger circle, I 
>>>> should expect that the probability of it landing in the smaller circle to 
>>>> be ¼.
>>>> But, I must be doing something wrong because I get ½ !
>>>> 
>>>> Here is my script:
>>>> 
>>>> on mouseDown
>>>> 
>>>>    getStuff
>>>> 
>>>> end mouseDown
>>>> 
>>>> 
>>>> local tR, tTheta, tX0, tY0, tX1, tY1, tTotCount, tL, tLongCount
>>>> 
>>>> on getStuff
>>>> 
>>>>    put item 1 of the loc of grc OuterCircle into tx0
>>>> 
>>>>    put item 2 of the loc of grc OuterCircle into tY0
>>>> 
>>>>    put "" into tTotCount
>>>> 
>>>>    put "" into tLongCount
>>>> 
>>>>    emptyFlds
>>>> 
>>>> end getStuff
>>>> 
>>>> 
>>>> on mouseUp
>>>> 
>>>>    lock screen
>>>> 
>>>>    repeat 1000
>>>> 
>>>>            put random(200) into tR -- 200 is half the width of the larger 
>>>> circle
>>>> 
>>>>            if tR > 1 then
>>>> 
>>>>                    ## put random(2*pi) into tTheta1
>>>> 
>>>>                    get random(360)
>>>> 
>>>>                    put it*pi/180 into tTheta1
>>>> 
>>>>                    put tR*cos(tTheta1) into tX1
>>>>                    put tR*sin(tTheta1) into tY1
>>>> 
>>>>                    set the loc of grc Ptgrc to tX0 + tX1, tY0 - tY1 --- 
>>>> grc Ptgrc is a 2 pixle oval
>>>> 
>>>>                    if intersect(grc Ptgrc, grc InnerCircle, "opaque 
>>>> Pixels") then add 1 to tLongCount
>>>> 
>>>>                    add 1 to tTotCount
>>>> 
>>>>            end if
>>>> 
>>>>    end repeat
>>>>    put tTotCount into fld "totcountFld"
>>>> 
>>>>    put tLongCount into fld “LongCountFld"
>>>> 
>>>>    put tLongCount/tTotCount into fld "RatioFld"
>>>> 
>>>>    unlock screen
>>>> 
>>>> end mouseUp
>>>> 
>>>> 
>>>> Apparently, this does not generate a random point within the larger 
>>>> circle! Can someone please tell me what’s wrong here?
>>>> 
>>>> Thanks,
>>>> Roger
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>>> 
>>> 
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