On Sunday, 15 January 2023 at 07:36:14 UTC zaqhie...@gmail.com wrote: Hi all,
I have a question: why SymPy (in JULIA and PYthon) unable to get the numerical answer for area of surface of revolution? Is it impossible? This is my question posted today on Julia Discourse: https://discourse.julialang.org/t/area-of-surface-of-revolution-integral-too-hard-to-be-computed-by-julia-sympy-and-python-sympy/92981 Please ask questions here rather than posting a link to somewhere else. You can numerically evaluate integrals using evalf: In [*1*]: x = symbols("x") ...: ...: f = (x**6 + 2)/(8*x**2) ...: g = sqrt(1 + diff(f,x)) ...: ...: h = 2*pi*Integral(((x**6 + 2)/(8*x**2))*sqrt(1 + diff(f,x)), (x, 1, 3)) In [*2*]: h Out[*2*]: 3 ⌠ ⎮ ___________________ ⎮ ╱ 3 6 ⎮ ⎛ 6 ⎞ ╱ 3⋅x x + 2 ⎮ ⎝x + 2⎠⋅ ╱ ──── + 1 - ────── ⎮ ╱ 4 3 ⎮ ╲╱ 4⋅x 2⋅π⋅⎮ ────────────────────────────────── dx ⎮ 2 ⎮ 8⋅x ⌡ 1 In [*3*]: h.evalf() Out[*3*]: 116.281297293490 -- Oscar -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/9ec8b552-e641-463a-823c-513bb8729cecn%40googlegroups.com.
