Hi,
i have a controller with this :
response.headers['Content-Disposition'] = 'inline; filename=%s' %
request.vars.filename
to force streaming the pdf file , and i do not why it does not work ..
any idea ?
Thank you
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentati
Hello,
i use sqlformgrid and like this :
controller:
def art_manage():
records= SQLFORM.grid(query=db.t_art,maxtextlength =
40,deletable=False,create=True, fields=[db.t_art.f_name, db.t_art.f_team,
db.t_art.f_tit])
return dict(records=records)
view:
{{=records}}
the records displayed
-abstraction-layer#callbacks-on-record-insert-delete-and-update
>
>
> Cheers
> Andrew
>
> ___
> *www.TenOutOfTen.org* <https://www.TenOutOfTen.org>
> roge...@gmail.com
> (+95) 09 250018669 <+95%209%20250%20018%20669> (Myanmar)
>
>
r FORM and SQLFORM. "
>
> So, when you declare the grid, you link the function that you want to run
> to: oncreate=myoncreate
>
> On Thursday, October 1, 2020 at 9:07:34 AM UTC-5 lcham...@gmail.com wrote:
>
>>
>> Hello,
>> i use sqlformgrid and like this :
>
> Cheers
> Andrew
>
> ___
> *www.TenOutOfTen.org* <https://www.TenOutOfTen.org>
> roge...@gmail.com
> (+95) 09 250018669 <+95%209%20250%20018%20669> (Myanmar)
>
>
>
> On Fri, 2 Oct 2020 at 00:07, lcham...@gmail.com
> wrote:
&
good idea it works , thank you
i have to practise more
Le jeudi 8 octobre 2020 à 16:05:39 UTC+2, Alex Beskopilny a écrit :
> maybe you could do this
>
> def art_manage():
>
> if len(request.args) >= 2 and ('new' == request.args[0]):
># some code
>return ' create !!!
Hello,
i don't know why , i can upload a pic from a form using ckeditor
/app/download/plugin_ckeditor_upload.upload.a7dc4103618b052d.57494e5f32303230313030315f31365f35325f31305f50726f2e6a7067.jpg
i submit the record is registered, , i visualise the view , the code source
is correct
and the p
Did you find a solution ?
thanks
Le dimanche 29 mars 2020 à 17:13:14 UTC+2, and...@gmail.com a écrit :
> I have this problem using web2py 2.18 with pyrhon 3.8 and mysql.
> When I log in int the app it happens this error:
> 255
>
> I don't know id it's an error regarding mysql
> Versione
> w
I moved an app/db to a new server. This apps connects perfectly, i am sure
the credentials are good, the auth method is mysql_native_password as
before.
I tried to change the drivers method .. i cannot connect, what ca i do, i
search in the forum, no response, thank you very much, i am in the .
forget it : solved using
python3 -m pip install PyMySQL
Sorry for disturbing
Le mercredi 4 novembre 2020 à 11:51:10 UTC+1, lcham...@gmail.com a écrit :
> I moved an app/db to a new server. This apps connects perfectly, i am sure
> the credentials are good, the auth met
*To Reproduce*
Steps to reproduce the behavior:
1. Create a new project(*New simple application*).
2. Go to Models, and edit *db.py*
Add this:
db.define_table('contacts', Field('first_name'), Field('last_name'),
Field('company_name'), Field('address'), Field('city'), Field('county'),
Hello ,
i have 2 tables like this :
Model
db.define_table('t_plasmids',
Field('f_protein', type='string', comment="50 characters max",
label=T('Protein')),
Field('f_plasmid_name', type='string', comment="100 characters max",
label=T('Plasmid Name')),
migrate = Tru
Sorry, i just start to move to py4web and if i follow the doc but :
if you create an application from scaffold, well, you have a set of files
and you have to write your functions in controllers.py, but you don't know
why. If you try to create (as in web2py) a toto.py, well, py4web never
finds
I've just come from web2py and I find the py4web doc very incomplete, even
for trivial things like:
if you create an application from scaffold, well, you have a set of files
and you have to write your functions in controllers.py, but you don't know
why. If you try to create (as in web2py) a t
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