On Fri, 12 Mar 2010 at 01:27PM +0100, G. Damm wrote:
> is it possible to make stereographic 3d-plots with sagetex?
> I'd want to make a beamer-presentation with these plots and want to
> help my students see the 3d.
Can Sage make stereographic 3-d plots? If there's a way to get a PNG
image of suc
Dear support
the following two commands can be used to test, if a function is a
polynomial or quotient of two polynomials in x variable.
sage: (x^3+x+3+1/(x))._maxima_().polynomialp([x]).sage()
0
sage: ((x^3+x+3+1)/(x^4+3))._maxima_().polynomialp([x],"constantp",
"integerp").sage()
1
Is there a
And I guess the answer to Paul's question is then:
sage: (sinh(log(t)))._maxima_().exponentialize().sage()
1/2*t - 1/2/t
sage: (cos(log(t)))._maxima_().exponentialize().sage()
1/2*e^(-I*log(t)) + 1/2*e^(I*log(t))
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On 12 bře, 21:19, Guillaume wrote:
> > No, AFAIK, nothing other than explicit substitution with .subs().
>
> Hello,
>
> there are a few weird results. I'd like to solve this homogenous edo :
>
> $tx'=x+\sqrt{x^2+y^2}$.
>
> using x=tu
>
> sage: t=var('t')
> sage: x(t) = function('x',t)
> sage: id
On 12 bře, 16:48, Burcin Erocal wrote:
> On Fri, 12 Mar 2010 15:23:43 +0100
>
> Paul Zimmermann wrote:
> > is there a way in Sage to convert expressions involving trigonometric
> > or hyperbolic functions to exponentials, like the convert/exp
> > function of Maple?
>
> > > convert(sinh(log(t)),
> No, AFAIK, nothing other than explicit substitution with .subs().
Hello,
there are a few weird results. I'd like to solve this homogenous edo :
$tx'=x+\sqrt{x^2+y^2}$.
using x=tu
sage: t=var('t')
sage: x(t) = function('x',t)
sage: id(t)=t
sage: u=function('u',t)
sage: d=diff(u*id,t)
appar
On Mar 12, 9:18 am, Michael Beeson wrote:
> On the pagehttp://www.sagemath.org/doc/reference/sage/symbolic/expression.html
>
> the first example has eqn.subs(x==5) and I think it should be
> eqn.subs(x=5)
It seems to work either way, and there are examples in the
documentation using both: type
Hi,
Is this helping?
sage: var('a,b,z')
(a, b, z)
sage: f=a*z+i*b*z^2
sage: f.norm()
b*z^2*conjugate(b)*conjugate(z)^2 - I*a*z*conjugate(b)*conjugate(z)^2
+ I*b*z^2*conjugate(a)*conjugate(z) + a*z*conjugate(a)*conjugate(z)
sage: f.norm().full_simplify()
b^2*z^4 + a^2*z^2
sage: f.norm().factor()
(b
sage: var('z'); var('a');var('b');
sage: F = a*z + i*b*z^2
sage:
Now F.norm() or something should give me (a*z)^2 + (b*z^2)^2, but I
can't find a command to do that.
I want to do this when F is a polynomial of degree 6 with complex
rational coefficients to eliminate i and produce
a polynomial o
I think I've got a vague idea what happens here... The same thing also
happens when
I define the max() function myself:
sage: def my_max(x,y):
sage: if(x>y): return x
sage: else: return y
sage: fermi2(x,y,d,L) = 1 - 1/( exp( ( my_max(abs(x),abs(y))-L) /d) +
1)
sage: fermi2
(x, y, d, L)
On Mar 12, 2010, at 9:05 AM, gerhard wrote:
Trying to wrap an existing library.
I managed to at least get started with a .spyx file as follows:
cdef extern from "stdlib.h":
void *malloc(size_t size)
int free(void*)
int sizeof()
cdef extern from "func.h
On the page
http://www.sagemath.org/doc/reference/sage/symbolic/expression.html
the first example has eqn.subs(x==5) and I think it should be
eqn.subs(x=5)
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On Mar 12, 5:47 pm, Harald Schilly wrote:
> I'm not sure but there might be a bug or problem evaluating the
> expression. Anyways, going the "pure" python way works:
>
> sage: def fermi(x,y,d,L): return 1 - 1/( exp( ( max(abs(x),abs(y))-
> L) /d) + 1)
>
> sage: plot3d(lambda x,y : fermi(x,y,0.
Trying to wrap an existing library.
I managed to at least get started with a .spyx file as follows:
cdef extern from "stdlib.h":
void *malloc(size_t size)
int free(void*)
int sizeof()
cdef extern from "func.h":
int func( int n, float* x )
cdef doub
On Mar 12, 5:39 pm, stefan wrote:
> I have encountered a somewhat strange problem ...
Ah, I got it, the max function is evaluated during the definition of
the function, look:
sage: fermi(x,y,d,L) = 1 - 1/( exp( ( max(abs(x),abs(y))-L) /d) + 1)
sage: fermi
(x, y, d, L) |--> -1/(e^(-(L - abs(x))/
On Mar 12, 5:39 pm, stefan wrote:
> Basically, I am trying to plot this expression:
>
> #sage> fermi(x,y,d,L) = 1 - 1/( exp( ( max(abs(x),abs(y))-L) /d) + 1)
I'm not sure but there might be a bug or problem evaluating the
expression. Anyways, going the "pure" python way works:
sage: def fermi(
Hello group,
I have encountered a somewhat strange problem in plotting a simple
function. It seems to be related to the issues described in the
tutorial section "Some Common Issues with Functions", but the lambda-
function trick does not work here.
I have uploaded a worksheet with what I have bee
Hello all,
is it possible to make stereographic 3d-plots with sagetex?
I'd want to make a beamer-presentation with these plots and want to
help my students see the 3d.
Thanks,
Georg
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On Fri, 12 Mar 2010 15:23:43 +0100
Paul Zimmermann wrote:
> is there a way in Sage to convert expressions involving trigonometric
> or hyperbolic functions to exponentials, like the convert/exp
> function of Maple?
>
> > convert(sinh(log(t)),exp);
> 1
>
Hi,
is there a way in Sage to convert expressions involving trigonometric or
hyperbolic functions to exponentials, like the convert/exp function of Maple?
> convert(sinh(log(t)),exp);
1
t/2 - ---
Actually I do need them to be plotted by color.it seems that sage is not
designed for this way.could anyone give some information aboutwhat open source
software can do this?Thanks a lot!YC - 原文 - 发件人: Jason Grout 主 题: Re:
回复: [sage-support] Re: 3D plot in sage时 间: 2010年3月12日 01:26:30On
On 03/12/2010 03:51 AM, Marshall Hampton wrote:
> One option is several implicit plots, colored by value, i.e. something
> like:
>
> var('x,y,z')
> f=cos(x)*cos(y)+cos(y)*cos(z)+cos(z)*cos(x)
>
> imps = []
> plot_range = srange(0,3,.75)
> color_range = [i/N(len(plot_range)) for i in range(len(plo
One option is several implicit plots, colored by value, i.e. something
like:
var('x,y,z')
f=cos(x)*cos(y)+cos(y)*cos(z)+cos(z)*cos(x)
imps = []
plot_range = srange(0,3,.75)
color_range = [i/N(len(plot_range)) for i in range(len(plot_range))]
for i,q in enumerate(plot_range):
red = color_rang
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