Hi,
I am looking for a way to fit data (vector of values) to a density function
using an optimization (ordinary least squares or maximum likelihood fit).
For example if I have a vector of 100 values generated with rnorm:
rnorm(n=100,mean=500,sd=50)
How can I fit these data to a Gaussian density
ion:
>
> library(MASS)
> ?fitdistr
>
> No optimization is needed to fit a normal distribution, though.
>
>
> On 21/03/2015 13:05, Johannes Radinger wrote:
>
>> Hi,
>>
>> I am looking for a way to fit data (vector of values) to a density
>> functi
On Sat, Mar 21, 2015 at 3:41 PM, Prof Brian Ripley
wrote:
> On 21/03/2015 14:27, Johannes Radinger wrote:
>
>> Thanks for the fast response. The fitdistr() function works well for the
>> predefined density functions. However, what is the recommended approach
>> to optimiz
Hi,
I'd like to match the beginning and the end of a string. E.g. I want to
extract all strings from a vector that beginn with "12" and end with
"Apples":
a <- "2 green Apples"
b <- "12 green Apples"
c <- "12 Apples and 2 green Bananas"
d <- "12 yellow Bananas"
fruitlist <- c(a,b,c,d)
# This is
Hi,
I'd like to arrange two wireframe plots (library "lattice") next to each
other using the grid.arrange function of the library "gridExtra". However
the two wireframe plots should be closer to each other and the outer 2D box
should be removed (to save space).
To remove the outer box for a single
Dear R-User!
This is a question to all of you that are familiar with the 'dismo'
package, in particular we are interested in the gbm.step() function to
create a boosted regression tree model in R. From the model output object we
can use the $cv.statistics to get information on the cross-validation
Hi
I'd like to remove a leading "3" if my number is 7 digits long, if it is
only 6 I don't want to anything.
I think this should be possible with a 1-liner using sub() but I am not
sure how to define the number of characters following the leading one.
For example my vector:
a <- c(3593857,384723
Hi,
I have a dataframe containing 3 columns:
data.frame(X=c(100,102,104,102,103),Y=c(12,14,14,13,16),Time=c(1,2,3,4,5))
where X and Y are coordinates and "Time" refers to an index of a timestep.
Now I would like to get the distance between the consecutive timesteps.
This should actually provide
Hi Ray,
thank you very much. That one-line approach is what I was looking for.
A very simple but very efficient way without loading any other packages.
/j
On Tue, Dec 18, 2012 at 11:17 AM, Ray Brownrigg
wrote:
> On 18/12/2012 10:56 p.m., Johannes Radinger wrote:
>>
>> Hi,
Hi,
I'd like to merge mutliple dataframes from a list of dataframes by some common
columns. The approach for simply merging 2 dataframes is working with:
merge(df1,df2,by=c("col1","col2","col3"),all=TRUE)
For mutliple dataframes in a list I try to use the merge_all command
from the package resha
.x=TRUE, all.y=TRUE)
>
>
> Contact the package maintainer for more info.
>
> maintainer('reshape')
> [1] "Hadley Wickham "
>
>
> Hope this helps,
>
> Rui Barradas
>
> Em 11-01-2013 10:08, Johannes Radinger escreveu:
>>
>> Hi,
>>
Hi,
I would like to split dataframe based on one colum and want
to connect the two dataframes by rows (like rbind). Here a small example:
# The orgininal dataframe
df1 <- data.frame(col1 = c("A","A","B","B"),col2 = c(1:4), col3 = c(1:4))
# The datafame how it could look like
df2 <- data.frame(A.
Hi,
I am running an ANCOVA model like:
aov(Y ~ Var1 + Var2 + Var3 + Var4 + CoVar1 + CoVar2)
where Y is the response (metric, 1.0-1000.0), VarX are all
metric predictors, and CoVarX are two Covariates each a
factor of 4-5 levels.
So far as I can remember results of an ANCOVA for a Covariate
of i
Hi,
is there a way to color the branches or text label of the branches of
dendrograms e.g. from hclust() according to a grouping variable. Here
I have something in mind like:
http://www.sigmaaldrich.com/content/dam/sigma-aldrich/life-science/biowire/biowire-fall-2010/proteome-figure-1.Par.0001.Ima
Hi,
I have a vector of strings like:
c("a1b1","a2b2","a1b2") which I want to spilt into two parts like:
c("a1","a2","a2") and c("b1","b2,"b2"). So there is
always a first part with a+number and a second part with b+number.
