Hi,
I would like to replicate the behavior of box() with rect() (don't ask why).
However, my rect()angles are always too small. I looked a bit into the
internal C_box but
couldn't figure out how to solve the problem. Below is a minimal
working (and a slightly bigger) example.
Cheers,
Marius
## M
gt; Finally your second example simply multiplies the first problem by
> specifying a layout of more than one plot. Applying the "xaxs" and
> "yaxs" parameters before you start plotting will fix this:
>
> par(xaxs="i",yaxs="i")
>
> Jim
>
&g
col = adjustcolor("grey80", alpha.f = 0.5))
par(xpd = FALSE)
On Fri, Jun 24, 2016 at 8:40 PM, Marius Hofert
wrote:
> Hi Jim,
>
> Thanks a lot, exactly what I was looking for.
>
> Cheers,
> Marius
>
>
>
> On Thu, Jun 23, 2016 at 11:06 PM, Jim Lemon wrote:
>
On Mon, Jun 27, 2016 at 5:42 PM, Greg Snow <538...@gmail.com> wrote:
> You can use the grconvertX and grconvertY functions to find the
> coordinates (in user coordinates to pass to rect) of the figure region
> (or other regions).
>
> Probably something like:
> grconvertX(c(0,1), from='nfc', to='use
Hi,
I need a fast way to split a data.frame (and matrix) into a list of
columns. For matrices, split(x, col(x)) works (which can then be done
in C for speed-up, if necessary), but for a data.frame? split(iris,
col(iris)) does not work as expected (?).
The outcome should be lapply(seq_len(ncol(iris
Hi David and Jeff,
Thanks for your quick help, unclass() was precisely what I was looking for.
Cheers,
M
On Mon, Aug 29, 2016 at 10:39 AM, aditya pant wrote:
>
> ^^ठश्रएइ),,,
>
> From: David Winsemius
> Sent: 29-08-2016 11:59
> To: Marius H
Hi,
I have a function main() which calls another function aux() many times. aux()
mostly does the same operations based on an object and thus I would like it to
compute and store this object for each call from main() only once.
Below are two versions of a MWE. The first one computes the right res
anks & cheers,
Marius
On Mon, Aug 29, 2016 at 7:59 PM, Duncan Murdoch
wrote:
> On 29/08/2016 1:36 PM, Marius Hofert wrote:
>> Hi,
>>
>> I have a function main() which calls another function aux() many times. aux()
>> mostly does the same operations based on an obje
Hi Duncan,
... I don't have to know (I thought). The idea was to set up the environment
only for a single object x. If it (= the environment (see MWE 2) *or* the object
(see MWE 1)) exists, it's the right one. But I agree that it's 'cleaner' to work
with a hash -- yet I first wanted to understand
Hi,
Is there a plotmath symbol like LaTeX's \mapsto?
I need this comparably often, for example if you want to plot a
two-place function in one variable (and thus would like to have
ylab="t \mapsto f(t,s)", for example). If there is such a symbol, I'd
be great to have it as an example on ?plotmath.
Dear Professor Ripley,
Thank you for your reply.
Do you specify \u21A6 via something like this?
plot(1, main=expression(symbol("\u21A6")))
This gives an the 'registered trademark symbol' (circled R) for me
(also cairo-based Linux).
Thanks and cheers,
Marius
___
Hi,
Inside a C function (foo()), I need to call R's order(). Writing R
Extensions (2014, Section 6.10) gave me the hint to use
R_orderVector() for this task. The third argument of this function
needs an SEXP containing (in my case) the vector x (of which I would
like to determine order()).
My que
Dear expeRts,
I would like to find out how R computes pbinom(). A grep in the
source code reveiled src/library/stats/R/distn.R:146:
.External(C_pbinom, q, size, prob, lower.tail, log.p), so
'C_pbinom' refers to compiled C/C++ code loaded into R. Where can
I find the source code of C_pbinom?
Cheer
4 at 7:28 AM, Sarah Goslee wrote:
> R FAQ 7.40
>
> http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-do-I-access-the-source-code-for-a-function_003f
>
> Sarah
>
>
> On Tuesday, August 26, 2014, Marius Hofert
> wrote:
>>
>> Dear expeRts,
>>
>> I w
Dear Ranjan,
thanks, that was what I was looking for. Somehow my 'grep' must have
missed that.
