On Tuesday 02 May 2006 14:59, Dan wrote:
> Is:
>
> A && (B || C || D || E || F)
>
> equivalent to?:
>
> A && (!B && !C && !D && !E && !F)
>
I believe that's a fundamental logic rule, so yes.
A && B == ~A || ~B
--Russell
> as in:
>
> meta __FORGED_OUTLOOK_DOLLARS (__OUTLOOK_DOLLARS_MUA && !
> __O
if I
could check that.
--Russell
--
Russell Miller - [EMAIL PROTECTED] - Agoura Hills, CA
deal with *their* spam problem - that you're apparently (if unwittingly)
helping to cause.
University networks are pretty well known to be swiss cheese as far as
security goes. Yours is probably no exception. Fix that problem and your
spam problem should be fixed along with it.
--Russell
--
Russell Miller - [EMAIL PROTECTED] - Agoura Hills, CA
