On Dec 5, 5:31 am, Dan Drake wrote:
> I keep wondering whether Sage is making a mistake, or I'm not
> understanding complex analysis. I'm a little afraid to learn the answer.
> :)
>
> Take f(z) = (z-I)*(z-1)^2/(z-(-1/2-I/3)). It's analytic everywhere
> except at -1/2-I/3, where it has a simple p
I'm doing my masters at the moment and I plan on running sage quite a bit
for now, both via the VM and a local linux install. I can try one image a
month for you guys (The cap is a bit of an issue), and I'll try break each
distro during my coffee breaks :P May be it'd help to setup a page on what
t
On Dec 5, 9:14 am, Carel van Dam wrote:
> I'm doing my masters at the moment and I plan on running sage quite a bit
> for now, both via the VM and a local linux install. I can try one image a
> month for you guys (The cap is a bit of an issue), and I'll try break each
> distro during my coffee bre
Hello!
I am trying to use unicode characters in axes labels and it fails with
exception:
P = plot_step_function([(i,prime_pi(i)) for i in
range(20)],thickness=2,color='black')
P.show(axes=False,frame=True,axes_labels=('текс','x'))
Traceback (most recent call last):
File "", line 1, in
Fil
On Dec 5, 10:04 am, achrzesz wrote:
> On Dec 5, 5:31 am, Dan Drake wrote:
>
>
>
> > I keep wondering whether Sage is making a mistake, or I'm not
> > understanding complex analysis. I'm a little afraid to learn the answer.
> > :)
>
> > Take f(z) = (z-I)*(z-1)^2/(z-(-1/2-I/3)). It's analytic eve
If I have a boolean expression of a certain number of variables, how
do I define a polynomial ring with them.. For example, let
(x0,x1,x2,x3,x4,x5,x6,x7) be a set of variables, and I have an
expression S = x0 + x1*x3 + x7
I need to define the polynomial ring
R.=BooleanPolynomialRing(4)
This exer
R=BooleanPolynomialRing(100,['x'+str(i) for i in [1..100]])
R.inject_variables()# if you don't really need the identifiers in
Python's namespace, better skip this
On Dec 5, 6:18 am, Subhadeep Banik wrote:
> If I have a boolean expression of a certain number of variables, how
> do I define a
So it sounds like you should file a ticket, Dan. Maybe we're just
sending it to Maxima wrong.
(%i9) f(z):=(z-%i)*(z-1)^2/(z-(-1/2-%i/3));
2
(z - %i) (z - 1)
(%o9) f(z) := -
On Dec 5, 3:18 pm, Subhadeep Banik wrote:
> If I have a boolean expression of a certain number of variables, how
> do I define a polynomial ring with them.. For example, let
> (x0,x1,x2,x3,x4,x5,x6,x7) be a set of variables, and I have an
> expression S = x0 + x1*x3 + x7
> I need to define the
Hi
sagenb doesn't seem to be working. A student of mine is about to
defenestrate herself (her words) because it's not working.
If this is expected downtime; my apologies -- she wasn't supposed to
be using sagenb in the first place, but that's life. :-)
regards
john perry
--
To post to this gro
test.sagenb.org seems to be up, so if she has a saved local copy of a
worksheet, she could use that..
Doug
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On Dec 5, 2011 9:47 AM, "john_perry_usm" wrote:
>
> Hi
>
> sagenb doesn't seem to be working. A student of mine is about to
> defenestrate herself (her words) because it's not working.
>
> If this is expected downtime; my apologies -- she wasn't supposed to
> be using sagenb in the first place, bu
Hi, all,
I'm new here and new-ish to sage and I was hoping you could help me
with a rather complicated problem. My professor gave me this
inequality:
0 < (2*n*(i+j+k))/(-k*n+j*(n-s)+i*s) < 1
and he wants me to see if I can find solutions within the following
constraints: 0 < s < n, i,j,k integer
On 12/5/11 11:54 AM, William Stein wrote:
On Dec 5, 2011 9:47 AM, "john_perry_usm" mailto:john.pe...@usm.edu>> wrote:
>
> Hi
>
> sagenb doesn't seem to be working. A student of mine is about to
> defenestrate herself (her words) because it's not working.
>
> If this is expected downtime;
I don't think maxima does polyhedral computations in its assume facility,
so you probably get the wrong answer.
We do, however, have quite a lot of tools for polyhedral computations:
sage: P = Polyhedron(ieqs=[(1,2), (10,-7)])
sage: P
A 1-dimensional polyhedron in QQ^1 defined as the convex hull
On Dec 5, 11:54 am, William Stein wrote:
> On Dec 5, 2011 9:47 AM, "john_perry_usm" wrote:
>
> > sagenb doesn't seem to be working. A student of mine is about to
> > defenestrate herself (her words) because it's not working.
>
> ...
>
> I have just initiated restarting the server.
Our windows th
On 12/5/11 11:47 AM, john_perry_usm wrote:
defenestrate herself (her words)
For the curious: http://en.wikipedia.org/wiki/Defenestration
Defenestration is the act of throwing someone or something out of a
window.[1] The term "defenestration" was coined around the time of an
incident in Pragu
On Sat, Nov 26, 2011 at 10:12 PM, pong wrote:
>
> Thanks for the tips, but I would like to have "live" 3D-plots (ones
> that one can spin and drag around).
In theory, doing this (written by Bill Cauchois) should work, but it
doesn't work on Android:
I = icosahedron()
I.show(viewer='canvas3
On Dec 5, 4:56 pm, kcrisman wrote:
> So it sounds like you should file a ticket, Dan. Maybe we're just
> sending it to Maxima wrong.
>
> (%i9) f(z):=(z-%i)*(z-1)^2/(z-(-1/2-%i/3));
> 2
> (z - %i) (z - 1)
> (%o
That would explain why it wasn't working. I've never done polyhedral
computations before, but I will look at your example and the reference
manual and see what I can do!
Thank you!
On Dec 5, 1:45 pm, Volker Braun wrote:
> I don't think maxima does polyhedral computations in its assume facility,
Here is a first implementation of the cup product. I hope (of course) that
the code is correct, but it is certainly not very idomatic. Any suggestions
for improvement are welcome!
def cup_product(X,c1,dim1,c2,dim2):
d = dim1 + dim2
faces1 = list(X.n_faces(dim1))
faces2 = list(X.n_fa
Hi
I am trying to set up sage using vitualbox. What base memory should I
set in virtualbox for the sage ? While setting up, I assigned 1024 MB
base memory. Later the Virtualbox keeps reminding me that base memory
is more than 50 % of total memory (1.74 GB) and there might be
problems.
I also don't
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