The issue has been reported before:
http://jira.codehaus.org/browse/CHEN-53
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On Mon, May 14, 2012 at 7:41 PM, Norman Franke wrote:
> I don't think the OnEvent mixin is compatible, at lest it wasn't for me.
It could.
Please file an issue in the jira (the chenillekit one not tapestry
one) with a test case, thanks
Cheers
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Massimo
http://meridio.blogspot.com
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Hi there --
We are using 4.1.7-SNAPSHOT because it has some fixes from the last
official build 4.1.6. Using the snapshots have been fine for a while.
Unfortunately the last few months have new 4.1.7-SNAPSHOT builds being
deployed with no changes. It looks like some sort of automated build
process
Rather writing out your own disabled attribute, try having your Mixin
bind to the disabled parameter:
@BindParameter
private boolean disabled;
then set this to false and have the input component disable itself:
void beginRender() {
disabled = true;
}
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Steve Eynon
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Yes,I believe if we use the tapestry's existing event processing chain,we
will get the rendered html we want.
The question is:in the back of tapestry's existing event processing
chain,tapestry use PageRenderQueue(or something else) and RenderCommand to
render blocks/zones/components. So , why don't
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Hey, that's a great idea - thanks!
Am 14.05.2012 18:04, schrieb Norman Franke:
> I generally give the object I want to find a unique CSS class, and
> find it via prototype: $$('form.fooBar')[0]
>
> Norman Franke Answering Service for Directors, Inc.
Hi Alexander
I think the problem come from the fact that the input element of the
datefield is closed (writer.end()) in the beginRender phase. So when your
mixin is executed, it is too late.
You should maybe test if the field using the mixin is a Datefield, and if
this the case, get the Input Ele
I don't think the OnEvent mixin is compatible, at lest it wasn't for me.
Norman Franke
Answering Service for Directors, Inc.
www.myasd.com
On May 14, 2012, at 11:58 AM, Massimo Lusetti wrote:
> On Mon, May 14, 2012 at 4:47 PM, Nicolas Barrera wrote:
>
>> Hi all...,
>>
>> does somebody knows
I generally give the object I want to find a unique CSS class, and find it via
prototype: $$('form.fooBar')[0]
Norman Franke
Answering Service for Directors, Inc.
www.myasd.com
On May 12, 2012, at 3:46 PM, Bryan Lewis wrote:
> We dealt with this issue by writing a javascript function to find
On Mon, May 14, 2012 at 4:47 PM, Nicolas Barrera wrote:
> Hi all...,
>
> does somebody knows if chenille kit project is compatible with T 5.3?
>
> I was thinking to add this library to a T5.3 project and I wondered if
> this was possible.
>
> cheers and thanks in advance.
I released 1.3.3 which
Hi all...,
does somebody knows if chenille kit project is compatible with T 5.3?
I was thinking to add this library to a T5.3 project and I wondered if
this was possible.
cheers and thanks in advance.
Nicolás.-
Another option is call ComponentRequestHandler instead of
HttpServletRequestHandler which might be easier to pass an event context.
You will need to store a fake request and response in the RequestGlobals if
you want to use the ComponentRequestHandler but the request URL will not be
important.
htt
Unfortunately I think howard's right in that you will need a fake request and
response. It's perfectly legal for a component to @Inject Request or @Inject
Response so you will need these.
It's probably easiest to take a very simple ajax zone update and try to fake
it from a non-web thread.
As an
Thank you for your encouragement.I will post my code when i finished . ^_^
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Okay... Thank you so much for your patience and worthy replies...
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I think it might be a problem with "Ids=10025033/10025032"
Take a look http://tomcat.apache.org/tomcat-7.0-doc/config/systemprops.html
here for "org.apache.tomcat.util.http.ServerCookie.FWD_SLASH_IS_SEPARATOR"
and "org.apache.catalina.STRICT_SERVLET_COMPLIANCE"
Any further questions, I think yo
How about just render a block(or zone,component,etc) in a non-web-thead ?
Think about this:no event on the component will be execute,the
non-web-thread just prepare PageRenderQueue (or something else,I'm not
sure),RenderCommand and render the html of the block.and then,the
non-web-thread push the
I just copied and pasted it from firebox browser show cookies section where
it displays name, value etc.,
The following is taken from request headers using firebug
isUserLogin=True; userId=2058; smsAvail=30; position=2;
Ids=10025033/10025032
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> and the other cookies are
> Cfp 1
> JEB2 4FB0E5C76E651
> i00 75474fb0eb0ee
Cookies should be of the form "key2=value1; key2=value2". How are you
writing these cookies?
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> Have you given me the entire cookie value? This does not include the
"isUserLogin" value you were initially talking about
"isUserLogin" is get written in cookies, when user logged in, I have given
you the another module cookie value
and the other cookies are
Cfp 1
JEB2 4FB0E5C76E651
i00 75474f
> Thank you for your reply...
No problem
> This is what I have in my request headers (Taken using firebug)
> Cookie BigIP_Colcms=271399690.0.
Have you given me the entire cookie value? This does not include the
"isUserLogin" value you were initially talking about.
> Is there any way to avoid
Thank you for your reply...
This is what I have in my request headers (Taken using firebug)
Cookie BigIP_Colcms=271399690.0.
Is there any way to avoid this log being written in the log file?
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Hi Lance,
Thanks for the pointer, works great, thank you very much
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> Thank you ! That's a way to solve my problem...
No problem, if you could share your code I would be interested to see your
solution since I'm doing something similar myself
> By the way,where are you from?
I'm australian but live in London, UK
> I am from china, and it's difficult to communicat
This error is being logged by Tomcat, not Tapestry
(http://www.docjar.com/html/api/org/apache/tomcat/util/http/Cookies.java.html).
Can you inspect the HTTP headers (using firebug etc) and see what the value
of the entire cookie is?
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Anyone?
Is this needs any server side settings changes or any tapestry changes?
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Thank you ! That's a way to solve my problem...
By the way,where are you from ?I am from china,and it's difficult to
communicate width each other for my poor English.
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public void onExpandAll() {
TreeExpansionModel expansionModel = tree.getExpansionModel();
List roots = getTreeModel().getRootnodes();
for (TreeNode root : roots) {
expandAll(root);
}
}
private void expandAll(TreeNode node) {
if (node.getHasChildren()) {
expansionModel.ma
I just recently asked the same question on the list
http://tapestry.1045711.n5.nabble.com/tapestry-push-proof-of-concept-td5697644.html
here
The steps to do it are:
1. In the intital tapestry page request, use ComponentResources to generate
a Link to a component event (most likely without the co
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