Jan Groenewald writes:
> Problem was interface="eth1".
> It works with interface="196.21.91.202"
>
> I found this documentation misleading, as if we are moving from
> addresses
> to interfaces names, from sage: notebook? which is why I put "eth1"
> in the first place; but a re-read led me to try t
I am using firefox 13.0.1 with sage 5.1 and have exactly the same problem
On Sunday, 8 May 2011 19:06:00 UTC+12, Keshav Kini wrote:
>
> This was discussed on the IRC channel yesterday. Harmor was using Firefox
> 4, and when he tried it with Chromium it worked, apparently. I also thought
> it s
# This command works for me:
polygon([(0,0), (2,1), (0,3)], alpha=0.5, axes_labels=['x','y'])
On Monday, July 16, 2012 8:27:25 PM UTC+2, The Doctor (Michael) wrote:
>
> Thanks a lot. On my figure number (2) above:
>
> And for figure 2, I used polygon():
>
> figure2 = polygon([(0,0), (2,1), (0,3
#You probably need the right-hand sem-iring:
l1=[(3*cos(phi),3*sin(phi)) for phi in srange(-n(pi)/2,n(pi)/2,0.01)]
l2=[(6*cos(phi),6*sin(phi)) for phi in srange(-n(pi)/2,n(pi)/2,0.01)]
l2.reverse()
figure4=polygon(l1+l2)
figure4.show(xmin=-6,xmax=6)
>
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l1=[(3*cos(phi),3*sin(phi)) for phi in srange(n(pi)/2,3*n(pi)/2,0.01)]
l2=[(6*cos(phi),6*sin(phi)) for phi in srange(n(pi)/2,3*n(pi)/2,0.01)]
l2.reverse()
figure4=polygon(l1+l2)
figure4.show(xmin=-6,xmax=6)
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On 7/16/12 1:43 PM, The Doctor (Michael) wrote:
l1=[(3*cos(phi),3*sin(phi)) for phi in srange(3*n(pi)/2,n(pi)/2,0.01)]
l2=[(6*cos(phi),6*sin(phi)) for phi in srange(3*n(pi)/2,n(pi)/2,0.01)]
l2.reverse()
If I do
print l1+l2
here, I see your list is empty. Perhaps your sranges are empty?
Jaso
One additional thing:
i need to plot a circular region between 2 circles of radius 3 and 6, with
3*pi/2 to pi/2 and I have tried the following code but keep getting an
Assertion error:
l1=[(3*cos(phi),3*sin(phi)) for phi in srange(3*n(pi)/2,n(pi)/2,0.01)]
l2=[(6*cos(phi),6*sin(phi)) for phi in
Thanks a lot. On my figure number (2) above:
And for figure 2, I used polygon():
figure2 = polygon([(0,0), (2,1), (0,3)], alpha=0.5)
I have tried adding axes with:axes_label=['x','y'], but sage ignores
that request and prints the graph without any axes. How can I fix that?
Thanks again,
l1=[(cos(phi),sin(phi)) for phi in srange(n(pi)/4,3*n(pi)/4,0.01)]
l2=[(2*cos(phi),2*sin(phi)) for phi in srange(n(pi)/4,3*n(pi)/4,0.01)]
l2.reverse()
p=polygon(l1+l2)
c1=circle((0,0), 1,rgbcolor=(0,0,0))
c2=circle((0,0), 2,rgbcolor=(0,0,0))
l0=line([(-2*cos(n(pi)/4),2*sin(n(pi)/4)),(0,0),(2*cos(n(
Thanks that is what I was looking or; with just one more thing.What would
be the simplest way to add the circles of radius 1 and 2, and the lines
theta = pi/4 and theta = 3*pi/4? Thanks again.
On Sunday, July 8, 2012 10:44:31 AM UTC-4, The Doctor (Michael) wrote:
>
> Hullo.
>
> I am new to Sage,
Hi Carlos
On 12 July 2012 14:38, Carlos Baptista wrote:
> A google search led me to:
>
> http://wiki.sagemath.org/sage_matlab
>
> Here they describe how you can get the Matplotlib GUI to work. They
> however use a Tk backend and as I am on Kubuntu I do not prefer to use
> Tk/GTK/GTK+ packages. P
Hi
On 12 July 2012 18:37, Jan Groenewald wrote:
> Hi
>
> On 12 July 2012 18:32, Jason Grout wrote:
>
>> On 7/12/12 9:33 AM, Jan Groenewald wrote:
>>
>>> Can anyone help with this?
>>> (It is a sage 5.1 compiled from source on Ubuntu 12.04)
>>>
>>> sage: notebook(interface="eth1", port=8080, sec
Well, complex spline interpolation does not fit my needs as I am looking
for interpolation by a function of type
(a_8*x^8+a_7*x^7+a_6*x^6+a_5*x^5+a_4*x^4+a_3*x^3+a_2*x^2+a_1*x^1+a_0)/(b_8*x^8+b_7*x^7+b_6*x^6+b_5*x^5+b_4*x^4+b_3*x^3+b_2*x^2+b_1*x^1+b_0).or
(a_7*x^7+a_6*x^6+a_5*x^5+a_4*x^4+a_3*x^3+a_
On Monday, July 16, 2012 5:08:34 AM UTC-4, Urs Hackstein wrote:
>
> Ok. I overlooked it. Thus is there an alternative to interpolate points
> (x_1k,x_2k)\in\mathbb{C}x\mathbb{C} by a function f:\mathbb{C}\to\mathbb{C}?
>
>
I don't know whether
http://www.sagemath.org/doc/reference/sage/calculus
Ok. I overlooked it. Thus is there an alternative to interpolate points
(x_1k,x_2k)\in\mathbb{C}x\mathbb{C} by a function f:\mathbb{C}\to\mathbb{C}?
2012/7/13 Pablo Fernandez
> > Dear Pablo Fernandez,
> >
> > thanks a lot for your suggestion. Unfortunately, it does not work in my
> case
> > and
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