Python code uses the indentation to denote code blocks, and a tab
character is not the same as 4 spaces (even though when you view the file
in an editor they may appear equivalent).
The recommendation is to always use spaces in your STAX jobs. Most
text/xml editors have settings to allow you to use soft tabs (so when you
press the Tab key it will emulate with spaces).
Here is a link with some useful information about Python indentation:
http://www.secnetix.de/olli/Python/block_indentation.hawk
Thanks,
David
David Bender
STAF/STAX Development
IBM Software Group, WPLC
11501 Burnet Rd.
Bldg. 903-5B002
Austin, TX 78758-3400
Phone (T/L): 1-512-286-5315 (363-5315)
ITN: 23635315
Email: bda...@us.ibm.com
Sangram Bakshi <san...@gmail.com>
08/18/2009 07:24 AM
To
staf-users@lists.sourceforge.net
cc
Subject
Re: [staf-users] Staf Stax Python Code Indentation
Hi ,
I observe the code compiles with four spaces after a "if" or "for " , but
it fails to compile if by mistake we give a "tab"(equivalent to four
spaces). I am able to work fine , my code compiles fine.
Do suggest any other tips for indentation.
Regards
On Tue, Aug 18, 2009 at 5:12 PM, Sangram Bakshi <san...@gmail.com> wrote:
Hi ,
I was coding python in staf stax job. I follow basic python indentation.
For e.g:
nodeList = document.getElementsByTagName("machine_name")
x = nodeList.getLength()
if nodeList.getLength():
nodeList = document.getElementsByTagName("machine_name")
for i in range(nodeList.getLength()):
node = nodeList.item(i)
I give four spaces after a if or for .
The code compiles sometimes , it does'nt compiles sometimes if i disturb
it it a little bit and gain maintain the space indentation.
Any simple rule to follow while coding to keep proper indentation.
I feel the env is very sensitive.
For e.g:
<script>
machname = []
vmware_value = []
vmware_attr = []
sangram = 'None'
nodeList = document.getElementsByTagName("machine_name")
x = nodeList.getLength()
if nodeList.getLength():
nodeList = document.getElementsByTagName("machine_name")
for i in range(nodeList.getLength()):
node = nodeList.item(i)
if node.getNodeType() == Node.ELEMENT_NODE:
children = node.getChildNodes()
for j in range(children.getLength()):
thisChild = children.item(j)
if (thisChild.getNodeType() == Node.TEXT_NODE):
machname.append( thisChild.getNodeValue())
Till yellow highlighted it compiles fine : after that the following does
not compiles.
nodeList = document.getElementsByTagName("vmware")
if nodeList.getLength():
nodeList = document.getElementsByTagName("vmware")
#for i in range(nodeList.getLength()):
#node = nodeList.item(i)
# id = ""
# attrList = node.getAttributes()
#for k in range(attrList.getLength()):
# thisAttr = attrList.item(k)
# if thisAttr.getNodeName() == "id":
# id = thisAttr.getNodeValue()
# vmware_attr.append(id)
#if node.getNodeType() == Node.ELEMENT_NODE:
# children = node.getChildNodes()
#for j in range(children.getLength()):
# thisChild = children.item(j)
# if (thisChild.getNodeType() == Node.TEXT_NODE):
# vmware_value.append(thisChild.getNodeValue())
</script>
Kinldy suggest a easy technique to follow indentation.
Regards
Sangram
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