On 2 June 2015 at 13:26, Gregory Bard wrote:
>
> Consider the integral of sqrt( cot(x)^2 ). I think we can all agree that
>
> sqrt( cot(x)^2 ) = abs( cot (x) ) =/= cot(x)
>
> ...
That is probably exactly where the disagreement starts since sqrt can
be considered a "multi-valued function" and one
Hi everyone. I have found a bug in how Sage computes integrals, but it
seems to be the case that it can come up in a broad set of situations. This
bug caused me tremendous embarrassment while teaching Calculus II last
semester.
Consider the integral of sqrt( cot(x)^2 ). I think we can all agre
