[R] plot x-axis DateTime NOT evenly spaced

R-64 latest Hi. I am trying to plot a set of csv data, which looks like > head(interval) date inteval 1 2012-07-01 00:57:54 +0900 156 2 2012-07-01 01:07:41 +0900 587 3 2012-07-01 01:09:31 +0900 110 4 2012-07-01 01:18:42 +0900 551 5 2012-07-01 01:39:01 +0900

Re: [R] plot x-axis DateTime NOT evenly spaced

-%m-%d %H:%M:%S") > library(xts) > dat3<-xts(dat2[,-1],order.by=dat2[,1]) > plot(dat3) > A.K. > > > > > - Original Message - > From: ishi soichi > To: r-help > Cc: > Sent: Monday, January 7, 2013 3:55 AM > Subject:

[R] installing biOps on MacOSX fails

version.string R version 2.15.2 (2012-10-26) I am trying to install biOps on MacOS X 10.8.2 First, I have tiff, fftw-3, jpeg and set paths like cd /usr/include sudo ln -s /usr/local/include/fftw3.h for x in /usr/local/include/j*.h; do sudo ln -s $x; done for x in /usr/local/include/tiff*.h; do

Re: [R] installing biOps on MacOSX fails

2013/3/4 Prof Brian Ripley > See the recent discussion on R-sig-mac (the place to ask questions about > OS X). > > > On 04/03/2013 11:00, ishi soichi wrote: > >> version.string R version 2.15.2 (2012-10-26) >> >> I am trying to install biOps on MacOS X 10.8.2 &g

[R] reduce the size of list

hi. I have a list like x <- list(1:10,11:20,21:30) It's a sort of a 3 x 10 matrix in list form. I would like to reduce the dimension of this list. it would be something like list(1:3, 11:13, 21,23) I tried x[,1:3] does not work of course. Neither lapply(x, [1:3]) works... Any suggestions?

Re: [R] reduce the size of list

thanks! It works. I couldn't possibly figure out such trick... soichi 2013/3/8 Jorge I Velez > If I understood correctly, > > lapply(x, "[", 1:3) > > will do what you want. > > HTH, > Jorge.- > > > On Fri, Mar 8, 2013 at 5:05 PM, ishi soic

[R] transpose lists

Can you think of a function that transposes a list like > x [[1]] [1] 12.1 0.1 12.0 1.1 [[2]] [1] 3.44 3.00 33.10 23.00 ? ishida [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listi

Re: [R] transpose lists

help-boun...@r-project.org [mailto:r-help-bounces@r- > > project.org] On Behalf Of ishi soichi > > Sent: Friday, March 08, 2013 10:50 AM > > To: r-help > > Subject: [R] transpose lists > > > > Can you think of a function that transposes a list like > > What shall

Re: [R] transpose lists

t; function (i) sapply(lis, "[", i)) > > > I hope it helps. > > Best, > Dimitris > > > On 3/8/2013 11:06 AM, ishi soichi wrote: > > Thanks. The result should be a list of lists like... > > > >> x > > [[1]] > > [1] 12.10 3.44 >

[R] list + lapply insead of matrix + apply

I need to develop a simple list manipulation. Although it seems easier to do it in matrix form, but I need it in list form. I have a matrix x <- matrix(c(12.1, 3.44, 0.1, 3, 12, 33.1, 1.1, 23), nrow=2) for list form example, the conversion is x.list <- lapply(seq_len(nrow(x)), function(i) x[i,]

Re: [R] list + lapply insead of matrix + apply

there is a typo. lapply(x.list, calcnorm, x.list) should be lapply(x.list, calcnorm2, x.list) sorry. 2013/3/10 ishi soichi > I need to develop a simple list manipulation. Although it seems easier to > do it in matrix form, but I need it in list form. > > I have a matrix >

Re: [R] list + lapply insead of matrix + apply

t; > > For the second case: > lst1<-as.list(data.frame(t(apply(x,1,calcnorm2.const,x > names(lst1)<- NULL > lst1 > #[[1]] > #[1] 0.0 31.75257 > > #[[2]] > #[1] 31.75257 0.0 > > > > > A.K. > - Original Message - > From:

Re: [R] take two columns from a set of lists

the title of this thread was wrong. it's misleading sorry. ishida 2013/3/11 ishi soichi > > say I have a matrix and lists like > > x <- matrix(c(12.1, 3.44, 0.1, 3, 12, 33.1, 1.1, 23), nrow=2) > > x.list <- lapply(seq_len(nrow(x)), function(i) x[i,]) > > if

[R] take two columns from a set of lists

say I have a matrix and lists like x <- matrix(c(12.1, 3.44, 0.1, 3, 12, 33.1, 1.1, 23), nrow=2) x.list <- lapply(seq_len(nrow(x)), function(i) x[i,]) if I want a column of the matrix x, I write x[, 2] for example. But how can I do something similar for a set of lists, x.list, above? > x.lis

Re: [R] take two columns from a set of lists

yes. thank you. ishida 2013/3/11 Jorge I Velez > Is the following that you are looking for? > > unlist(lapply(x.list, "[", 2)) > > HTH, > Jorge.- > > > On Mon, Mar 11, 2013 at 9:52 PM, ishi soichi <> wrote: > >> say I have a matrix and l

[R] image color analysis

I am not sure if I should ask this question in this list. But I'll try. Currently I am trying to analyze images using EBImage and biOps. One of the features that I need to extract from various images is the color spectrum, namely, which colors each image consists of. So, each image hopefully can

Re: [R] image color analysis

thanks for the tips! your answer will certainly help me a lot! ishida 2013/3/13 Robert Baer > On 3/13/2013 12:05 AM, ishi soichi wrote: > >> I am not sure if I should ask this question in this list. But I'll try. >> >> Currently I am trying to analyze images using

[R] distinguishing input objects for a function

platform x86_64-apple-darwin9.8.0 arch x86_64 os darwin9.8.0 system x86_64, darwin9.8.0 version.string R version 2.13.1 (2011-07-08) I am trying to write a function that takes a few objects as input. test <- function(directory, num = 1:100) { > } the argument