Re: "IPython is available, use IPython for PySparkInterpreter"

2018-03-20 Thread Felix Cheung
I think that's a good point - perhaps this shouldn't be a warning. From: Ruslan Dautkhanov Sent: Monday, March 19, 2018 11:10:48 AM To: users Subject: "IPython is available, use IPython for PySparkInterpreter" We're getting " IPy

Re: "IPython is available, use IPython for PySparkInterpreter"

2018-03-19 Thread andreas . weise
I already filed an issue: Checkout https://issues.apache.org/jira/browse/ZEPPELIN-3290 Jeff Zhang wanted to wait for other users feedback there. On 2018/03/19 18:10:48, Ruslan Dautkhanov wrote: > We're getting " IPython is available, use IPython for PySparkInterpreter " >

"IPython is available, use IPython for PySparkInterpreter"

2018-03-19 Thread Ruslan Dautkhanov
We're getting " IPython is available, use IPython for PySparkInterpreter " warning each time we start %pyspark notebooks. Although there is no difference between %pyspark and %ipyspark afaik. At least we can use all ipython magic commands etc. (maybe becase we have zeppelin.pys

Re: IPython is available, use IPython for PySparkInterpreter

2017-12-11 Thread Ruslan Dautkhanov
python interpreter become much more mature. > > > > > Ruslan Dautkhanov 于2017年12月11日周一 下午1:20写道: > >> Getting "IPython is available, use IPython for PySparkInterpreter" >> warning after starting pyspark interpreter. >

Re: IPython is available, use IPython for PySparkInterpreter

2017-12-10 Thread Jeff Zhang
it is available, otherwise still use the old python interpreter implementation. I will change ipython as default and the original python implementation as fallback when ipython interpreter become much more mature. Ruslan Dautkhanov 于2017年12月11日周一 下午1:20写道: > Getting "IPython is available, us

IPython is available, use IPython for PySparkInterpreter

2017-12-10 Thread Ruslan Dautkhanov
Getting "IPython is available, use IPython for PySparkInterpreter" warning after starting pyspark interpreter. How do I default %pyspark to ipython? Tried to change to "class": "org.apache.zeppelin.spark.PySparkInterpreter", to "class": "org.a