Cheers,
Marius
On Wed, Aug 27, 2014 at 8:34 AM, Marius Hofert
wrote:
> Dear Sarah, Dear David,
>
> thanks for helping. I know the FAQ and I know the R News article, but
> I st
Dear R-Users,
I have the following problem: I would like to create a postscript file
containing an r-plot with the string "\\vartheta" in it (reason: this
is later converted to the TeX-string "\vartheta" and a vartheta is
printed in the figure). In the minimal example below, the problem is
Dear R-users,
I have a plot created with the code below. I tried to put some text to the
right of the color key. I worked with grid.text and also viewport(), but
couldn't achieve this. I know this should be simple, but I just couldn't figure
out how to do it. How does this work?
Cheers,
Mariu
Dear R-Users,
I would like to color the data in a splom according to their position in the
matrix, i.e. I would like to have all data shown in the upper left corner to be
blue, all entries below that to be black, and the data to the right to be all
red. I tried to color the "splom" with the fol
Dear ExpeRts,
I have the scatter plot matrix as given below. I would like the different
"sub-plots" in the scatter plot matrix to be colored differently. How do I get
all points shown in the upper-left plot (on position (1,1) in the scatter plot
matrix) to be plotted in blue, and the points sho
Dear expeRts,
I'm familiar with IEEE 754. Is there an easy way to explain why even
just printing of small numbers fails?
1e-317 # 1e-317 => fine
1e-318 # 9.87e-319 => gets tricky; seems to call print() => as.character()
=> format() => paste()
1e-318 == 9.87e-319 # TRUE
2.48e-324 # prints
Hi,
1) Given .Random.seed, how can one compute *the* integer 'seed' such
that set.seed(seed) generates .Random.seed?
2) If 1) is not possible, how can one compute *an* integer 'seed' from
a given .Random.seed such that different .Random.seed's are guaranteed
to give different integers 'seed' (or a
Hi,
I typically start R with "--no-restore --no-save" (to avoid .RData
files being written) and would like to have the same behavior under 'R
CMD BATCH'. I use R_BATCH_OPTIONS="--no-restore --no-save" in my
~/.Renviron but running an R script with 'R CMD BATCH' still produces
a .RData file. What's
On Tue, Sep 10, 2019 at 12:38 PM Martin Maechler
wrote:
>
> >>>>> Marius Hofert
> >>>>> on Mon, 9 Sep 2019 22:38:38 +0200 writes:
>
> > Hi,
> > I typically start R with "--no-restore --no-save" (to avoid .RData
>
exp(-x) being not quite 0, but x=746
leads to exp(-x)==0 being TRUE. But these are integer x's...
Many thanks and cheers,
Marius
>
> Bill Dunlap
> Spotfire, TIBCO Software
> wdunlap tibco.com
>
>
>> -Original Message-----
>> From: r-help-boun...@r-project.or
Hi,
?.Machine says that 'double.xmin' is 'the smallest non-zero normalized
floating-point number'. On my machine, this is 2.225074e-308. However,
2.225074e-308 / 2 is > 0 and smaller than 2.225074e-308, so
double.xmin is not the smallest such number (?) Am I missing anything?
Cheers,
Marius
___
Dear expeRts,
Here is a minimal example with the latest version of 'tables' (questions below):
require(tables)
saveopts <- table_options(toprule="\\toprule", midrule="\\midrule",
bottomrule="\\bottomrule",
titlerule="\\cmidrule(lr)",
rowlabeljustification="r")#, justi
Dear expeRts,
I struggle with the following problem using snow clusters for parallel
computing: I would like to specify l'Ecuyer's random number generator. Base R
creates a .Random.seed of length 7, the first value indicating the kind fo
random number generator. I would thus like to use the com
;> library(snow)
>> RNGkind("L'Ecuyer-CMRG")
>> cl <- makeCluster(parallel::detectCores(), type="MPI")
> 4 slaves are spawned successfully. 0 failed.
>> .t <- snow::clusterSetupRNG(cl, seed=.Random.seed[2:7])
>> stopCluster(cl)
>
>
I updated to the latest CRAN versions of 'rlecuyer', 'Rmpi', and 'snow':
,[ sessionInfo() ]
| ...
| other attached packages:
| [1] rlecuyer_0.3-3 Rmpi_0.6-1 snow_0.3-10
| ...
