Antonin: Thanks for share your query. I want to create a row with name, year of creation, area protected (in hectare), a photo, the Commons category (if exists) and the legal decree that creates the protected area, so I see that seems impossible to do it with a few concats :)
I already have the query and the data from Wikidata, so this isn't the key problem. On Mon, Apr 16, 2018 at 8:40 AM, Antonin Delpeuch (lists) < li...@antonin.delpeuch.eu> wrote: > Hi, > > It is possible to use templates in Listeria table cells, by tweaking > your SPARQL query so that it returns the appropriate wikicode: > > https://www.wikidata.org/wiki/User:Pintoch/orgid > > If you have templates which depend on multiple variables in your SPARQL > query, I suppose you could take advantage of the fact that the pipe > characters in wiki tables can also be used to separate template > arguments: you could generate parts of the template in various > consecutive SPARQL variables and they would all be rendered as one > template in a cell (but the headers would go out of sync). > > But that's a ugly hack - I would be interested in a cleaner way too. > > Antonin > > On 16/04/2018 13:30, Dennis Tobar wrote: > > Hi: > > > > I'm working on protected areas in Chile and I want to get the list using > > Listeriabot but in a "special format" using templates. I tried to find > > some example without luck. > > > > Does anyone know a working example of Listeriabot + template to render > > the rows?. > > > > Kindly, > > > > -- > > Dennis Tobar Calderón > > Ingeniero en Informática UTEM > > > > > > _______________________________________________ > > Wikidata mailing list > > Wikidata@lists.wikimedia.org > > https://lists.wikimedia.org/mailman/listinfo/wikidata > > > > > _______________________________________________ > Wikidata mailing list > Wikidata@lists.wikimedia.org > https://lists.wikimedia.org/mailman/listinfo/wikidata > -- Dennis Tobar Calderón Ingeniero en Informática UTEM
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