Does the equation that generates the graph lend itself to finding its first derivative - or are you dealing with data points with no generating equation?
Sent from my Verizon Wireless BlackBerry -----Original Message----- From: Bryan McCormick <br...@deepfoo.com> Sender: use-livecode-boun...@lists.runrev.com Date: Sat, 04 Dec 2010 14:10:26 To: <use-livecode@lists.runrev.com> Reply-To: How to use LiveCode <use-livecode@lists.runrev.com> Subject: Re: Finding local minima and maxima of a graph Peter, Yes, I have thousands of .csv files to process. I have data that is ordered by column containing high and low values. On 12/4/2010 12:56 PM, Bryan McCormick wrote: > I have a very large number of graphs to crunch through to find local > minima and maxima. The data is regularly spaced, which eliminated one > problem. I know too that the window value used has to be an adjustable > variable as peak and trough significance may need to be found for a wide > range of time periods within the data set. > > I had thought of using a moving average to find a slope of zero and then > use an offset function to find the peak and trough in time. > > I've used stackoverflow to have a look and apparently the problem is a > lot less trivial than I thought. > > Any suggestions for fitting to a function, using the graphing functions > in rev, etc would be most welcome. _______________________________________________ use-livecode mailing list use-livecode@lists.runrev.com Please visit this url to subscribe, unsubscribe and manage your subscription preferences: http://lists.runrev.com/mailman/listinfo/use-livecode _______________________________________________ use-livecode mailing list use-livecode@lists.runrev.com Please visit this url to subscribe, unsubscribe and manage your subscription preferences: http://lists.runrev.com/mailman/listinfo/use-livecode
