On Tue, Nov 11, 2008 at 3:15 AM, cesarnda <[EMAIL PROTECTED]> wrote: > > that is the output I was expecting, but it is not the input I gave. > Obviously, > 1/x - 1/(x+1) = 1/(x*(x+1)) > > but, if the right hand side can be done why the left hand side can't? > This is the bug I was talking about...
It probably depends on the algorithm, in sympy, it's currently the other way round: In [2]: sum(1/x - 1/(x+1), (x, 1, oo)) Out[2]: 1 In [3]: sum(1/(x*(x+1)), (x, 1, oo)) Out[3]: Sum(1/(x*(1 + x)), (x, 1, oo)) Ondrej --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
