I ran two separate hours-long projects. Results of each were saved to
two separate .RData files.
Content of each includes, among others, the following:
me se t p sig
pc21.age 0.640 0.219 2.918 0.004 ***
pc21.agesq 0.000 0.000 NaN NaN
pc21.inc
t not html, otherwise they can
> be mangled.
>
> Cheers
> Petr
>
>> -Original Message-
>> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Steven Yen
>> Sent: Tuesday, January 16, 2018 9:44 AM
>> To: r-help@r-project.org
>> Su
Understood. In my case, a.RData and b.RData contain identical
variables/data, plus simulation outputs from separate runs. The codes
deliver what I need. Good to know the three lines work. Thank you.
On 1/16/2018 8:06 PM, Duncan Murdoch wrote:
> On 16/01/2018 6:33 AM, Steven Yen wrote:
>&g
I am running R-3.0.3 on RStudio 1.1.183. I have recently gotten the following
error message while saving an .RData file with the save.image command. I have
not had this problem until recently. Help appreciated.
===
Error in save.image("bope1a.RData") :
image could not be renamed and is left i
I have trouble documenting an R package. In my .Rd file (sixth line below), I
have
uhat<-m%*%y
but when the package is built (successfully), the matrix multiplication part
does not show up in the documentation. The line become (missing %*% y)
uhat<-m
===
\examples{
x<-c(1,2,3,4,5)
y<-c(1,1,2,
I build binary data files into a library by placing the .rda files at the
proper \data sub-folder before building the library with the following
procedure:
1. File -> Open project
2. Build -> Build binary packages.
This has worked up to 3 .rda files.
Now, I add another .rda file to the folder. I
I have had trouble installing packages (e.g., car, aod) in some
computers (such as computers in the student lab) but no problem in my
own laptop.
Installation typically goes through, but after I got out and back in R
(and RStudios), the error message says "packages xxx not available".
That is,
eed(76543211)
a<-matrix(rpois(20,2),nrow=10); a
a<-sqrt(w)*a; a
t(a)%*%a
On 1/4/2017 5:41 PM, Steven Yen wrote:
> I need help with gls{nlme}.
> Specifically, I am estimating an equation with AR(1) using
> maximum-likelihood. I am not understanding the correlationoption
lemented two of them (?) and it is unclear (to me) what you think
> the right answer for any of them is supposed to be.
> -- Sent from my phone. Please excuse my brevity. On June 7, 2017
> 8:50:55 PM PDT, Steven Yen wrote:
>> I need to have all elements of a matrix multiplied by a
What is a good way to grep multiple strings (say in a vector)? In the
following, I grep ants, cats, and fox separately and concatenate them,
is there a way to grep the trio in one action? Thanks.
all<-c("ants","birds","cats","dogs","elks","fox"); all
[1] "ants" "birds" "cats" "dogs" "elks" "
Dear R users:
> # p is a vector if length 10
> # a is a vector if length 3
> # I like to create a matrix with
> # the first column being p multiplied by a[1]
> # the second column being p multiplied by a[2]
> # the third column being p multiplied by a[3]
> # The following would do that:
Hi all, need help below. Thank you.
> # Matrix v is 5 x 3
> # Vector b is of length 3
> # I like to add b[1] to all element in v[,1]
> # I like to add b[2] to all element in v[,2]
> # I like to add b[3] to all element in v[,3]
> # as follows
> v<-matrix(0,nrow=5,ncol=3); v
[,1] [,2] [
Dear fellow R users:
I am reading a data (ascii) file with fortran fixed format, containing
multiple records. R does not recognize fortran's record break (a slash).
I tried to do the following but it does not work. Help appreciated.
60 FORMAT(1X,F6.0,5F8.6/1X,5F8.4,F10.6/1X,2F6.0,3E15.9,F8.0,F
n 5/27/2016 2:21 PM, John McKown wrote:
> On Fri, May 27, 2016 at 12:56 PM, Steven Yen <mailto:sye...@gmail.com>>wrote:
>
> Dear fellow R users:
> I am reading a data (ascii) file with fortran fixed format, containing
> multiple records. R does not recognize fortran
f8")), digits=10)
> V1 V2 V3 V4 V5 V6 V7
> 1 1950 0.61435 0.026834 0.087227 0.006821 0.180001 0.0456
>
>
> If I recall correctly, a dot in the format pushes the decimal point:
>
> > print(read.fortran(textConnection(txt), c("f5&
I read a csv file (with read.csv) containing missing values (as shown
below). Is there a convenient way to set these NA into zeros?
