Hi Benjamin, [Please do not top-post]
On Sun, Nov 19, 2023 at 6:08 PM Szőke Kálmán Benjamin <egyszer...@freemail.hu> wrote: > (void)(devno); is need because devno arguments is an unused variable, need to > use this solution to suppress any potential warnings. No, devno is a function parameter. There is no warning if '(void)(devno)' is removed.
