On 12/01/14 08:12, Roelof Wobben wrote:
# Write a Python procedure fix_machine to take 2 string inputs
# and returns the 2nd input string as the output if all of its
# characters can be found in the 1st input string and "Give me
# something that's not useless next time." if it's impossible.
OK< So there is nothing here about the orders being the same.
That makes it much easier.
# 5***** # If you've graduated from CS101,
# Gold # try solving this in one line.
Its not too hard to do in one line.
I think a filtered list comprehension and the all() function
would be one way.
print "Test case 1: ", fix_machine('UdaciousUdacitee', 'Udacity') ==
"Give me something that's not useless next time."
print "Test case 2: ", fix_machine('buy me dat Unicorn', 'Udacity') ==
'Udacity'
print "Test case 3: ", fix_machine('AEIOU and sometimes y... c',
'Udacity') == 'Udacity'
print "Test case 4: ", fix_machine('wsx0-=mttrhix', 't-shirt') == 't-shirt'
I'd not use the while loop personally, I'd go for a for loop over b
and use the in operation on a. So Something like
for letter in b:
if letter not in a:
return ....
return b
HTH
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.flickr.com/photos/alangauldphotos
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