Better yet, is there an option to assign zeros to these blank cells in
reading the csv file? Thank you!
NA -1 NA NA NA 1 NA
NA NA NA NA NA NA NA
NA NA
test option for linearHypothesis in library(car) include "Chisq" and
"F". I prefer a simple t-test so that I can retrieve the standard error.
Any options other than linearHypothesis to test the linear hypothesis
(with 1 restriction/degree of freedom)?
> summary(ols1)
Coefficients:
helps,
> John
>
> -
> John Fox, Professor
> McMaster University
> Hamilton, Ontario
> Canada L8S 4M4
> Web: socserv.mcmaster.ca/jfox
>
>
>> -Original Message-
>> From: R-help [mailto:r-help-boun...@r-project.org] On Be
> development version of the car package on R-Forge, which you should be able
> to install via install.packages("car", repos="http://R-Forge.R-project.org";).
> Then see ?linearHypothesis for more information.
>
> Best,
> John
>
>> -Original Me
Also,
Is there a way to get the second command (hypothesis defined with
externally scalars) below to work? Thanks.
linearHypothesis(U,"0.5*eq1_DQ+0.3*eq2_DQ",verbose=T)
w1<-0.5; w2<-0.3
linearHypothesis(U,"w1*eq1_DQ+w2*eq2_DQ",verbose=T) # does not work
On 6/29/2016
A is a 5 x 3 matrix and a is a 3-vector. I like to exponentiate A[,1] to
a[1], A[,2] to a[2], and A[,3] to a[3], and obtain the product of the
resulting columns, as in line 3.
I also accomplish this with lines 4 and 5. I like to have rowProducts(B)
but there is not so I came up with something u
I recently updated my R and RStudio to the latest version and now the
binary option in the "build" command in devtools stops working.
I went around and used the binary=F option which worked by I get the
.tar.gz file instead of the .zip file which I prefer.
Does anyone understand the following e
Thanks. I found the reason was Rtools does not run under the new version
of R. I had to go back to as early as R 3.0.2 (September 2013) to make
Rtools work.
Any idea for a go-around? Thanks.
On 7/19/2016 4:38 PM, John McKown wrote:
> On Tue, Jul 19, 2016 at 3:15 PM, Steven Yen <mail
tion like this.
Any help/insight would be appreciated.
On 7/20/2016 10:08 AM, Steven Yen wrote:
> On 7/19/2016 4:38 PM, John McKown wrote:
>> On Tue, Jul 19, 2016 at 3:15 PM, Steven Yen > <mailto:sye...@gmail.com>>wrote:
>>
>> I recently updated my R and RStudio to
How do I read a block of space-delimited numbers into a column vector
using the read.table command? Thank you.
--
Steven Yen
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
Dear Members
I have a data frame as generated below. I like to be able to call a
function both with a vector and a vector (mydata$v1) in that data frame
(v1). The first call works, but the second does not. Can someone help me
with the second call? Thanks!!
---
mydata<-data.frame(matrix(1:20,ncol=
Thanks! From this I learn the much needed class statement
if (class(wt)=="character") wt <- x[, wt]
which serves my need in a bigger project.
Steven Yen
On 6/23/2015 6:20 PM, boB Rudis wrote:
You can do something like:
aaa <- function(data, w=w) {
if (class(w)
t;mts" and "ts"
- The time-date objects POSIXt , POSIXct, POSIXlt
==> do work with inherits(, , )
We've seen this use of
class(.) == ".."(or '!=" or %in% ...)
in too many places; though it may work fine in your test cases,
it is
was hoping to figure out a way to fix the wmean
routine some how so that I can call with
wmean(mydata,wt=weight)
Good to know there is a better way to initialize the vector Mean and and
a better list command. Thank you!
On 6/26/2015 2:39 AM, David Winsemius wrote:
On Jun 25, 2015, at
How do I judge if a matrix contain any NA or otherwise non-missing,
non-numerical?
In the following, I would like to deliver ONE logical of TRUE or FALSE,
rather than a 4 x 4 matrix containing TRUE or FALSE. Thank you.