Unfortunately there is no separator I could use to directly split
the vecto
x
> [1] "a1b1" "a2b2" "a1b2"
>> substr(x, 1, 2)
> [1] "a1" "a2" "a1"
>> substr(x, 3, 4)
> [1] "b1" "b2" "b2"
>
> HTH,
> Jorge.-
>
>
> On Wed, Mar 13, 2013 at 7:37 PM, Johann
Hi,
I just discovered the package "sets" and its ability to perform fuzzy
systems calculations.
The example in the manual of fuzzyinference() gives an overview how to
develop rules.
However my "rules" are already available as data.frame and I'd like to
convert them into the format
that is needed
Following my last mail, I found a simple solution using eval(parse)):
df <-
data.frame(depth=c("low","medium","high"),velocity=c("medium","medium","low"),suitability=c("low","medium","low"))
df$rule <- paste("fuzzy_rule(depth %is% ",df[,"depth"]," && ","velocity
%is% ",df[,"velocity"],", ","suitab
Hi,
I am trying to use the fuzzy_inference system on multiple input values.
Basically I combine two variables (depth, velocity) into the variable
suitability.
Both depth and velocity have 3 trapezoid classes (verylow,medium,high) each.
The consequent (suitability) has 4 fuzzy levels (none,low,medi
iverse to [0,1], so the fuzzy inference
> returns empty sets for those entries in your df with values larger than 1
> ...
>
> David
>
>
> On 2013-05-08 14:53, Johannes Radinger wrote:
>
>> This email has already been sent to the R-mailing list,
>> but maybe y
Hi,
I'd like to get mean values for the margins of my casted data.frame.
For the casting I am using dcast() from reshape2. However, when I set
the margins parameter (margins=c("grand\_row")) I get following error
concerning
an unrecognized escape character '\_'. So what is the correct command
to
Hi,
I am trying to calculated various summary statistics using the dcast
function
of reshape2. This works perfectly for getting the mean, sum, length, sd. But
when I want to calculate the median I get an error. I tried it with and
without removing
NAs:
my_median <- function(x) median(x, na.rm =
Hi,
I am using colsplit (package = reshape) to split all strings
in a column according to the same patterns. Here
an example:
library(reshape2)
df1 <- data.frame(x=c("str1_name2", "str3_name5"))
df2 <- data.frame(df1, colsplit(df1$x, pattern = "_", names=c("str","name")))
This is nearly what I
Thank you,
this works perfectly...
best regards,
Johannes
On Thu, Sep 27, 2012 at 1:43 PM, Ista Zahn wrote:
> Hi Johannes,
>
> On Thu, Sep 27, 2012 at 7:25 AM, Johannes Radinger
> wrote:
>> Hi,
>>
>> I am using colsplit (package = reshape) to split all strings
&
Hi,
I have a dataframe with multiple (appr. 20) columns containing
vectors of different values (different distributions).
Now I'd like to create a crosstable
where I compare the distribution of each vector (df-column) with
each other. For the comparison I want to use the ks.test().
The result sho
Y=runif(n), Z=rchisq(n, df=3))
>
> apply(dat, 2, function(x) apply(dat, 2, function(y) f(x, y)))
>
> Hope this helps,
>
> Rui Barradas
> Em 28-09-2012 11:10, Johannes Radinger escreveu:
>>
>> Hi,
>>
>> I have a dataframe with multiple (appr. 20) columns co
Hi,
I'd like to cut a hierachical cluster tree calculated with hclust at a
specific height.
However ever get following error message:
"Error in cutree(hc, h = 60) :
the 'height' component of 'tree' is not sorted (increasingly)"
Here is a working example to show that when specifing a height in
ven height is only possible for ultrametric trees
> (with monotone clustering heights)."
>
> Use a different method (but not median).
>
> -
> David L Carlson
> Department of Anthropology
> Texas A&M University
> College Station, TX 77840-4352
>
> -Original
y the resulting dendrograms can
> have so called inversions (which are hard to interpret)."
>
> The cutree manual page:
>
> "Cutting trees at a given height is only possible for ultrametric trees
> (with monotone clustering heights)."
