From: Stephen Warren <swar...@nvidia.com>
This better mirrors the behaviour of bash, for example:
$ if test -z = -z; then echo yes; else echo no; fi
yes
This is parsed as a string comparison of "-z" and "-z", since the check
for the binary "=" operator occurs first. Without this change, the
command would be parsed as a -z test of "-", followed by a syntax error;
a trailing -z without and operand.
This is a behavioural change, but I believe any commands affected were
previously invalid or bizarely formed.
Signed-off-by: Stephen Warren <swar...@nvidia.com>
---
v3: New patch.
---
common/cmd_test.c | 8 ++++----
1 file changed, 4 insertions(+), 4 deletions(-)
diff --git a/common/cmd_test.c b/common/cmd_test.c
index 69b1b4cee69a..e65dd531877e 100644
--- a/common/cmd_test.c
+++ b/common/cmd_test.c
@@ -39,10 +39,6 @@ const struct {
int op;
int adv;
} op_adv[] = {
- {0, "-o", OP_OR, 1},
- {0, "-a", OP_AND, 1},
- {0, "-z", OP_STR_EMPTY, 2},
- {0, "-n", OP_STR_NEMPTY, 2},
{1, "=", OP_STR_EQ, 3},
{1, "!=", OP_STR_NEQ, 3},
{1, "<", OP_STR_LT, 3},
@@ -53,6 +49,10 @@ const struct {
{1, "-le", OP_INT_LE, 3},
{1, "-gt", OP_INT_GT, 3},
{1, "-ge", OP_INT_GE, 3},
+ {0, "-o", OP_OR, 1},
+ {0, "-a", OP_AND, 1},
+ {0, "-z", OP_STR_EMPTY, 2},
+ {0, "-n", OP_STR_NEMPTY, 2},
};
static int do_test(cmd_tbl_t *cmdtp, int flag, int argc, char * const argv[])
--
1.8.1.5
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