> a<-matrix(1:16,nrow=4)
> diag(a)<-NA
> a
[,1] [,2] [,3] [,4]
[1,] N
I need help with element-by-element division. Below, matrices a and c are
both 5 x 2 and element-by-element division works as (I) expected. What if
matrix is 1 by 2: to divide first column of a by b[1] and second column of
a by b[2]. I had to go around (two ways) to make it work. In Gauss, these
ca
I have a line containing summation of four components.
# This works OK:
p<-pbivnorm(bb,dd,tau)+pbivnorm(aa,cc,tau)-
-pbivnorm(aa,dd,tau)-pbivnorm(bb,cc,tau)
# This produces unpredicted results without warning:
p<-pbivnorm(bb,dd,tau)+pbivnorm(aa,cc,tau)
-pbivnorm(aa,dd,tau)-pbivnorm(bb
My obj does not always come with a logical variable defined. So I do
my.foo <- function(obj,df,digits=5){
if (!is.na("obj$spec$Fisher")) Fisher<-obj$spec$Fisher
...
}
This works when "Fisher" is defined in/passed from obj. When it is
not, I get error:
Error in (!is.na("obj$spec$Fisher")) & Fi
t(spec = list)
Fisher <- ifelse(!("Fisher" %in% names(obj$spec)), FALSE, obj$spec$Fisher)
Cheers,
Ben
On Dec 14, 2014, at 8:07 AM, Steven Yen wrote:
> My obj does not always come with a logical variable defined. So I do
>
> my.foo <- function(obj,df,digits=5){
> if (!i
How do I specify the type of regression in calling a procedure/
In the following I call the procedure to do a probit regression. Of
course, I can change "probit" into "lm" in procedure "myreg" to do a
linear regression.
My question is, how do I automate this (choice of lm or probit) in
callin
I like to multiple the first and second column of a 10 x 3 matrix by
100. The following did not work. I need this in an operation with a
much larger scale. Any help?
aa<-matrix(1:30,nrow=10,ncol=3); aa
bb<-matrix(c(100,100,1),nrow=1,ncol=3); bb
dim(aa)
dim(bb)
aa*bb
Results:
> aa<-matrix(1:30
Thank you both. Both John and Peter's suggestions work great!!
At 06:17 PM 1/7/2015, John McKown wrote:
>On Wed, Jan 7, 2015 at 5:05 PM, Steven Yen
><<mailto:sye...@gmail.com>sye...@gmail.com> wrote:
>I like to multiple the first and second column
>of a 10 x 3 mat
Dear
I use sm2vec from package corpcor to puts the lower triagonal entries
of a symmetric matrix (matrix A) into a vector. However, sm2vec goes
downward (columnwise, vector B), but I would like it to go across
(rowwise). So I define a vector to re-map the vector (vector C). This
works. But is
88050 0.3907721 1.0941534 0.2402183 -1.6214086
No need to play with potentially error-prone index vectors; upper.tri
does that for you.
Hope this helps,
Peter
On Fri, Jan 30, 2015 at 3:03 PM, Steven Yen wrote:
> Dear
> I use sm2vec from package corpcor to puts the lower triagonal entries of a
&
I am trying to build an R package with Rtools version 3.5.0.4 along with
R-3.5.1
using the following sequence of commands:
File -> Open Project -> Build -> Build Binary Package
I received the following error message:
zip I/O error: No such file or directory
zip error: Temporary file failure (Y
Can someone help me with polygon. The following codes are self-runnable
and mark a shaded area under the standard normal curve in the x-range
(-3,-1).
Is there a way to also mark the area in (1,3), at the same time.
That is, I want shaded areas in both tails. Thank you...
===
# Create data for t
inue with
>
>
> polygon(-rev(cord.x), rev(cord.y), col = 'skyblue')
>
>
> Hope this helps,
>
> Rui Barradas
>
> Às 17:25 de 02/10/2018, Steven Yen escreveu:
>> Can someone help me with polygon. The following codes are self-runnable
>> and mark a shad
Thanks!!! It did wonders.
Steven
On 10/3/2018 9:39 AM, David Winsemius wrote:
>> On Oct 2, 2018, at 5:50 PM, Steven Yen wrote:
>>
>> Great. Thanks! It did wonders.
>> 1. Is there a way to suppress the obvious tick stops (-3,-2,-1,0,1,2,3)
>> and mark only the tick
Is it possible to release the file destination after sending it to a pdf
file?