`
But I still obtain:
,
| Error in .lec.SetPackageSeed(seed) :
| Seed[1] >= -1065242851, Seed i
Since clusterSetupRNG() calls clusterSetupRNGstream() and this calls
.lec.SetPackageSeed(), I could further minimalize the problem:
set.seed(1)
RNGkind("L'Ecuyer-CMRG") # => .Random.seed is of length 7 (first number encodes
the rng kind)
(seed <- .Random.seed[2:7]) # should give a valid seed for
Dear Hana,
Thanks for helping.
I am still wondering, why m1 (which should be 2^32-209 [see line 34 in
./src/RngStream.c]) is -767742437 in my case and why the minimal example you
gave was working for you but isn't for me.
Apart from that, ?.Random.seed -> "L'Ecuyer-CMRG" says:
,
| The 6 ele
Dear Daniel,
That's exactly what I also suspected (last post). The question now seems how to
correctly convert .Random.seed from signed to unsigned so that it is accepted by
the rlecuyer package.
Cheers,
Marius
__
R-help@r-project.org mailing list
ht
Thanks a lot, Duncan, that solved it!
Cheers,
Marius
Duncan Murdoch writes:
> On 13-01-24 2:09 AM, Marius Hofert wrote:
>> Dear Daniel,
>>
>> That's exactly what I also suspected (last post). The question now seems how
>> to
>> correctly convert .Rando
Dear expeRts,
I have a data.frame with certain covariate combinations ('group' and 'year')
and corresponding values:
set.seed(1)
x <- data.frame(group = c(rep("A", 4), rep("B", 3)),
year = c(2001, 2003, 2004, 2005,
2003, 2004, 2005),
tply, by=c("group", "year"), all=TRUE) # merge the two
data.frames
tply$num[is.na(tply$num)] <- 0
tply
Marius Hofert <> writes:
> Dear expeRts,
>
> I have a data.frame with certain covariate combinations ('group' and 'year')
>
Dear expeRts,
The question is rather simple: Why does aggregate (or similarly tapply()) not
keep the order of the grouping variable(s)?
Here is an example:
x <- data.frame(group = rep(LETTERS[1:2], each=10),
year = rep(rep(2001:2005, each=2), 2),
value = rep(1:1
>
> I'm no expeRt, but suppose that we change the setup slightly:
>
> xx <- x[sample(nrow(x)), ]
>
> Now what would you like
>
> aggregate(value ~ group + year, data=xx, FUN=function(z) z[1])
>
> to return?
>
> Personally, I prefer to have R return the same thing regardless
> of how the input da
Dear expeRts,
I would like to create a Q-Q plot including a Q-Q line for Gamma
distributed data.
The specialty is that it should be in log-log scale. For Q-Q line in
log-log scale,
I discovered the argument 'untf' of abline. As you can see in 2), this
works fine.
But for 3) it does not provide the
Hi,
I try to apply a function to subsets of a data.frame. tapply() does the job, but
the as output, I am looking for a vector (not an array/matrix) ordered in the
same way as the original data, so I can simply cbind the result to the original
data.frame. Below is a minimal example.
I know that th
Dear Bill,
Thanks a lot for your quick reply, that was exactly what I was looking for.
Cheers,
Marius
William Dunlap writes:
> Does ave() do what you want?
> y. <- ave(x$value, x$x1, x$x2, FUN=function(x)x)
>
> Bill Dunlap
> Spotfire, TIBCO Software
> wdunlap tibco.com
>
>
Hi,
What's the best approach to determine if a user uses an R version before 2.15.1
patched?
I know that the sessionInfo() command provides details, but I'm not sure how
the output of sessionInfo() is best used to determine R versions. This seems to
work, but a) there is certainly a better way and
Thanks, Berend, that works.
Cheers,
Marius
Berend Hasselman writes:
> On 22-09-2012, at 19:32, Marius Hofert wrote:
>
>> Hi,
>>
>> What's the best approach to determine if a user uses an R version before
>> 2.15.1
>> patched?
>> I know that
Dear grid expeRts,
I would like to create a layout with grid that looks like the following, but
with cells (1,1), (1,4), (4,1), and (4,4) removed and cells (2,1) and (3,1)
(and (4,2) and (4,3)) combined to one cell (so that contents can easily be
centered.
