I really don't understand what you have done here. On 27/11/14 11:52, Paul Sladen wrote:
The remaining fifteen lower bits converted to decimal match exactly:> >>F3 01 90 B7 - 42.79 - 0x90b7 & 0x7fff => 0x10b7 => 4279 decimal > >>F3 01 97 78 - 60.08 - 0x9778 & 0x7fff => 0x1778 => 6008 decimal
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