Hi, I found the thread http://r.789695.n4.nabble.com/Matrix-as-input-to-xyplot-lattice-proper-extended-formula-syntax-td896948.html I used Gabor's approach and then tried to assign the plot to a variable (see below). But a Quartz device is opened... why? I don't want to have anything plot/printed, I just would like to store the plot object. Is there something like "plot = FALSE"?
Cheers, Marius library(lattice) library(zoo) df <- data.frame(y = matrix(rnorm(24), nrow = 6), x = 1:6) xyplot(zoo(df[1:4], df$x), type = "p") plot.object <- xyplot(zoo(df[1:4], df$x), type = "p") # problem: a Quartz device is opened (on Mac OS X 10.6) ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