How can this be achieved?
requir
Bert Gunter writes:
> Inline below.
>
> On Sun, Sep 23, 2012 at 1:41 AM, Marius Hofert
> wrote:
>> Dear grid expeRts,
>>
>> I would like to create a layout with grid that looks like the following, but
>> with cells (1,1), (1,4), (4,1), and (4,4) removed and
Ahh, now I see what you mean... Thanks, that indeed works.
Cheers,
Marius
Marius Hofert writes:
> Bert Gunter writes:
>
>> Inline below.
>>
>> On Sun, Sep 23, 2012 at 1:41 AM, Marius Hofert
>> wrote:
>>> Dear grid expeRts,
>>>
>>>
Hi,
Why does the upper left panel (in the plot below) not have a gray background?
Cheers,
Marius
require(grid)
require(gridBase)
pdf(file="Rplot.pdf", width=8, height=8, onefile=FALSE)
## set up the grid layout
gl <- grid.layout(5, 5, widths=unit(c(1.8, 8, 0.8, 8, 0.8), "cm"),
par(plt=gridPLT())
## plot
par(new=TRUE) # always do this before each new 'graphics' plot
grid(col=1)
plot(1:10, 1:10, log="y", xlab="", ylab="",
xaxt=if(i==2) "s" else "n", yaxt=if(j==1) &q
Embedded Controllers) .OO#. .OO#. rocks...1k
> ---
> Sent from my phone. Please excuse my brevity.
>
> Marius Hofert wrote:
>
>>Dear Paul,
>>
>>Thank you for helping. T
frame.plot=FALSE, xaxt="n", yaxt="n")
grid(col="white", lty="solid", lwd=1.6, equilogs=FALSE) # background
grid
upViewport()
}
}
par(par.)
dev.off()
Paul Murrell writes:
> Hi
>
> On 24/09/12 18:06, Marius Hofert wrote:
="n", yaxt="n")
grid(col="white", lty="solid", lwd=1.6, equilogs=FALSE) # background
grid
upViewport()
}
}
par(par.)
dev.off()
Paul Murrell writes:
> Hi
>
> On 25/09/12 11:50, Marius Hofert wrote:
>> Dear Paul,
>>
>
Dear Paul,
Many thanks, that solved it.
Cheers,
Marius
Paul Murrell writes:
> Hi
>
> On 25/09/2012 6:10 p.m., Marius Hofert wrote:
>> Dear Paul,
>>
>> Thanks. Redrawing the points solves it for the minimal example, but
>> what happens if you have plot(..,
Dear grid-expeRts,
The goal:
I would like to construct a plot (matrix) with grid and gridBase,
which consists of four "sub-plots". The sub-plots should have a square plotting
region as one would force with par(pty="s") in base graphics.
The problem:
I don't get a square plotting region, not eve
In the meanwhile, I found a more minimal example which shows the problem (just
change 'inch' to TRUE to see the difference):
require(grid)
inch <- FALSE # TRUE
d <- if(inch) 5 else 1
pspc <- d*c(0.3, 0.3) # width, height of panels
spc <- d*c(0.05, 0.05) # width, height of space
axlabspc <- d*c(
Please note:
1) your example is not working in the way you provided it (see
http://www.minimalbeispiel.de/mini-en.html)
2) you receive a warning, not an error
3) I'd try and debug qua.regressCOP2 to see why the warning appears
4) in case 3) does not help, contact the maintainer of copBasic (Willia
ith the diagram.
> If you change your grid.show.layout() call to the following (which "removes"
> the
> normal margin used by grid.show.layout()) ...