Below, line 3 send the graph to a pdf file.
I like to release the devise so that I can see result produced by line
for on the console (screen). Thanks.
x<-1:10
pdf("test1.pdf") # pdf {grDevices}
boxplot(x) # This goes
David, Rui, and All:
Greetings.
1. I need a helping hand with the polygon statement below so that I can
have the area under the curve highlighted, between (z1,z2).
2. Is it possible to label the X-axis with in two scale, in the current
z-scale and another, say x = (z+5)*2?
Thank you.
z1<- -1
z2<
I need help with "apply". Below, I have no problem getting the column sums.
1. How do I get the sum of squares?
2. In general, where do I look up these functions?
Thanks.
x<-matrix(1:10,nrow=5); x
sum <- apply(x,2,sum); sum
[[alternative HTML version deleted]]
How do I print a matrix running a procedure? In the code below, I print
with the cat command and get a vector (from A and C).
A<-matrix(rpois(16,lambda=5),nrow=4,byrow=T)
B<-diag(4)
try5<-function(A,B){
C<-A+B
cat("\nA =",A,"\nC = ",C)
structure(list(A=A,B=B,C=C))
}
v<-try5(A,B)
v$C
--
st
("\nC = ")
> print(C)
> structure(list(A=A,B=B,C=C))
> }
>
> HTH,
> Eric
>
>
> On Sat, Dec 22, 2018 at 4:32 PM Steven Yen <mailto:st...@ntu.edu.tw>> wrote:
>
> How do I print a matrix running a procedure? In the code below, I
> pri
I have known from the old days to set a random seed of a LARGE ODD
NUMBER. Now I read instructions of set.seed and it requires ANY INTEGER.
Any idea? Or, does it matter. Thanks.
--
st...@ntu.edu.tw (S.T. Yen)
[[alternative HTML version deleted]]
__
I would like to suppressed printing of retrievable results in a
procedure and to print only when retrieved.
In line 10 below I call procedure "try" and get matrices A,B,C all
printed upon a call to the procedure. I get around this unwanted
printing by calling with v<-try(A,B) as in line 11.
An
s already a base function try() so that's not a great
> name for test functions.
>
> Sarah
>
> On Tue, Dec 25, 2018 at 8:47 AM Steven Yen <mailto:st...@ntu.edu.tw>> wrote:
>
> I would like to suppressed printing of retrievable results in a
> procedure and
I install package using either the command line or Tools -> Install
packages... (in RStudio) and get a non-fatal message saying...
Installing package into ‘C:/Users/xuhaer/Documents/R/win-library/3.5’
(as ‘lib’ is unspecified)
I know it is not a fatal message. But, is there a way to do a cleaner
I like to print a vector, wrapped by rows of 10.
Below the first command below works for 20 numbers.
The second command is ugly. How can I print the 25 numbers into 2 rows
of ten plus a helf row of 5? Thanks.
> x<-1:20; matrix(x,nrow=2,byrow=T)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9]
Is there a way to over-write a procedure (subroutine)?
I include a default procedure fixx in a list of procedures which are
compiled into a package. By default, the procedure deliver the data matrix x.
fixx <- function(x){
result <- list(x=x)
return(result)
}
In some applications, I have tran
nside of a package
namespace then look at the assignInNamespace function in the utils
package (but note the warning in the description on the help page).
On Tue, Sep 2, 2014 at 12:45 PM, Steven Yen wrote:
> Is there a way to over-write a procedure (subroutine)?
>
> I include a default procedure f
I use the following command to write data to a .csv file:
write.csv(yxz,file="foo.csv")
And I get the following in the file, with one column appended to the file:
"","fsp","fsec","cincome",
"1",0,3,2.25,...
"2",0,1,2.75,...
"3",1,1,0.625,...
Question: is there a way to avoid the first colu
Wonderful. It worked like charms and I love it! Thank you Don.
Steven
At 05:06 PM 9/24/2014, Don McKenzie wrote:
I believe you need to specify row.names = FALSE
See the help for write.table()
On Sep 24, 2014, at 2:00 PM, Steven Yen wrote:
> I use the following command to write data t
Hello
I read data with fortran format:
mydata<-read.fortran('foo.txt',
c("4F10.4","F8.3","3F3.0","20F2.0"))
colnames(mydata)<-c("q1","q2","q3","q4","income","hhsize",
"weekend","dietk","quart1","quart2","quart3","male","age35",
"age50","age65","midwest","south","west","no
Thanks to all.
