Ok. I overlooked it. Thus is there an alternative to interpolate points
(x_1k,x_2k)\in\mathbb{C}x\mathbb{C} by a function f:\mathbb{C}\to\mathbb{C}?

2012/7/13 Pablo Fernandez <pablo.f...@gmail.com>

> > Dear Pablo Fernandez,
> >
> > thanks a lot for your suggestion. Unfortunately, it does not work in my
> case
> > and the error sounds a bit strange to me. As you suggested, I tried
> > xx=[0.5*I, 1*I,
> >
> 5*I,10*I,50*I,100*I,500*I,1000*I,5000*I,10000*I,5*10^4*I,10^5*I,5*10^5*I,10^6*I,5*10^6*I,10^7*I,5*10^7*I,10^8*I]
> > yy=[f_1,f_2,
> > f_3,f_4,f_5,f_6,f_7,f_8,f_9,f_10,f_11,f_12,f_13,f_14,f_15,f_16,f_17,f_18]
> > points = zip(xx, yy)
> > model(x) = (a_8*x^8 + a_7*x^7+ a_6*x^6 + a_5*x^5 + a_4*x^4 + a_3*x^3
> > +a_2*x^2 + a_1*x + a_0) / (b_8*x^8 + b_7*x^7 + b_6*x^6 + b_5*x^5
> +b_4*x^4 +
> > b_3*x^3 + b_2*x^2 + b_1*x + b_0)
> >
> > fit = find_fit(points, model, solution_dict=True)
> >
> > but received the following error
> >
> ...
> >
> > TypeError: data has to be a list of lists, a matrix, or a numpy array
> >
> > Any suggestion?
> >
> See the documentation. Just type on the notebook:
> find_fit?
> ...
> data – A two dimensional table of *floating point* numbers.
> ...
>
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