>
> grid.show.layout(gl, vp=viewport(width=1.25, height=1.25))
>
> ... then you should find your viewports line up with
Hi,
If I use invisible(Sys.setlocale("LC_COLLATE", "C")) in ~/.Rprofile, then
> sort(c("L.Y", "Lu", "L.Q"))
[1] "L.Q" "L.Y" "Lu"
whereas using invisible(Sys.setlocale("LC_COLLATE", "en_US.UTF-8")) results in
> sort(c("L.Y", "Lu", "L.Q"))
[1] "L.Q" "Lu" "L.Y"
I know this issue has appeared alr
Hi,
Thanks for you help. I use R-devel under Ubuntu 14.04, here is the output of
sessionInfo():
> sessionInfo()
R Under development (unstable) (2014-06-02 r65832)
Platform: x86_64-unknown-linux-gnu (64-bit)
locale:
[1] LC_CTYPE=en_US.UTF-8 LC_NUMERIC=C
[3] LC_TIME=en_US.UTF-8LC_C
Hi,
... so something like this? [in foo.R]
old.coll <- Sys.getlocale("LC_COLLATE")
Sys.setlocale("LC_COLLATE", locale="C")
Sys.setlocale("LC_COLLATE", locale=old.coll)
Cheers,
Marius
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https://stat.ethz.ch/mailman/
Dear expeRts,
What's a 'good' (nice-looking, easy-to-read) setup for the LaTeX package
'listings' to display R code?
The two versions below are partly inspired by the settings of the package
SweaveListingUtils and
http://r.789695.n4.nabble.com/R-How-to-format-R-code-in-LaTex-documents-td816055.ht
ell
> wrote:
>> The knitr package makes this relatively easy to do. See for example
>> http://biostat.mc.vanderbilt.edu/KnitrHowto
>>
>> Frank
>>
>>
>> Marius Hofert-3 wrote
>>> Dear expeRts,
>>>
>>> What's a 'good
Dear expeRts,
I'm trying to use the package SweaveListingUtils, but the rather minimal example
below leads to
,
| ./minimal.tex:43: Undefined control sequence.
| l.43 \lstdefinelanguage
|{Rd}[common]{TeX}%
| ?
`
Why?
Cheers,
Marius
\documentclass[article]{jss}
Dear expeRts,
I would like to download a time series of historical data from the ticker with
symbol "ROG.VX". Interestingly, I obtain constant values (138.3 for each day in
the chosen period) although the yahoo.finance website tells me that the time
series is not at all constant. What's wrong?
gt; On Fri, 23 Nov 2012, Marius Hofert wrote:
>
>> Dear expeRts,
>>
>> I would like to download a time series of historical data from the ticker
>> with
>> symbol "ROG.VX". Interestingly, I obtain constant values (138.3 for each day
>> in the chosen p
Dear expeRts,
I have two matrices A and B. They have the same number of columns but possibly
different number of rows. I would like to compare each row of A with each row
of B and check whether all entries in a row of A are less than or equal to all
entries in a row of B. Here is a minimal work
Dear expeRts,
If I specify group = as.factor(rep(1:2, each=n)) in the below
definition of dat, I get the expected behavior I am looking for. I
wonder why I
don't get it if group is *not* a factor... My guess was that,
internally, factors are treated as natural numbers (and this indeed
seems to be
Dear Bert,
Thanks for helping.
Your questions 'answers' why I get the expected behavior if
'group' is a factor. My question was why I don't get the expected
behavior if 'group' is not a factor.
>From a theoretical (non-programming) point of view, there is no
difference in a factor with two level
Dear expeRts,
shouldn't this...
x <- 1:10
myplot <- xyplot(x~x,col="red")
trellis.device(postscript,color=FALSE,file="plot.ps")
print(myplot)
dev.off()
... give a black/white plot?
Cheers,
Marius
__
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https://stat.eth
Dear expeRts,
I would like to call a function f from a function g with or without an
argument.
I use missing() to check if the argument is given. If it is not given, can I
set
it to anything such that the following function call (to f) behaves as if the
argument
isn't given? It's probably bes
Ahh, thank you very much, precisely what I was looking for :-)))
Cheers,
Marius
On 2010-11-13, at 12:41 , Duncan Murdoch wrote:
> Marius Hofert wrote:
>> Dear expeRts,
>> I would like to call a function f from a function g with or without an
>> argument. I use miss
Dear expeRts,
I would like to use expression() for creating labels in a splom, as shown in
the
first minimal example below. Is there any way I can simplify having to write
"expression(italic(...))" several times?
The second example is what I tried so far, but I can't manage to get italic() to
w
Dear expeRts,
I am not sure if I found a bug...
I would like to create a function that itself creates a lattice plot without
colors. Following
http://www.mail-archive.com/r-help@r-project.org/msg64699.html
I use trellis.device() to set the colors to FALSE. Whenever I call the minimal
example bel
ht thing which I would if I used the "col = 1" options in
the call of xyplot
Cheers,
Marius
On 2010-11-27, at 02:38 , David Winsemius wrote:
>
> On Nov 26, 2010, at 6:35 PM, Marius Hofert wrote:
>
>> Dear expeRts,
>>
>> I am not sure if I found a bug...