Steven Yen
At 06:18 PM 9/30/2014, Nordlund, Dan (DSHS/RDA) wrote:
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Steven Yen
> Sent: Tuesday, September 30, 2014 2:04 PM
> To: r-help
> Su
Hello
Any idea how to read a text file with fortran format, WITH MULTIPLE
RECORDS? My fortran format is as follows, and I do know I need to
change F7.4 to F7.0, and 2F2.0 to 2I2, etc.
I just have no idea how to handle the "slash" (/) which dictates a
jump to the next record in fortran. Thank yo
Hello
Can someone help me with the following, specifically in judging
whether a matrix exists. I have trouble with the first line below. In
this case, matrix obj$hessian exists and is 74 x 74. I receive the
error message:
Warning message:
In all(w$hessian) : coercing argument of type 'double' t
AM 10/19/2014, Richard M. Heiberger wrote:
all() takes a logical argument, not numeric. See ?all
I think you are looking for
is.null(obj$hessian)
If this isn't what you are looking for, please send a reproducible example
to the entire list.
Rich
On Sun, Oct 19, 2014 at 12:17 AM, Ste
Dear
I am interested in selecting rows and columns of a matrix with a
criterion defined by a binary indicator vector. Let matrix a be
> a<-matrix(1:16, 4,4,byrow=T)
> a
[,1] [,2] [,3] [,4]
[1,]1234
[2,]5678
[3,]9 10 11 12
[4,] 13 14 15 16
5 11 17 23 29 35
[6,]6 12 18 24 30 36
> (j<-matrix(c(0,1,0,1,0,1)))
[,1]
[1,]0
[2,]1
[3,]0
[4,]1
[5,]0
[6,]1
> ((a[as.logical(j), as.logical(j)]))
[,1] [,2] [,3]
[1,]8 20 32
[2,] 10 22 34
[3,] 12 24 36
Steven Yen
before and after. Thanks.
Steven Yen
---
out<-round(cbind(me,se,t,p),digits)
colnames(out)<-c("estimates","s.e.","|t-value|","p-value")
rownames(out)<-rownames(me)
out
estimates s.e. |t-value| p-value
(Intercept) 0.223263 0.146167
Wonderful. Works great!
Steven Yen
At 11:52 AM 10/29/2014, Kevin E. Thorpe wrote:
On 10/29/2014 11:41 AM, Steven Yen wrote:
Hello
I am designing a regression printout, which works out nicely. Then, I
try to inject a column of characters to indicate a discrete regressor
with a dot (.). Then
I like to remove from a data frame rows with labels containing
certain string, e.g., "sex" and "rating". Below is a list of the data
frame and my failed attempt to the rows. Any clues? Thanks.
> out
est se t p disc
p.(Intercept) 26.430 13.605 1.943 0.053
p.sex
t all but the rows whose names contain the character sequences
>"sex" or "rating".
>
>Bill Dunlap
>TIBCO Software
>wdunlap <http://tibco.com>tibco.com
>
>On Sun, Nov 16, 2014 at 6:31 PM, Steven Yen
><<mailto:sye...@gmail.com>sye...@gmail.
I had trouble with matrix multiplication when a matrix reduces to a
vector. In the following, lines 1 and 2 work when matrices u and a are
both of order 2.
Lines 3 and 5 do not work (message is matrix not conformable) when u is (T
x 1) and a is (1 x 2) and This causes a problem for users of other
ource'
command. This does not work; it complains about a function (fn below) not
defined.
Compiling the function into a library file does not work either (with all
sorts of error messages saying this and that not defined).
Steven Yen
fn <- function(beta){
f<-... (define f in this r
3 - fix the errors I got from making it a package. It does not lie when it
> tells you things are undefined and, who knows, they may need to be defined.
>
>
> On 03/10/2015 09:47, Steven Yen wrote:
>
>> Hi
>> I collect a list of calls to a package in a function (routine) so
or source it from inside probit.R. Thanks.
On Sat, Oct 3, 2015 at 4:47 AM, Steven Yen wrote:
> Hi
> I collect a list of calls to a package in a function (routine) so that I
> do not need to repeat the same sets of codes from program to program. In
> the following, inserting the func
Dear
How do you construct a lower triangular matrix from a vector.