>
> Use a different method
Hi,
I am wondering if it is possible to set the path to the output file of the
function
BIOMOD_Modeling() from the 'Biomod2' package. I can see the option
SaveObj to state if the output should be save to the hard disk. When this is
enabled, all files are printed to the working directory. So is Bio
Hi,
I've got a dataframe having a code as column name.
Addtionally I have another dataframe with a two columns (and lots of
rows), the first
containing the code and the second some Text (real name).
Now I'd like to use the information (pairs of code and name) of the
second dataframe to rename all
A","Col
> B","Col D","Col E","Col C"))
>
> names(df)<-df_names$name[match(names(df),df_names$code)]
>
>
> A.K.
>
> - Original Message -
> From: Johannes Radinger
> To: r-help@r-project.org
> Cc:
> Sent: Tue
Hi,
I have data in a dataframe in following structure
var1 <- c("a","b","c","a","b","c","a","b","c")
var2 <- c("X","X","X","Y","Y","Y","Z","Z","Z")
var3 <- c(1,2,2,5,2,6,7,4,4)
df <- data.frame(var1,var2,var3)
Now I'd like to calculate relative values of var3. This values
should be relative to th
Hi,
I'd like to use Latin Hypercube Sampling (LHC) in the the context of
uncertainty / sensitivity analysis of a complex model with approximately 10
input variables. With the LHC approach I'd like to generate parameter
combinations for my model input variables.
Therefore I came across an simple ex
Hi,
I'd like to follow up an older discussion on adding significance stars to
boxplots.
(
http://r.789695.n4.nabble.com/indicating-significant-differences-in-boxplots-td862335.html
)
As suggested by Jim Lemon, there is following solution for a single boxplot:
boxplot(count ~ spray, data = InsectS
Hi,
I'd like to plot a boxplot and use a scatter.smooth line plot as an overlay
for this plot.
This works except for the problem that the x-axis ticks for both plots are
differently spaced:
The boxplot ticks are closer and the space between the outer most boxplots
and the plot region (box) is larg
n Tue, Nov 19, 2013 at 4:43 AM, Johannes Radinger <
> johannesradin...@gmail.com> wrote:
>
>> Hi,
>>
>> I'd like to plot a boxplot and use a scatter.smooth line plot as an
>> overlay
>> for this plot.
>> This works except for the problem that
Hi,
I found follwowing example of pnorm here:
http://www.r-tutor.com/elementary-statistics/probability-distributions/normal-distribution
Problem
Assume that the test scores of a college entrance exam fits a normal
distribution. Furthermore, the mean test score is 72, and the standard
deviat
gt; Feladó: r-help-boun...@r-project.org [r-help-boun...@r-project.org] ;
> meghatalmazó: Johannes Radinger [johannesradin...@gmail.com]
> Küldve: 2013. december 12. 14:56
> To: R help
> Tárgy: [R] Solving a normal distribution pnorm for q
>
> Hi,
>
>
>
> I found follwowin
ion(x)pnorm(q=x,sd=sd1)*r+pnorm(q=x,sd=sd2)*(1-r)-X,c(-1e6,1e6))
>
>
> Cheers
>
> Am 12.12.2013 15:58, schrieb Johannes Radinger:
> > Thanks for the fast response. Of course I totally overlooked qnorm as I
> had
> > a more complex task in my head.
> >
> > I
:00 +0200
From: "Johannes Radinger"
To: r-help@r-project.org
Subject: [R] Regression with ranges and displaying them in an XY-Plot
Message-ID: <20110728124900.198...@gmx.net>
Content-Type: text/plain; charset="utf-8"
Hello UseRs,
I've got 3 variables, the dependent variab
Hello,
I'd like to perform a regression using MCMCregress (MCMCpack).