>
plot.(U)
b
... but it didn't work :-(
Cheers,
Marius
On 2010-11-27, at 12:00 , ottorino wrote:
> Il giorno sab, 27/11/2010 alle 00.35 +0100, Marius Hofert ha scritto:
>> The reason why I would like to use trellis.device() within a function
>> is that
>> the plo
Thanks very much, exactly what I was looking for :-)))
Cheers,
Marius
On 2010-11-27, at 13:16 , Peter Ehlers wrote:
> On 2010-11-27 03:31, Marius Hofert wrote:
>> Hi,
>>
>> I get a warning () using
>>
>> xyplot.<- function(u) {
>> BW.theme<-
Dear expeRts,
below is a minimal example from the thread
http://www.mail-archive.com/r-help@r-project.org/msg48098.html
about how to remove the outer box / frame of a wireframe plot.
As one can see, the suggested code does remove the box (by making it
transparent),
however, it also removes the
okay, solved :-))
It is mentioned here:
http://r.789695.n4.nabble.com/How-to-remove-outer-box-from-Wireframe-plots-td824819.html
so ...
wireframe(z ~ x*y, data = test, scales = list(col = "black", arrows = FALSE),
par.settings = list(axis.line = list(col = "transparent")))
... solves it.
Cheer
col="transparent"),
clip=list(panel="off")))
Cheers,
Marius
On 2010-11-27, at 13:16 , Peter Ehlers wrote:
> On 2010-11-27 03:31, Marius Hofert wrote:
>> Hi,
>>
>> I get a warning () using
>>
>> xyplot.<- function(u) {
Dear Peter,
thanks a lot, modifyList() did it perfectly!
Cheers,
Marius
On 2010-11-28, at 01:26 , Peter Ehlers wrote:
> On 2010-11-27 15:03, Marius Hofert wrote:
>> Dear Peter,
>>
>> do you know anything similar for a cloud() plot?
>> This does not work:
&
Dear expeRts,
I am struggling with warning/error handling.
I would like to call a function which can produce either
a) normal output
b) a warning
c) an error
Since the function is called several (thousand) times in a loop, I would like
to proceed "quietly" and collect the warnings and errors
On 2010-12-06, at 01:07 , David Winsemius wrote:
>
> On Dec 5, 2010, at 3:13 PM, Marius Hofert wrote:
>
>> Dear expeRts,
>>
>> I am struggling with warning/error handling.
>>
>> I would like to call a function which can produce either
>> a)
Hmm... still not quite what I was hoping for... but thanks anyway.
I would like to have the output in the following form:
> f(1)
$result
[1] 0
$warning
[1] NULL # or ""
$error
[1] NULL # or ""
> f(-1)
$result
[1] NaN
$warning
[1] "Warning in log(-1) : NaNs produced" # or something similar
$
Dear Mario,
I tried "-n 4" and obtain the same error :-(
Cheers,
Marius
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commente
Hi,
I found the thread
http://r.789695.n4.nabble.com/Matrix-as-input-to-xyplot-lattice-proper-extended-formula-syntax-td896948.html
I used Gabor's approach and then tried to assign the plot to a variable (see
below). But a Quartz device is opened... why? I don't want to have anything
plot/pri
Dear expeRts,
I somehow don't see why the following does not work:
integrand <- function(x, vec, mat, val) 1 # dummy return value
A <- matrix(runif(16), ncol = 4)
u <- c(0.4, 0.1, 0.2, 0.3)
integrand(0.3, u, A, 4)
integrate(integrand, lower = 0, upper = 1, vec = u, mat = A, val = 4)
I would like
Ahh... thanks, I totally missed that.
Cheers,
Marius
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and provide commented, minimal, self-con
Dear expeRts,
how can I decrease the space between the tick marks and the corresponding
labels in an splom?
See here:
library(lattice)
U <- matrix(runif(4000), ncol = 8)
splom(U, axis.text.cex = 0.2) # => space between the [small] tick labels and
tick marks is/seems to be too large
I checked ?
what I am looking for.
