Thanks for the reply, now i get it
On Thu, Aug 28, 2014 at 10:56 PM, Daniel-Constantin Mierla
<mico...@gmail.com> wrote:
> To give a better visual perspective, practically if you do:
>
>
> $sht(a=>$ci::srcip) = $si;
>
> for and INVITE request that comes from 1.2.3.4 and has the header:
>
> Call-Id: abcd
>
> Then in the the hash table a is added the pair ('abcd::srcip', '1.2.3.4').
>
> So, the pseudo variables (the $xy... tokens are evaluated).
>
> Cheers,
> Daniel
>
>
> On 28/08/14 17:35, Alex Balashov wrote:
>>
>> It's not an operator, actually. :-) It's just a convention. You can call
>> your keys anything you like (that's grammatically valid).
>>
>> On 08/28/2014 09:37 AM, aft wrote:
>>
>>> Hi,
>>>
>>> From kamailio documentation, the usage of hashtable is given as :
>>>
>>> modparam("htable", "htable", "a=>size=4;")
>>> ...
>>> $sht(a=>test) = 1;
>>> $sht(a=>$ci::srcip) = $si;
>>>
>>> I get it that in the first statement, a is the hashtable, a new
>>> key-value pair is added to one of its empty bucket (test,1).
>>>
>>> What is happening in the second statement?
>>>
>>>
>>>
>>
>>
>
> --
> Daniel-Constantin Mierla
> http://twitter.com/#!/miconda - http://www.linkedin.com/in/miconda
> Next Kamailio Advanced Trainings 2014 - http://www.asipto.com
> Sep 22-25, Berlin, Germany ::: Oct 15-17, San Francisco, USA
>
>
>
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--
-Cheers
-Arif
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