One variable therefore should be a function rather than a variable:
I want to use X as an input and X should be defined as a random number between
to values. Therefore I want to use the function runif like:
X <-(1, Xa, Xb) but
inal-Nachricht
> Datum: Wed, 10 Aug 2011 08:19:07 -0500
> Von: Jean V Adams
> An: "Johannes Radinger"
> CC: r-help@r-project.org
> Betreff: Re: [R] function runif in for loop
> Johannes,
>
> You have the loop set up right, you just need to add indexing to
Original-Nachricht
> Datum: Wed, 10 Aug 2011 09:38:38 -0400
> Von: Duncan Murdoch
> An: Johannes Radinger
> CC: r-help@r-project.org
> Betreff: Re: [R] function runif in for loop
> On 10/08/2011 7:28 AM, Johannes Radinger wrote:
> > Hello,
>
Hello,
just to follow up a question from last week. Here what I've done so far (here
an example):
library(MCMCpack)
Y=c(15,14,23,18,19,9,19,13)
X1=c(0.2,0.6,0.45,0.27,0.6,0.14,0.1,0.52)
X2a=c(17,22,21,18,19,25,8,19)
X2b=c(22,22,29,34,19,26,17,22)
X2 <- function()runif(length(X2a), X2a, X2b)
is not working
/johannes
Original-Nachricht
Datum: Mon, 15 Aug 2011 10:20:53 +0200
Von: "Johannes Radinger"
An: r-help@r-project.org
Betreff: MCMC regress, using runif()
Hello,
just to follow up a question from last week. Here what I've done so far
1000 model runs?
Thank you very much
/johannes
Original-Nachricht
> Datum: Mon, 15 Aug 2011 08:33:52 -0300
> Von: Alexandre Camargo Martensen
> An: Johannes Radinger
> Betreff: Re: [R-sig-eco] Extracting information from lm results
> Hi Johannes,
>
Hello,
I've a question concerning the display of interval data.
A sample dataset where X is an interval between Xa and Xb
which should be displayed:
Y=c(15,14,23,18,19,9,19,13)
Xa=c(17,22,21,18,19,25,8,19)
Xb=c(22,22,29,34,19,26,17,22)
X = (Xa+Xb)/2
It's easily possible to plot the mean of the
Hello,
I am a beginner with ggplot and after doing simple graphs (histogram, segments
etc.)
some questions came up:
1) I tried to do a histogram, but nothing is displayed although it works with
another vector.
I think it is because of the very small values (n=1000, min=1.222e-24 max,
1.890e-20
Hello,
I import a xlsx-table with read.xlx which contains NAs in 4 columns. In the
excel table these 4 columns contain floats/integers and the word NA. But when I
am importing the NAs are recognized as strings rather than as missing values.
How can I set that if a cell contains the word NA tha
Hello UseRs,
I've somehow general questions.
I've got a dataset which shows signs of heteroscedasticity and non-normality in
errors if I do a normal linear regression of the form Y~X. So to things came
into my mind, either transforming the variables (log or log10) or using robust
regression. So
Hello,
I've some questions concerning log-transformations and plotting of the
regression lines. So far as I know is it a problem to log-transform values
smaller than 1 (0-1). In my statistics lecture I was told to do a log(x+1)
transformation in such cases. So I provide here a small example to
Hello,
I am using cbind in a lm-model. For standard lm-models
the r.squared can be easily extracted with summary(model)$r.squared,
but that is not working in in the case with cbind.
Here an example to illustrate the problem:
a <- c(1,3,5,2,5,3,1,6,7,2,3,2,6)
b <- c(12,15,18,10,18,22,9,7,9,23,12,
Hi,
I am looking for a very easy way to transform
a column in a dataframe from counts (eg. c(1,0,21,2,0,0,234,2,0))
into a binary form to get presence/absence values
e.g. c(1,0,1,1,0,0,1,1,0). Is there a simple built-in function?
or do I have do to it with a replaceement funciton using IF x > 0
TH
Original-Nachricht
> Datum: Thu, 31 May 2012 11:16:32 +
> Von: "ONKELINX, Thierry"
> An: Johannes Radinger , "R-help@r-project.org"
>
> Betreff: RE: [R] Transform counts into presence/absence
> Just use the logical operators.
Hi,
I have a dataframe and want to remove columns from it
that are populated with a similar value (for the total
column) (the variation of that column is 0). Is there an
easier way than to calculate the statistics and then
remove them by hand?
A <- runif(100)
B <- rep(1,100)
C <- rep(2.42,100)
D
exept for column with name "B".