Cheers,
Marius
On 2010-12-26, at 14:36 , David Winsemius wrote:
>
> On Dec 26, 2010, at 5:41 AM, Marius Hofert wrote:
>
>> Dear expeRts,
>>
>> how can I decrease the space between the tick marks and the corresponding
>> labels in
Dear Peter,
thank you very much, *precisely* what I was looking for!
Cheers,
Marius
On 2010-12-27, at 02:27 , Peter Ehlers wrote:
> On 2010-12-26 08:26, Marius Hofert wrote:
>> Dear David,
>>
>> thank you for your answer.
>> As I wrote, I am looking for an o
Dear expeRts,
I use foreach to do parallel computations. Is it possible to have some progress
output written while the computations are done? In the minimal example below, I
just print a number ("n") to check the progress. If you run this example with
"%do%" instead of "%dopar%", then the compu
Hi,
how can I create an array of lists of three components?
This approach does not work:
n1 <- 2
n2 <- 4
n3 <- 5
res <- array(rep(vector("list",3), n1*n2*n3), dim = c(n1,n2,n3))
res[1,1,1] # is not a list with three components...
The goal is that res[1,1,1] is a list with three components. Also,
L)), n1*n2*n3), dim = c(n1,n2,n3))
>> res[1,1,1] # is not a list with three components...
> [[1]]
> [[1]][[1]]
> NULL
>
> [[1]][[2]]
> NULL
>
> [[1]][[3]]
> NULL
>
>
>> str(res)
> List of 40
> $ :List of 3
> ..$ : NULL
> ..$ : NULL
&g
Dear Gabor,
*perfect*, precisely what I was looking for.
Many thanks,
Marius
On 2010-12-29, at 23:19 , Gabor Grothendieck wrote:
> On Wed, Dec 29, 2010 at 4:58 PM, Marius Hofert wrote:
>> Dear Jim,
>>
>> thanks for your quick response. Here is what I try to ac
Dear (T)eXpeRts,
I try to create a LaTeX table from an R matrix for the first time. I am not
sure what the "best" approach is, I just read about latex() from Hmisc
(toLatex() didn't work).
Consider the following minimal example:
library(Hmisc)
mat <- matrix(c(1,NA,3,100,1,4), ncol = 3, byr
Hi,
why does format(1, big.mark = "\\,") not give me "10\,000"? How can I get
this kind of "big.mark"?
Cheers,
Marius
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to have
"10\,000" is for use in LaTeX. If I produce the format "10\\,000" in a table,
then xtable gives me 10$\backslash$,000 for the corresponding cell entry, which
is wrong :-(. Do you know a trick for that?
Cheers,
Marius
>
>
> Uwe Ligges
>
>
>
>
Ahhh, great!
I knew it will be correct if the output is directed to a file, but I wanted it
for the console [which is perfectly solved by cat()].
Thanks, Uwe.
Cheers,
Marius
On 2010-12-30, at 19:55 , Uwe Ligges wrote:
>
>
> On 30.12.2010 19:53, Marius Hofert wrote:
&g
us
On 2010-12-30, at 21:29 , John Kane wrote:
> Have a look at xtable.
>
> --- On Thu, 12/30/10, Marius Hofert wrote:
>
>> From: Marius Hofert
>> Subject: [R] latex() etc.: How to nicely format a matrix for a LaTeX
>> document?
>> To: "Help R"
>&g
Dear expeRts,
As you can see from this example...
trellis.device("pdf", width = 5, height = 5)
print(xyplot(0 ~ 0, main = "This title is not 'centered' for the human's
eye", scales = list(alternating = c(1,1), tck = c(1,0
dev.off()
... the title does not seem to be "centered" for the huma
Dear expeRts,
I usually use par.settings = standard.theme(color = FALSE) to create lattice
graphics
without colors, so something like
library(lattice)
x <- runif(10)
xyplot(x ~ 1:10, type = "l", par.settings = standard.theme(color = FALSE))
Now I would like to use an additional component in par
Dear David,
this I already tried. But as you can see, the plot itself *is* colored.
However, I want to have color = FALSE, so, unfortunately, this approach does
not work...
Cheers,
Marius
On 2011-01-04, at 14:32 , David Winsemius wrote:
>
> On Jan 4, 2011, at 5:57 AM, Marius Hofert
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