On 2 June 2015 at 13:26, Gregory Bard <gregory.bard1...@gmail.com> wrote: > > Consider the integral of sqrt( cot(x)^2 ). I think we can all agree that > > sqrt( cot(x)^2 ) = abs( cot (x) ) =/= cot(x) > > ...
That is probably exactly where the disagreement starts since sqrt can be considered a "multi-valued function" and one can choose branch cuts so that the equality holds. -- You received this message because you are subscribed to the Google Groups "sage-devel" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-devel+unsubscr...@googlegroups.com. To post to this group, send email to sage-devel@googlegroups.com. Visit this group at http://groups.google.com/group/sage-devel. For more options, visit https://groups.google.com/d/optout.