I have to think about this
/Johannes
Original-Nachricht
> Datum: Thu, 31 May 2012 09:20:27 -0500
> Von: J Toll
> An: Johannes Radinger
> CC: R-help@r-project.org
> Betreff: Re: [R] Remove columns from dataframe based on their
Hi,
I have a dataframe with around 100 columns. Now I want
to redefine some of the columns as factors (using as.factor).
Luckily all the names of the columns I want to redefine start with
"crast". Thus I thought I can use grep() for that purpose...
...I found an example for redefining a single co
Hi,
I have a 1-column dataframe with rownames and I want to sort it
based on the single column. The typical procedure that is recommended
in diverse posts is to use order in the index. But that "destroys" my
dataframe structure. Probabaly it is a very simple solution. Here is a
short reproducable
Hi Achim,
thank you for your good explanation and the solution to my
question...
cheers,
/j
Original-Nachricht
> Datum: Fri, 8 Jun 2012 09:30:42 +0200 (CEST)
> Von: Achim Zeileis
> An: Johannes Radinger
> CC: R-help@r-project.org
> Betreff: Re: [R] Sort 1-c
Hi,
I've kind of a tricky question, which I don't know how to solve yet:
I get multiple dataframes loaded (readRDS) in a loop function. Each loaded
dataframe contains two columns one with a var-name and one with a value. The
rownumber (order) is very important as it is a value of the rank (1:x
Hello R-people!
I have a general statistical question about regressions. I just want
to describe my case:
I have got a dataset of around 150 observations and 1 dependent and 2
independent variables.
The dependent variable is of metric nature (in my case meters in a
range from around 0.5-1
try such a
service, for example:
http://stackoverflow.com/
FWIW, this is an example of censoring in regression. R has packages
for this, but you need to learn more or get help to use them properly,
as you, yourself, indicated.
-- Bert
On Sun, Jul 17, 2011 at 3:01 AM, Johannes Radinger
wrote
Hello UseRs,
I've got 3 variables, the dependent variable Y as well as a max and a min value
of the independent variable (Xa and Xb) where in some cases Xa=Xb (so actually
a single value for X).
First I'd like to perform a regression, but my problem is that my X is a range
(acutally a censored
Hi,
I just recently changed my OS to Ubuntu 12.04 (32bit). Now I tried to install
some packages required by my old and working scripts. Unfortunately I fail when
trying to install the package "xslx". Maybe it is related to the 32bit version
of my R (its not possible to install a 64 bit version)
ew packages are not available for
> it. Please do as the posting guide suggests and update to R 2.15.1 (or
> R-patched).
>
>
> On 25/07/2012 09:47, Johannes Radinger wrote:
> > Hi,
> >
> > I just recently changed my OS to Ubuntu 12.04 (32bit). Now I tried to
> insta
Hi,
I used to use reshape and moved to reshape2 (R 2.15.1). Now I tried some of my
older scripts and was surprised that my cast function wasn't working like
before.
What I did/want to do:
1) Melt a dataframe based on a vector specifying column names as measure.vars.
Thats working so far:
dfm <-
Hello,
I am using a grid.layout for combining multiple ggplot-plots.
So far I am doing it this way to get a pdf/eps:
pdf("/path/to/my/file.pdf") #or postscript("/path/to/my/file.eps")
grid.newpage()
pushViewport(viewport(layout = grid.layout(nrow=2, ncol=2,
widths = unit(c
Hello,
I created several plot with ggplot2 dev mode.
Now I want to combine the plots in a grid
e.g. 2x2 with a fixed size of the output.
What I am doing at the moment is:
grid.newpage()
pushViewport(viewport(layout = grid.layout(nrow=2, ncol=2,
widths = unit(c(7.5,6.5),
Hello,
I have got a dataframe which looks like:
y <- c(1,5,6,2,5,10) # response
x <- c(2,12,8,1,16,17) # predictor
group <- factor(c(1,2,2,3,4,4)) # group
df <- data.frame(y,x,group)
Now I'd like to resample that dataset.
I want to get dataset (row)
per group. So per total sample I get 4 rows
i
Hello,
I think I am not to far from a solution. I want to do lm regressions with
several variables which I define before in a list. What I've done so far is
like:
y <- c(1,5,6,2,5,10) # response
x1 <- c(2,12,8,1,16,17) # predictor
x2 <- c(2,14,5,1,17,17)
df <- data.frame(y,x1,x2)
predictorlist
Hi,
Original-Nachricht
> Datum: Mon, 21 Nov 2011 14:46:17 +0100
> Von: Uwe Ligges
> An: Johannes Radinger
> CC: r-help@r-project.org
> Betreff: Re: [R] lm and loop over variables
>
>
> On 21.11.2011 13:34, Johannes Radinger wrote:
> > Hello,
&
Hello,
I want to arrange a pairs-plot and a simple boxplot next to each other.
