Ralph, this is brilliant. I remember trying to do something similar years ago, and giving up because I didn't know how to do the math. I suck at math, or rather I am too lazy and impatient to work the problem.
Bob S > On Apr 3, 2020, at 14:27 , Ralph DiMola via use-livecode > <use-livecode@lists.runrev.com> wrote: > > Graham, > > This my distance calculation for what it's worth. > > Function distance lat1, lon1, lat2, lon2, unit > -- Calculate Distance between to points > -- > --lat1, lon1, lat2, lon2 are in deg.fractionalDegrees > -- Unit > -- if empty then miles > -- K = kilometers > -- N = nautical miles > local theta > local dist > > Put lon1 - lon2 into theta > put Sin(deg2rad(lat1)) * Sin(deg2rad(lat2)) + Cos(deg2rad(lat1)) * > Cos(deg2rad(lat2)) * Cos(deg2rad(theta)) into dist > > put Acos(dist) into dist > put rad2deg(dist) into dist > put dist * 60 * 1.1515 into dist > > switch unit > case "K" > put dist * 1.609344 into dist > case "N" > put dist * 0.8684 into dist > end switch > > Return dist > > End distance > > > Function rad2deg rad > Return rad / PI * 180.0 > end rad2deg > > > Ralph DiMola > IT Director > Evergreen Information Services > rdim...@evergreeninfo.net _______________________________________________ use-livecode mailing list use-livecode@lists.runrev.com Please visit this url to subscribe, unsubscribe and manage your subscription preferences: http://lists.runrev.com/mailman/listinfo/use-livecode