Hi Benjamin,

[Please do not top-post]

On Sun, Nov 19, 2023 at 6:08 PM Szőke Kálmán Benjamin
<egyszer...@freemail.hu> wrote:

> (void)(devno); is need because devno arguments is an unused variable, need to 
> use this solution to suppress any potential warnings.

No, devno is a function parameter. There is no warning if
'(void)(devno)' is removed.

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