Hi Everyone.
Kindly reply in "yes" or "no", as to whether it is possible to setup
encryption only between particular pair of nodes?
Or is it an "all" or "none" feature, where encryption is present between
EVERY PAIR of nodes, or in NO PAIR of nodes.
Thanks and Regards,
Ajay
On Mon, Apr 18, 2016
Also, wondering what is the difference between "all" and "dc" in
"internode_encryption".
Perhaps my answer lies in this?
On Mon, Apr 18, 2016 at 9:51 AM, Ajay Garg wrote:
> Ok, trying to wake up this thread again.
>
> I went through the following links ::
>
>
> https://docs.datastax.com/en/cassa
Ok, trying to wake up this thread again.
I went through the following links ::
https://docs.datastax.com/en/cassandra/1.2/cassandra/security/secureSSLNodeToNode_t.html
https://docs.datastax.com/en/cassandra/1.2/cassandra/security/secureSSLCertificates_t.html
and I am wondering *if it is possibl
Hi All.
A gentle query-reminder.
I will be grateful if I could be given a brief technical overview, as to
how secure-communication occurs between two nodes in a cluster.
Please note that I wish for some information on the "how it works below the
hood", and NOT "how to set it up".
Thanks and R
Thanks everyone for the reply.
I actually have a fair bit of questions, but it will be nice if someone
could please tell me the flow (implementation-wise), as to how node-to-node
encryption works in a cluster.
Let's say node1 from DC1, wishes to talk securely to node 2 from DC2
(with *"require_cl
Hi Ajay,
Have a look here :
https://docs.datastax.com/en/cassandra/1.2/cassandra/security/secureSSLNodeToNode_t.html
You can configure for DC level Security:
Procedure
On each node under sever_encryption_options:
- Enable internode_encryption.
The available options are:
- all
Security is a very wide concept. What exactly do you want to achieve ?
From: Ajay Garg [mailto:ajaygargn...@gmail.com]
Sent: Wednesday, January 06, 2016 11:27 AM
To: user@cassandra.apache.org
Subject: Basic query in setting up secure inter-dc cluster
Hi All.
We have a 2*2 cluster deployed, but no
