Antonin:
The query is http://tinyurl.com/yanppn5k and the possible result could be
this:
https://es.wikipedia.org/wiki/Anexo:Reservas_nacionales_de_Chile#Reservas_nacionales_de_Chile
(columns in es.wiki: photo, year of declaration, name, region, province,
area)
I want include an icon to Commons
I don't see why it would be impossible… Could you share your query and
give the wikicode you would like to generate for a sample row?
Antonin
On 16/04/2018 14:19, Dennis Tobar wrote:
> Antonin:
>
> Thanks for share your query. I want to create a row with name, year of
> creation, area protected
Antonin:
Thanks for share your query. I want to create a row with name, year of
creation, area protected (in hectare), a photo, the Commons category (if
exists) and the legal decree that creates the protected area, so I see that
seems impossible to do it with a few concats :)
I already have the q
Hi,
It is possible to use templates in Listeria table cells, by tweaking
your SPARQL query so that it returns the appropriate wikicode:
https://www.wikidata.org/wiki/User:Pintoch/orgid
If you have templates which depend on multiple variables in your SPARQL
query, I suppose you could take advanta
