[R] Breaking up a Row in R (transpose)

I have the following: Time A1 A1 B1 B1 C1 C2 x y x y x y 0 5 6 6 7 7 9 1 3 4 4 3 9 9 2 5 2 6 4 7 4 I want to change it to the following: 0

Re: [R] Breaking up a Row in R (transpose)

I have something like 28 rows and 6000 columns. How would I configure this with for loops. Thank you. Marc -- View this message in context: http://r.789695.n4.nabble.com/Breaking-up-a-Row-in-R-transpose-tp4607658p4609309.html Sent from the R help mailing list archive at Nabble.com. _

Re: [R] Breaking up a Row in R (transpose)

I am not opposed to for loops just do not know how to implement them. I am sorry for all the questions I am trying to learn. The posted code does not work for me in my set I am getting a : Error in `dimnames<-.data.frame`(`*tmp*`, value = list(c("A1", "A1.1", : invalid 'dimnames' given for d

Re: [R] Breaking up a Row in R (transpose)

structure(list(A2 = structure(c(9L, 4L, 4L, 3L, 5L, 7L, 5L, 7L, 6L, 1L, 1L, 1L, 3L, 4L, 5L, 5L, 2L, 5L, 3L, 4L, 4L, 8L, 4L, 3L, 4L, 5L, 4L, 3L), .Label = c("4.957", "4.958", "4.959", "4.96", "4.961", "4.962", "4.963", "4.964", "x"), class = "factor"), A2.1 = structure(c(6L, 2L, 2L, 2L, 2L,