On Thu, Nov 13, 2008 at 4:06 PM, Burcin Erocal <[EMAIL PROTECTED]> wrote:
>
> On Thu, 13 Nov 2008 12:32:54 +0100
> "Ondrej Certik" <[EMAIL PROTECTED]> wrote:
>
>>
>> On Thu, Nov 13, 2008 at 10:31 AM, Burcin Erocal <[EMAIL PROTECTED]>
>> wrote:
>> >
>
>> > We will have a completely new implementat
Burcin Erocal wrote:
> On Thu, 13 Nov 2008 04:09:56 -0600
> Jason Grout <[EMAIL PROTECTED]> wrote:
>
>> Burcin Erocal wrote:
>>
>>>
>>> Returning to the question of how Sage plans to handle this, the
>>> short answer is "I am working on it." :)
>>>
>> Yeah!
>>
>>
>>> We will have a completely ne
On Thu, 13 Nov 2008 12:32:54 +0100
"Ondrej Certik" <[EMAIL PROTECTED]> wrote:
>
> On Thu, Nov 13, 2008 at 10:31 AM, Burcin Erocal <[EMAIL PROTECTED]>
> wrote:
> >
> > We will have a completely new implementation of summation,
> > independent of the one in Maxima. At the moment I have an
> > imp
On Thu, 13 Nov 2008 04:09:56 -0600
Jason Grout <[EMAIL PROTECTED]> wrote:
>
> Burcin Erocal wrote:
>
> >
> >
> > Returning to the question of how Sage plans to handle this, the
> > short answer is "I am working on it." :)
> >
>
> Yeah!
>
>
> > We will have a completely new implementation
On Thu, Nov 13, 2008 at 10:31 AM, Burcin Erocal <[EMAIL PROTECTED]> wrote:
>
> On Mon, 10 Nov 2008 17:36:46 -0800 (PST)
> cesarnda <[EMAIL PROTECTED]> wrote:
>
>>
>> Actually this sum can't be done by Maxima, but Derive can do it (even
>> an old version of derive). do you have an idea of how this
Burcin Erocal wrote:
>
>
> Returning to the question of how Sage plans to handle this, the short
> answer is "I am working on it." :)
>
Yeah!
> We will have a completely new implementation of summation, independent
> of the one in Maxima. At the moment I have an implementation of the
> the
On Mon, 10 Nov 2008 17:36:46 -0800 (PST)
cesarnda <[EMAIL PROTECTED]> wrote:
>
> Actually this sum can't be done by Maxima, but Derive can do it (even
> an old version of derive). do you have an idea of how this problem is
> planning to be solved?
As Robert Dodier pointed out, Maxima can actual
On Nov 10, 7:15 pm, cesarnda <[EMAIL PROTECTED]> wrote:
> that is the output I was expecting, but it is not the input I gave.
> Obviously,
> 1/x - 1/(x+1) = 1/(x*(x+1))
>
> but, if the right hand side can be done why the left hand side can't?
> This is the bug I was talking about...
Thanks for p
On Tue, Nov 11, 2008 at 3:15 AM, cesarnda <[EMAIL PROTECTED]> wrote:
>
> that is the output I was expecting, but it is not the input I gave.
> Obviously,
> 1/x - 1/(x+1) = 1/(x*(x+1))
>
> but, if the right hand side can be done why the left hand side can't?
> This is the bug I was talking about...
that is the output I was expecting, but it is not the input I gave.
Obviously,
1/x - 1/(x+1) = 1/(x*(x+1))
but, if the right hand side can be done why the left hand side can't?
This is the bug I was talking about...
On 10 nov, 19:51, "Mike Hansen" <[EMAIL PROTECTED]> wrote:
> On Mon, Nov 10, 200
On Mon, Nov 10, 2008 at 5:36 PM, cesarnda <[EMAIL PROTECTED]> wrote:
>
> Actually this sum can't be done by Maxima, but Derive can do it (even
> an old version of derive). do you have an idea of how this problem is
> planning to be solved?
Is this the answer you were expecting?
(%i6) load(simpli
Actually this sum can't be done by Maxima, but Derive can do it (even
an old version of derive). do you have an idea of how this problem is
planning to be solved?
On 10 nov, 19:30, "William Stein" <[EMAIL PROTECTED]> wrote:
> On Mon, Nov 10, 2008 at 5:29 PM, cesarnda <[EMAIL PROTECTED]> wrote:
>
On Mon, Nov 10, 2008 at 5:29 PM, cesarnda <[EMAIL PROTECTED]> wrote:
>
> how could I compute this:
>
> sum_{ x = 1}^{\infty} 1/x - 1/(x+1)
>
> or
>
> sum(1/x-1/(x+1),x,1, infinity)
>
> directly in Sage, without calling maxima or sympy?
Unfortunately, this isn't implemented yet. See:
http://trac.
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