A similar problem was already posted here:
http://r.789695.n4.nabble.com/combining-pairs-plot-with-other-plots-in-one-output-td3946235.html
but still I don't really know how to do it...
Here a some code lines for the s
Hello,
assume we have following dataframe:
group <-c(rep("A",5),rep("B",6),rep("C",4))
x <- c(runif(5,1,5),runif(6,1,10),runif(4,2,15))
df <- data.frame(group,x)
Now I want to select all cases (rows) for those groups
which have more or equal 5 cases (so I want to select
all cases of group A and
Hello,
I'd like to add custom labels to my pair() plot. These
labels include math expression but they aren't correctly
displayed...
Further, I want that the boxes for the text.panel (diagonal)
have an other background color (grey80). Is that generally
possible? If yes how do I have to set it?
W
t; Datum: Thu, 24 Nov 2011 09:12:57 -0500
> Von: Gabor Grothendieck
> An: Johannes Radinger
> CC: r-help@r-project.org
> Betreff: Re: [R] dataframe indexing by number of cases per group
> On Thu, Nov 24, 2011 at 7:02 AM, Johannes Radinger
> wrote:
> > Hello,
> >
&g
Hi,
I just started with writing functions in R and so some questions popped up.
I provide some values as argument to my function such as:
function(a,b,c){}
Now i want that the function first checks if the arguments are valid for the
function. E.g argument "a" has to be a number in the range 0-1
ric(a)) stop("a is not numeric")
if(0 > a && a > 1) stop("a must be a value between 0 and 1")
a
}
/Johannes
Original-Nachricht
> Datum: Tue, 6 Dec 2011 07:04:59 -0500
> Von: "R. Michael Weylandt"
> An: Joh
the function call not outside
the function or before etc.
/Johannes
Original-Nachricht
> Datum: Tue, 6 Dec 2011 07:57:44 -0500
> Von: "R. Michael Weylandt"
> An: r-help , Johannes Radinger
> Betreff: Re: [R] Argument validation within functions
> Use the ! (n
Hi,
I am trying to get write my first own package.
I followed the instructions in "Creating R Packages: A Tutorial"
and "Writing R Extensions". So far everything works really
fine, the script works and even the man-pages don't show
any problems during the check process.
During "check" there is al
Am 10.12.2011 um 16:50 schrieb Uwe Ligges:
>
>
> On 09.12.2011 14:15, Johannes Radinger wrote:
>> Hi,
>>
>> I am trying to get write my first own package.
>> I followed the instructions in "Creating R Packages: A Tutorial"
>> and "Writing
Hello,
I know that it'll be quite easy to do what I want but somehow I am lost as I am
new to R. I want to get summary results arranged by groups. In detail
I'd like get the number (levels) of Species per Family like for this dataset:
SPEC <- factor(c("a","a","b","b","c","c","c","d","e","e","e",
Original-Nachricht
> Datum: Mon, 2 Jan 2012 14:29:07 +0100
> Von: Petr PIKAL
> An: "Johannes Radinger"
> CC: r-help@r-project.org
> Betreff: Re: [R] summary per group
> Hi
>
> >
> > Hello,
> >
> > I know that it&#
Hi,
I have got a dataset with
the variables Y,X1,X2,X3.
Some of these variables contain NAs. Therefore
incomplete datasets aren't recognized when
I am doing a regression like:
model <- lm(Y~X1+X2+X3)
so the resulting vector of resid(model) is
obviousely shorter then the original variables.
How
Hello,
I am doing a simple regression using lm(Y~X).
As my response and my predictor seemed to be skewed
and I can't meet the model assumptions. Therefore
I need to transform my variables.
