possible, let me check.
But, I would like to try another way.
The usecase I have is that I want to upload concepts that are organized in
categorized ids, e.g 1.0.0, 1.1.0, 1.0.2, 1.1.1, 1.1.2. (spreadsheet).
Thus, I want to reproduce it in my tree so:
1.1.0
1.1.1
1.1.2
which should be the best way to do it?
script or importing spreadsheet?,
Luis
El lun, 18 nov 2024 a las 11:41, Holger Knublauch (<hol...@topquadrant.com>)
escribió:
> Ok thanks. When you run this in Preview mode from the Script Editor panel,
> can you see which resources are changed?
>
> The system will perform constraint validation on those changed resources.
> Maybe some of them don't have rdf:type skos:Concept.
>
> Holger
>
>
> On 18 Nov 2024, at 11:38 AM, 'Luis Enrique Ramos García' via TopBraid
> Suite Users <topbraid-users@googlegroups.com> wrote:
>
> sure:
>
> let s = IO.uploadedFile(file).asSpreadsheet();
> machine_prefix_en= 'Machine for '
> machine_prefix_de= 'Maschine für '
>
>
> s.rows().forEach(row =>{
> let concept = skos.createConcept({
> uri: ' *http:sampleuri.com/id <http://sampleuri.com/id> * /'+
> row['id'],
> notation: row.id
> })
> //adding the current row to a taxon
> //concept.topConceptOf= graph.namedNode(' *http:sampleuri.com/
> <http://sampleuri.com/id>conceptschema1*')
>
> graph.addTriples
>
> try{
> prefLabelwithLang(concept,machine_prefix_en+row['label
> en'],'en')
> prefLabelwithLang(concept,machine_prefix_de+row['label
> de'],'de')
> let conceptLangEn = graph.langString(row['concept en'],'en')
> concept.add(skos.definition, conceptLangEn);
> let conceptLangDe = graph.langString(row['concept de'],'de')
> concept.add(skos.definition, conceptLangDe);
> //first level of clasification
> firstLevelTaxon(concept, row['id'])
> }
> catch{
> console.log()
> }
> }//end row
> )//end forEach
>
> //working with german
>
>
> function splitStringAtParentheses(input) {
> // Use a regular expression to match the content between parentheses
> const match = input.match(/^(.*?)\s*\(([^)]+)\)$/);
>
> // If a match is found, return an array with both parts, otherwise
> return null
> if (match) {
> return [match[1].trim(), match[2].trim()];
> } else {
> return null;
> }
> }
>
>
>
> function prefLabelwithLang(my_concept,my_label,my_lang){
> let prefLabelLang = graph.langString(my_label,my_lang)
> my_concept.add(skos.prefLabel, prefLabelLang);
> }
>
> function altLabelwithLang(my_concept,my_label,my_lang){
> let altLabelLang = graph.langString(my_label,my_lang)
> my_concept.add(skos.altLabel, altLabelLang);
> }
>
> function firstLevelTaxon(my_concept, id){
> const taxonLevel1
> =["1.17.03.01.00.00","1.17.03.02.00.00","1.17.03.03.00.00","1.17.03.04.00.00","1.17.03.05.00.00","1.17.03.06.00.00"]
> if (taxonLevel1.includes(id)){
> my_concept.broader = graph.namedNode(' *http:sampleuri.com/
> <http://sampleuri.com/id>*/1.17.03.00.00.00')
> }//if not first level
>
> else{
> const idArray = id.split(".");
> //evaluating the taxon
> if (idArray[-1] !== '00'){
> broaded_id = ' *http:sampleuri.com/ <http://sampleuri.com/id>*
> /1.17.03. <http://1.17.0.3/>'+idArray[3]+'.'+idArray[4]+'.00'
> my_concept.broader = graph.namedNode(broaded_id)
> }
> }//elnd else first level
>
> //console.log()
> }//firstLevelTaxon
>
> function prefLabelwithLang(my_concept,my_label,my_lang){
> let prefLabelLang = graph.langString(my_label,my_lang)
> my_concept.add(skos.prefLabel, prefLabelLang);
> }
>
> function altLabelwithLang(my_concept,my_label,my_lang){
> let altLabelLang = graph.langString(my_label,my_lang)
> my_concept.add(skos.altLabel, altLabelLang);
> }
>
> El lun, 18 nov 2024 a las 11:34, Holger Knublauch (<hol...@topquadrant.com>)
> escribió:
>
>> From the information provided I don't see anything wrong. But there may
>> be other steps in your script. For example, you may change other resources
>> that are not correctly typed and thus the sh:class constraint fails.
>>
>> Could you paste the whole script?
>>
>> Holger
>>
>>
>> On 18 Nov 2024, at 11:07 AM, 'Luis Enrique Ramos García' via TopBraid
>> Suite Users <topbraid-users@googlegroups.com> wrote:
>>
>> Dear All,
>>
>> I am receiving this error message in the execution of an script:
>>
>>
>> * Value must be an instance of skos:Concept *
>>
>>
>> *Value: http:sampleuri.com/id <http://sampleuri.com/id> Suggestion: Set
>> type of http:sampleuri.com/id <http://sampleuri.com/id> to Concept*
>>
>> However, in the output of statements I get:
>>
>> <http:sampleuri.com/id>
>> * a skos:Concept ;*
>> skos:broader <http:sampleuri.com/anotherid> ;
>>
>> Where I can see that http:sampleuri.com/id is a skos:Concept,
>>
>> thus I wonder why I am recieving this message?.
>>
>> this is the part of the script I use to create the concepts:
>>
>>
>> let concept = skos.createConcept({
>> uri: 'http:sampleuri.com/'+ row['id'],
>> notation: row.id
>> })
>>
>> Best regards
>>
>>
>> Luis Ramos
>>
>>
>>
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>>
>>
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>
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