On 21.09.2017 12:51, Heinrich Schuchardt wrote:
memset(newpart, '\0', sizeof(newpart));
only initializes the firest 4 or 8 bytes of *newpart and not the whole
structure disk_part.
We should use sizeof(struct disk_part).
Identified by cppcheck.
Fixes: 09a49930e41 GPT: read partition table from device into a data structure
Signed-off-by: Heinrich Schuchardt <xypron.g...@gmx.de>
---
cmd/gpt.c | 4 ++--
1 file changed, 2 insertions(+), 2 deletions(-)
diff --git a/cmd/gpt.c b/cmd/gpt.c
index 638aa19826..a9c562123f 100644
--- a/cmd/gpt.c
+++ b/cmd/gpt.c
@@ -190,10 +190,10 @@ static void del_gpt_info(void)
static struct disk_part *allocate_disk_part(disk_partition_t *info, int
partnum)
{
struct disk_part *newpart;
- newpart = malloc(sizeof(*newpart));
+ newpart = malloc(sizeof(struct disk_part));
if (!newpart)
return ERR_PTR(-ENOMEM);
- memset(newpart, '\0', sizeof(newpart));
+ memset(newpart, '\0', sizeof(struct disk_part));
newpart->gpt_part_info.start = info->start;
newpart->gpt_part_info.size = info->size;
Why don't you use calloc() instead and drop the memset completely?
Thanks,
Stefan
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