I wanted to ask what is the preferred way to find out
if predictor and/or response needs to be transformed
a
Hello,
I very general question but probably usefull to others as well:
Is there any prebuild function that reorders a dataframe from:
x1x2
1 100 200
2 101 201
3 102 202
4 103 203
5 104 204
6 105 205
to
1 100 x1
2 101 x1
3 102 x1
4 103 x1
5 104 x1
6 105 x1
7
Hi,
I'd like to use the reshape2 package for melting datasets.
The problem is that I've also loaded the gglot2 package which
automatically loads the reshape-package. And the reshape is
masking my reshape2.
Thats why I tried
reshape2::melt(df_test,id=c("X1",
"X2"),variable.name="variable_test",v
> Have you tried loading reshape2 after ggplot2 and all it's requirements?
> Usually whatever is loaded last masks earlier loaded packages with functions
> of the same name so if reshape2 is last then it should mask reshape(1) and
> all of it's similarly named functions.
>
> Brandon
Yes, res
quot;melt", data)
> }
>
>
> Brandon
No doesn't work either...value.name is ignored as well when
I call reshape2::melt()
/Johannes
> On Thu, Nov 10, 2011 at 08:45, Johannes Radinger wrote:
>
> > Have you tried loading reshape2 after ggplot2 and all it's requ
t2 0.8.9
cheers
/j
Original-Nachricht
> Datum: Thu, 10 Nov 2011 08:51:55 -0300
> Von: Luciano Selzer
> An: Johannes Radinger
> CC: Brandon Hurr , r-help@r-project.org,
> ggpl...@googlegroups.com
> Betreff: Re: reshape - reshape2 problem
> I had the same is
Hi,
I am looking for a way to save the result of a function, e.g the lm()-function
to a file and reload it afterwards again. I'd like to do that in order to
minimize the used memory when running the function in a loop. The actual
function I want to store is the evaluate() from the dismo package
Original-Nachricht
> Datum: Thu, 08 Mar 2012 09:51:01 -0500
> Von: Duncan Murdoch
> An: "R. Michael Weylandt"
> CC: Johannes Radinger , R-help@r-project.org
> Betreff: Re: [R] Save/Load function()-result to file in a loop
> On 08/03/2012 8:42 A
Hi,
I am trying to do plot a scatterplot matrix using pairs() from
the package graphics. There are now a few things I'd like to improve
for a better understanding.
1) My scatterplot uses two log-scaled axis...as I
don't know how to set them in pairs() I calculated the log before but now
the label
Hello,
I already posted that on stackoverflow[1], but although it's crossposting,
I think this question can probably easier to be answered by other R-users on
this list, which maintain packages etc.
I would like to make a package out of a function. The function
is working in a script, but when I
Hi,
I want to create a pdf of my Man-pages from my package.
Therefore I run in the terminal Rd2pdf on the package and
a pdf of all the pages is created.
After the titlepage there is the general package page, which includes
"Description" and "Details" etc. Unfortunately after the Subtitle "Details
Hi,
I try my first time to write a summary method for my function. The result of my
function is a list of two objects (2 arrays). In my summary both objects should
be displayed but with a some introductory text like:
ls <- list(A="A123",B="B123")
summaryout=function(x,...){
cat("This i
Hi,
I am wondering if anybody has experience with
scatterplot matrices where some (but NOT all) axis
are transformed and the labels are nicely plotted.
So far I looked into
1) pairs()
2) scatterplotMatrix() from package 'car'
3) splom() from packagae 'lattice'
4) plotmatrix() from 'ggplot2'
I ca
Hello,
probably it is quite easy but I can get it: I have
mulitple numeric vectors and a function using
all of them to calculate a new value:
L <- c(200,400,600)
AR <- c(1.5)
SO <- c(1,3,5)
T <- c(30,365)
fun <- function(L,AR,SO,T){
exp(L*AR+sqrt(SO)*log(T))
}
How can I get an array or
Dear Jean,
Thank you, expand.grid was the function I needed.
/johannes
>
> See
> ?expand.grid
>
> For example,
> df <- expand.grid(L=L, AR=AR, SO=SO, T=T)
> df$y <- fun(df$L, df$AR, df$SO, df$T)
>
> Jean
>
>
> Johanne
Hello,
I have a vector which looks like
x$ART
...
[35415] 0001-1;02-1;05-1;
[35417] 01-1; 01-1;02-1;
[35419] 01-1; 00
[35421] 01-1;04-1;05-1;
[35
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