I want to make vector
a <- 1:10
into a triangular matrix
1 0 0 0
2 3 0 0
4 5 6 0
7 8 9 10
Thank you!
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing
Hello
I am constructing a symmetric matrix with library "corpcor". In the
codes below, I am able to construct a symmetric matrix of order 3 and
4. However, the 5 x 5 matrix does not seem right? Help?
Thanks.
> library(corpcor)> r <- 1:3> rr <- vec2sm(r, diag = F)> rr <-
> rr[upper.tri(rr)]> r
I like to compose a symmetric matrix in the pattern as shown below (for 3 x
3 and 4 x 4). For a symmetric matrix of order 5, the result does not seem
right. Help? It is possible to write a two-level do loop for the task, but
I suppose that is less efficient.
> library(corpcor)> r <- 1:3; r[1] 1 2
Can anyone tell me how to retrieve the response (dependent) variable
from a probit regression object (as much as model.matrix(obj)
retrieves the data matrix). Below is a self-runnable set of codes.
Thank you!
library(sampleSelection)
data<-read.csv("https://dl.dropboxusercontent.com/u/220037024/Ye
Dear all
In the grep command below, is there a way to identify only "age" and
not "age2"? Thanks.
> x<-c("abc","def","rst","xyz","age","age2")
> x
[1] "abc" "def" "rst" "xyz" "age" "age2"
> grep("age2",x)
[1] 6
> grep("age",x) # I need to grab "age" only, not "age2"
[1] 5 6
Also, I post mess
Dear all
In the grep command below, is there a way to identify only "age" and
not "age2"? In other words, I like to greb "age" and "age2"
separately, one at a time. Thanks.
x<-c("abc","def","rst","xyz","age","age2")
x
[1] "abc" "def" "rst" "xyz" "age" "age2"
grep("age2",x)
[1] 6
grep("age
)
[1] 6
> grep("age\\b",x)
[1] 5
> grep("age2$",x)
[1] 6
> grep("age$",x)
[1]
From: Jim Lemon
Date: Wed, May 4, 2016 at 2:19 AM
Subject: Re: [R] Grep command
To: Steven Yen
Does not:
abcplus<-c("zxzxabc","zxzxabc2rst")
grepl("
I need help with gls{nlme}.
Specifically, I am estimating an equation with AR(1) using
maximum-likelihood. I am not understanding the correlationoption below.
Help appreciated.
===
library(nlme)
eq1<-log(chnimp)~log(chempi)+log(gas)+log(rtwex)+befile6+
affile6+afdec6
reg1<-gls(
I need help with what may be a simple option in R (or Rstudio)--to
receive an echo of a comment line.
Running the following two-line script in plain R,
# adding
1+2
I did get the echo:
> # adding
> 1+2
[1] 3
>
However, running the same lines in RStudio, the comment line does not
appear in
Can someone tell me a proper call to a procedure, in this case, pnorm.
In what follows, I had expected a = b, but they are not equal. What are
wrong with first call and second call? Thank you!
try<-function(x,log.p=FALSE){
a<-pnorm(x,log.p) # first call
b<-pnorm(x,log.p=log.p) # second ca
he variable z.
>
>
> f <- function(x, y = 0, z = FALSE){
> a <- x
> b <- y
> d <- z
> list(a = a, b = b, d = d)
> }
> z <- 2
> f(1, z)
> f(1, z = z)
>
>
> Hope this helps,
>
> Rui Barradas
>
> Às 11:11 de 20/09/20, Steven Y
d the variables in with the same order as the formal
> arguments, then you
> better name them as you send them in.
>
>
>
>
>
> On Sun, Sep 20, 2020 at 7:23 AM Steven Yen <mailto:st...@ntu.edu.tw>> wrote:
>
> > Thanks. So, to be s
I had to install/use an older version of (R-3.0.3) for a reason. While
installing a package from CRAN (either in RStudio or R), I received the
following warning message saying unable to access index for repository
http://cran.rstudio.com/bin/windows/contrib/3.0. See message below. In
this case,
is 7 years old. You shoudl realy consider to update
> to 4.0.2.
