On Jun 6, 6:12 pm, Tomo Lazovich <[email protected]> wrote:
> Hi everyone,
>
Hi,

> I've been working on representations of operators and kets in the position
> and momentum bases. So far, from what I can tell, the desired behavior is to
> return something like DiracDelta(x_1-x_2) for a representation of |x_1>
> (position ket), and something like x_1*DiracDelta(x_1-x_2) for the
> representation of the X operator (position operator).
>
> My question, then, is what should the representation of a full expression
> look like. Lets say we execute the following lines:
>
> >> x_ket = XKet()
> >> x_op = XOp()
> >> represent(x_op*x_ket, basis=XOp())
>
> With the current behavior (well, once that desired behavior is fully
> implemented), it would return
>
> >> x_1*DiracDelta(x_1-x_2)**2
>
> because it simply returns the representations of each QExpr individually, so
> we get two delta functions out.
>
> Is this what we actually expect the output of representing an expression
> like that to be?

No that's not what's expected. Whatever the representation of A and B
are, the representation of A*B is definitely not equal to the product
of the representations of A and of B.

In your case the x_op*x_ket is just a new ket, call it psi_ket. The
representation of psi_ket in the position basis would be <x_dummy|
psi_ket>. So that's what I would expect to get in general. Whether it
should reduce to something simple is a different story. You need to do
some more manipulation to get <x_dummy|psi_ket> in terms of the
representations of x_op and x_ket themselves. If you do it you get
x_ket*DiracDelta(x_ket-x_dummy). You can look up the manipulation in a
quantum mechanics text. It involves inserting a resolution of unity
between x_op and x_ket and evaluating the integral over position,
which is trivial in this case because of the delta function.

> Comments are greatly appreciated! Thanks
>
> Tomo

Cheers,
Julien

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