yes. thank you. ishida
2013/3/11 Jorge I Velez <jorgeivanve...@gmail.com> > Is the following that you are looking for? > > unlist(lapply(x.list, "[", 2)) > > HTH, > Jorge.- > > > On Mon, Mar 11, 2013 at 9:52 PM, ishi soichi <> wrote: > >> say I have a matrix and lists like >> >> x <- matrix(c(12.1, 3.44, 0.1, 3, 12, 33.1, 1.1, 23), nrow=2) >> >> x.list <- lapply(seq_len(nrow(x)), function(i) x[i,]) >> >> if I want a column of the matrix x, I write >> >> x[, 2] >> >> for example. >> >> But how can I do something similar for a set of lists, x.list, above? >> >> > x.list >> [[1]] >> [1] 12.1 0.1 12.0 1.1 >> >> [[2]] >> [1] 3.44 3.00 33.10 23.00 >> >> unlist(x.list)[,2] does not work. >> >> >> Anyone? >> >> ishida >> >> [[alternative HTML version deleted]] >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
