In 6.2, %display seems restricted to ('simple', 'ascii_art'). From a
terminal :
sage: %display typeset
---
ValueErrorTraceback (most recent call last)
in ()
> 1 get_ipython().magic(u'displ
On 2014-05-14, Volker Braun wrote:
> Instead of projecting (which requires some convention about bases to be
> able to work with coordinates) I would try to use the Minkowski sum with
> the linear space in the direction that you want to unconstrain.
IMHO, Jeroen needs to use Fourier-Motzkin eli
On 2014-05-14, Ailurus wrote:
> By "nontrivial way", do you mean the cosine or the square root (or both)?
I didn't actually notice sqrt.
Such equations are in fact not called quadratic, that was confusing.
Your original equations also contained i, which is, I presume,
sqrt(-1)?
> And yes, I cou
Instead of projecting (which requires some convention about bases to be
able to work with coordinates) I would try to use the Minkowski sum with
the linear space in the direction that you want to unconstrain.
E.g. the diagonal in the unit square:
sage: P = Polyhedron([(0,0), (1,1)])
Say you wa
Dear sage-support,
I am working with polyhedra, defined by equalities and inequalities
(H-representation). Those equations involve some variables I want to
eliminate, I want to project on the remaining variables.
I am wondering if there is an interface in Sage for projecting a
polyhedron on
On Wednesday, May 14, 2014 12:57:50 PM UTC-4, Fred Gruber wrote:
>
> Hi
> Since other people may use the notebook I would prefer if they didn't have
> to manually copy the URL.
>
> I noticed that the javascript variable "document.URL" have this
> information but I'm not sure how to bring the v
On Monday, May 12, 2014 4:52:42 PM UTC-4, Dima Pasechnik wrote:
>
> On 2014-05-12, J.A. Ketch > wrote:
> > thank you all for the answers
> > the version of my sage is : Sage Version 6.1.1, Release Date:
> 2014-02-04,
> > so I can not use hg. Some sites for the development refers to hg and not
Hi
Since other people may use the notebook I would prefer if they didn't have
to manually copy the URL.
I noticed that the javascript variable "document.URL" have this information
but I'm not sure how to bring the value back to python.
I tried the following in a cell but the webpage changes to
Hi
Since other people my use the notebook I would prefer if they didn' have to
manually copy the URL.
I notices that the javascript variable "document.URL)" have this
information but I'm not sure how the bring the value to python.
I tried the following in a cell but the page changes to another
By "nontrivial way", do you mean the cosine or the square root (or both)?
And yes, I could eliminate b and then solve for a, but that's a manual step
I'd rather avoid.
Ok, so I simplified the expressions using Sage (I'm quite surprised to see
that simplify_full() produces better results than M
On Wed, May 14, 2014 at 1:52 AM, wrote:
> Dear John
> I recently became acquainted with the software and its capabilities. I like
> to every value p, the two subspace subscribe to my account. Grateful for
> your guidance.
>
>
This is a problem in matrix theory which can be solved using row-red
On Wed, May 14, 2014 at 1:25 AM, nas mer wrote:
> Hi
> Thank you
> I attach the program of intersection in sage.
> please, look at the attach file.
See attached.
> Best regard
This is an elementary problem in matrix theory. Is this homework for a class?
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On 2014-05-14, Ailurus wrote:
> Hi all,
>
> I'm trying to solve the following system of two equations,
>
> Eq1 = 2*a^2*cos(pi/n)^2 - 2*a - b - (a*sin((2*pi)/n)*(-2*(cos((2*pi)/n) -
> sin((2*pi)/n)*i)*(a^2*cos((2*pi)/n) - 4*a - 2*b + a^2 + 2))^(1/2))/2 +
> 2^(1/2)*a*cos(pi/n)^2*(-(cos((2*pi)/n) -
Hi all,
I'm trying to solve the following system of two equations,
Eq1 = 2*a^2*cos(pi/n)^2 - 2*a - b - (a*sin((2*pi)/n)*(-2*(cos((2*pi)/n) -
sin((2*pi)/n)*i)*(a^2*cos((2*pi)/n) - 4*a - 2*b + a^2 + 2))^(1/2))/2 +
2^(1/2)*a*cos(pi/n)^2*(-(cos((2*pi)/n) -
sin((2*pi)/n)*i)*(a^2*cos((2*pi)/n) - 4*a
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