sure:
let s = IO.uploadedFile(file).asSpreadsheet();
machine_prefix_en= 'Machine for '
machine_prefix_de= 'Maschine für '
s.rows().forEach(row =>{
let concept = skos.createConcept({
uri: ' *http:sampleuri.com/id <http://sampleuri.com/id> * /'+
row['id'],
notation: row.id
})
//adding the current row to a taxon
//concept.topConceptOf= graph.namedNode(' *http:sampleuri.com/
<http://sampleuri.com/id>conceptschema1*')
graph.addTriples
try{
prefLabelwithLang(concept,machine_prefix_en+row['label
en'],'en')
prefLabelwithLang(concept,machine_prefix_de+row['label
de'],'de')
let conceptLangEn = graph.langString(row['concept en'],'en')
concept.add(skos.definition, conceptLangEn);
let conceptLangDe = graph.langString(row['concept de'],'de')
concept.add(skos.definition, conceptLangDe);
//first level of clasification
firstLevelTaxon(concept, row['id'])
}
catch{
console.log()
}
}//end row
)//end forEach
//working with german
function splitStringAtParentheses(input) {
// Use a regular expression to match the content between parentheses
const match = input.match(/^(.*?)\s*\(([^)]+)\)$/);
// If a match is found, return an array with both parts, otherwise return
null
if (match) {
return [match[1].trim(), match[2].trim()];
} else {
return null;
}
}
function prefLabelwithLang(my_concept,my_label,my_lang){
let prefLabelLang = graph.langString(my_label,my_lang)
my_concept.add(skos.prefLabel, prefLabelLang);
}
function altLabelwithLang(my_concept,my_label,my_lang){
let altLabelLang = graph.langString(my_label,my_lang)
my_concept.add(skos.altLabel, altLabelLang);
}
function firstLevelTaxon(my_concept, id){
const taxonLevel1
=["1.17.03.01.00.00","1.17.03.02.00.00","1.17.03.03.00.00","1.17.03.04.00.00","1.17.03.05.00.00","1.17.03.06.00.00"]
if (taxonLevel1.includes(id)){
my_concept.broader = graph.namedNode(' *http:sampleuri.com/
<http://sampleuri.com/id>*/1.17.03.00.00.00')
}//if not first level
else{
const idArray = id.split(".");
//evaluating the taxon
if (idArray[-1] !== '00'){
broaded_id = ' *http:sampleuri.com/ <http://sampleuri.com/id>*/
1.17.03.'+idArray[3]+'.'+idArray[4]+'.00'
my_concept.broader = graph.namedNode(broaded_id)
}
}//elnd else first level
//console.log()
}//firstLevelTaxon
function prefLabelwithLang(my_concept,my_label,my_lang){
let prefLabelLang = graph.langString(my_label,my_lang)
my_concept.add(skos.prefLabel, prefLabelLang);
}
function altLabelwithLang(my_concept,my_label,my_lang){
let altLabelLang = graph.langString(my_label,my_lang)
my_concept.add(skos.altLabel, altLabelLang);
}
El lun, 18 nov 2024 a las 11:34, Holger Knublauch (<hol...@topquadrant.com>)
escribió:
> From the information provided I don't see anything wrong. But there may be
> other steps in your script. For example, you may change other resources
> that are not correctly typed and thus the sh:class constraint fails.
>
> Could you paste the whole script?
>
> Holger
>
>
> On 18 Nov 2024, at 11:07 AM, 'Luis Enrique Ramos García' via TopBraid
> Suite Users <topbraid-users@googlegroups.com> wrote:
>
> Dear All,
>
> I am receiving this error message in the execution of an script:
>
>
> * Value must be an instance of skos:Concept *
>
>
> *Value: http:sampleuri.com/id <http://sampleuri.com/id> Suggestion: Set
> type of http:sampleuri.com/id <http://sampleuri.com/id> to Concept*
>
> However, in the output of statements I get:
>
> <http:sampleuri.com/id>
> * a skos:Concept ;*
> skos:broader <http:sampleuri.com/anotherid> ;
>
> Where I can see that http:sampleuri.com/id is a skos:Concept,
>
> thus I wonder why I am recieving this message?.
>
> this is the part of the script I use to create the concepts:
>
>
> let concept = skos.createConcept({
> uri: 'http:sampleuri.com/'+ row['id'],
> notation: row.id
> })
>
> Best regards
>
>
> Luis Ramos
>
>
>
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> .
>
>
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