Hi Achim,
thank you for your good explanation and the solution to my
question...
cheers,
/j
-------- Original-Nachricht --------
> Datum: Fri, 8 Jun 2012 09:30:42 +0200 (CEST)
> Von: Achim Zeileis <achim.zeil...@uibk.ac.at>
> An: Johannes Radinger <jradin...@gmx.at>
> CC: R-help@r-project.org
> Betreff: Re: [R] Sort 1-column dataframe with rownames
> On Fri, 8 Jun 2012, Johannes Radinger wrote:
>
> > Hi,
> >
> > I have a 1-column dataframe with rownames and I want to sort it
> > based on the single column. The typical procedure that is recommended
> > in diverse posts is to use order in the index. But that "destroys" my
> > dataframe structure. Probabaly it is a very simple solution. Here is a
> > short reproducable example:
> >
> > x <- c(1,3,51,2,34,44,12,33,2,8)
> >
> > df <- data.frame(x)
> > rownames(df) <- c("A","B","C","D","E","F","G","H","I","J")
> >
> > df.sort <- df[order(df[,"x"]),]
>
> If you select a single column, then the default is to drop the data.frame
> property. You exploit this in your own code in df[,"x"] which yields a
> simple vector. To suppress this behavior you can set drop = FALSE:
>
> df.sort <- df[order(df[,"x"]), , drop = FALSE]
>
> hth,
> Z
>
> > /Johannes
> > --
> >
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> >
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