>
> Best,
> Uwe Ligges
>
>
>
>
> On 05.10.2020 09:56, Steven Yen wrote:
>> I had to install/use an older version of (R-3.0.3) for a reason. While
>> installing a package from CRAN (either in RStudio or
chive.r-project.org')
or use the contrib.url argument.
Best,
Uwe Ligges
On 05.10.2020 10:47, Steven Yen wrote:
Thanks for the help. I do update to the latest R-4.0.2. As I said,
for reasons that's hard to explain, some of my tasks are better
handled with an older version of R, in thi
eived a warning but it went on to try
https://cran-archive.r-project.org/bin/windows/contrib/3.0/aod_1.3.zip
and it worked. See log below.
I expect to continue to use R-3.0.3 for a while and I very much like
this to become a routine. Thank you all.
Steven Yen
> install.packages("aod&quo
below, probably due to an R bug.
But since you're using an obsolete version of R, it shouldn't surprise
you that it has bugs that nobody else is seeing.)
Duncan Murdoch
On 08/10/2020 11:54 a.m., Steven Yen wrote:
Thanks. You gentlemen please tell me what this means. In R (outside
of R
file from CRAC
Archive, right. So, this will always work for me? Thank you all !! If
there are more direct options that work, I would still be interested to
know.
Steven Yen
On 2020/10/9 上午 12:49, Duncan Murdoch wrote:
Don't choose a mirror. That will override the repos choice.
Do updat
ssue is
>> that important to you. Such is the nature of volunteer-developed open source
>> software... so support your local experts.
>>
>>> On October 8, 2020 10:22:54 AM PDT, Steven Yen wrote:
>>> Thanks for the help. I have a reason to continue with R-3.0.3.
autocorrect is crazy
> On Oct 9, 2020, at 4:28 AM, Arne Henningsen wrote:
>
> Hi Steven
>
> Which optimisation algorithms in maxLik work better under R-3.0.3 than
> under the current version of R?
>
> /Arne
>
>> On Thu, 8 Oct 2020 at 21:05, Steven Yen wrote:
>
In R, I was able to set the language environment by fixing the line
in file "C:\Program Files\R\R-4.0.3\etc\Rconsole", line 70 below, set
language to EN:
language = EN
In RStudio, I am not able to do that, except to include the line
Sys.setenv(LANG="en");
in every one of my program file. That
Thanks. YES, include the line
Sys.setenv(LANG="en");
in my Rprofile file and it worked.
On 2020/11/18 上午 12:43, Jeff Newmiller wrote:
put it in your .Rprofile file. Read the R Installation and Administration
Manusl for more info.
On November 17, 2020 5:00:06 AM PST, Steven Yen wr
I hope I can get away without presenting a replicable set of codes
because doing so would impose burdens.
I call a function which return a data frame, with the final line
return(out)
In one case the data frame gets printed (similar to a regression
printout), with simply a call
me.probit(obj
of
printing it. By appending ";v" tp that command line, you implicitly
call "print".
Jim
On Mon, Nov 30, 2020 at 7:15 PM Steven Yen wrote:
I hope I can get away without presenting a replicable set of codes
because doing so would impose burdens.
I call a function which return
.../R/oprobit.R")
it did print. I do not understand.
On 2020/11/30 下午 06:41, Stefan Evert wrote:
On 30 Nov 2020, at 10:41, Steven Yen wrote:
Thanks. I know, my point was on why I get something printed by simply doing
line 1 below and at other occasions had to do line 2.
me.probit(obj)
T
No, sorry. Line 1 below did not print for me and I had to go around and
do line 2 to print:
me.probit(obj)
v<-me.probit(obj); v
A puzzle.
On 2020/11/30 下午 07:00, Duncan Murdoch wrote:
On 30/11/2020 5:41 a.m., Stefan Evert wrote:
On 30 Nov 2020, at 10:41, Steven Yen wrote:
Thanks
posting a reproducible example, you're wasting everyone's time.
Duncan Murdoch
On 30/11/2020 6:06 a.m., Steven Yen wrote:
No, sorry. Line 1 below did not print for me and I had to go around and
do line 2 to print:
me.probit(obj)
v<-me.probit(obj); v
A puzzle.
On 2020/11/30 下午
I constantly define variable lists from a data frame (e.g., to define a
regression equation). Line 3 below does just that. Placing each variable
name in quotation marks is too much work especially for a long list so I
do that with line 4. Is there an easier way to accomplish thisto
define a
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