Thanks David.
Regards
Sangram
On Tue, Aug 18, 2009 at 7:20 PM, David Bender <bda...@us.ibm.com> wrote:
>
> Python code uses the indentation to denote code blocks, and a tab character
> is not the same as 4 spaces (even though when you view the file in an editor
> they may appear equivalent).
>
> The recommendation is to always use spaces in your STAX jobs. Most
> text/xml editors have settings to allow you to use soft tabs (so when you
> press the Tab key it will emulate with spaces).
>
> Here is a link with some useful information about Python indentation:
>
> http://www.secnetix.de/olli/Python/block_indentation.hawk
>
> Thanks,
> David
>
> ------------------------------
> *David
> Bender*<http://w3.ibm.com/bluepages/simpleSearch.wss?searchBy=Name&searchFor=David+Bender>
> STAF/STAX Development
> IBM Software Group, WPLC
> 11501 Burnet Rd.
> Bldg. 903-5B002
> Austin, TX 78758-3400
> Phone (T/L): 1-512-286-5315 (363-5315)
> ITN: 23635315
> Email: *bda...@us.ibm.com* <bda...@us.ibm.com>
>
>
> ------------------------------
>
>
>
> *Sangram Bakshi <san...@gmail.com>*
>
> 08/18/2009 07:24 AM
> To
> staf-users@lists.sourceforge.net cc
> Subject
> Re: [staf-users] Staf Stax Python Code Indentation
>
>
>
>
>
> Hi ,
>
> I observe the code compiles with four spaces after a "if" or "for " , but
> it fails to compile if by mistake we give a "tab"(equivalent to four
> spaces). I am able to work fine , my code compiles fine.
>
>
> Do suggest any other tips for indentation.
>
>
> Regards
>
> On Tue, Aug 18, 2009 at 5:12 PM, Sangram Bakshi
> <*san...@gmail.com*<san...@gmail.com>>
> wrote:
> Hi ,
>
> I was coding python in staf stax job. I follow basic python indentation.
>
>
> For e.g:
>
> nodeList = document.getElementsByTagName("machine_name")
> x = nodeList.getLength()
> if nodeList.getLength():
> nodeList = document.getElementsByTagName("machine_name")
> for i in range(nodeList.getLength()):
> node = nodeList.item(i)
>
> I give four spaces after a if or for .
>
> The code compiles sometimes , it does'nt compiles sometimes if i disturb it
> it a little bit and gain maintain the space indentation.
>
> Any simple rule to follow while coding to keep proper indentation.
>
> I feel the env is very sensitive.
>
>
> For e.g:
>
> <script>
> machname = []
> vmware_value = []
> vmware_attr = []
> sangram = 'None'
>
> nodeList = document.getElementsByTagName("machine_name")
> x = nodeList.getLength()
> if nodeList.getLength():
> nodeList = document.getElementsByTagName("machine_name")
> for i in range(nodeList.getLength()):
> node = nodeList.item(i)
> if node.getNodeType() == Node.ELEMENT_NODE:
> children = node.getChildNodes()
> for j in range(children.getLength()):
> thisChild = children.item(j)
> if (thisChild.getNodeType() == Node.TEXT_NODE):
> machname.append( thisChild.getNodeValue())
>
> Till yellow highlighted it compiles fine : after that the following does
> not compiles.
>
> nodeList = document.getElementsByTagName("vmware")
> if nodeList.getLength():
> nodeList = document.getElementsByTagName("vmware")
> #for i in range(nodeList.getLength()):
> #node = nodeList.item(i)
> # id = ""
> # attrList = node.getAttributes()
> #for k in range(attrList.getLength()):
> # thisAttr = attrList.item(k)
> # if thisAttr.getNodeName() == "id":
> # id = thisAttr.getNodeValue()
> # vmware_attr.append(id)
> #if node.getNodeType() == Node.ELEMENT_NODE:
> # children = node.getChildNodes()
> #for j in range(children.getLength()):
> # thisChild = children.item(j)
> # if (thisChild.getNodeType() == Node.TEXT_NODE):
> # vmware_value.append(thisChild.getNodeValue())
>
> </script>
>
> Kinldy suggest a easy technique to follow indentation.
>
>
> Regards
> Sangram
>
>
>
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