Getting "IPython is available, use IPython for PySparkInterpreter" warning after starting pyspark interpreter.
How do I default %pyspark to ipython? Tried to change to "class": "org.apache.zeppelin.spark.PySparkInterpreter", to "class": "org.apache.zeppelin.spark.IPySparkInterpreter", in interpreter.json but this gets overwritten back to PySparkInterpreter. Also tried to change to zeppelin.pyspark.python to ipython with no luck too. Is there is a documented way to default pyspark interpreter to ipython? Glanced over PR-2474 but can't quickly get what I am missing. Thanks.
