I am trying to do ttest for each plate which has equal number of disease and
controls. by searching this forum I found one posting suggesting OP to use
"by(eo,PlateID, function(.sub) t.test(IL1Ra~Group,data=.sub))". when i
modified this for my use I used to get the pvalues for each plate, recently
any one
1Rnwb wrote:
>
> I am trying to do ttest for each plate which has equal number of disease
> and controls. by searching this forum I found one posting suggesting OP to
> use "by(eo,PlateID, function(.sub) t.test(IL1Ra~Group,data=.sub))". when i
> modified this
with my limited understanding, I am not surprised to see this data fitting
nicely at the end just by eyeballing at it. the reaction at the early time
point is not completed as the time passes which is close to 20 units the
reaction generates more metabolite to be measured reliably your t=0 and t=1
y"by(eo,eo$sex,function(.sub) t.test(prt1~Disease,data=.sub))" is
also not working when I select the data for 40 plates. I used these two
formulas earlier sucessfully. I am uploading a part of data as a delim file
for sample http://www.nabble.com/file/p25051220/r..txt r..txt . Thanks
1Rnwb
Hello list,
I have a similar issue as this post
http://tolstoy.newcastle.edu.au/R/e6/help/09/04/11438.html#options2 and I
used the suggestion provided by Jorge with modifications to my data
do.call(c,lapply(your_list_with_the_t_tests,function(x) x$p.value))
but I am getting the following error
okay fixed it by putting "c" in quote marks.
1Rnwb wrote:
>
> Hello, I am using "B" as a vector to store all the t.tests. since i am a
> newbie to both R and statistics I am not sure if "B" is the list. Also I
> see "c" used in the do.call
Is "B" a list? If not, I am not sure if lapply can take
> it. Try aggregate().
>
> On Fri, Aug 28, 2009 at 10:53 AM, 1Rnwb wrote:
>
>>
>> Hello list,
>>
>> I have a similar issue as this post
>> http://tolstoy.newcastle.edu.au/R/e6/help/09/0
Hello R gurus,
I am biologist doing biomarker research and I have a data set where I have 6
proteins and close to 3000 samples, i have to look for differences between
disease(Y) and controls(N) along with genetic risk, genotypes, sex and other
demographic info available. however i do not know any
then what will be the other factors needed to be adjusted and whether I
should adjust or use them as covariates. Finally how these analysis will be
done in R
Harrell, Frank E wrote:
>
> 1Rnwb wrote:
>> Hello R gurus,
>>
>> I am biologist doing biomarker research and I
I use the long way, you might have to play around with my script to get is
correct. once you get it to work, you can add as many points to reflect,
median, percentile etc.
## generatiing vectors for Group1
a<-LMMP8[Self_T1D=="N"]
w <- a[!is.na(a)]
length(w)
c<-mean(a, na.rm=TRUE)
c
since heatmap is a graphic image it needs the "graphics" library. you can see
these two in the examples for heatmap.
require(graphics); require(grDevices)
Markus Mühlbacher wrote:
>
> Dear R community!
>
> I am trying to create a heatmap based on the following data. As you can
> see the diago
Please explain me as what it means and how this analysis can be done using R
and which library(ies) are needed.
Thanks
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01.408.8111
>
>
>> -Original Message-
>> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
>> project.org] On Behalf Of 1Rnwb
>> Sent: Monday, July 20, 2009 11:30 AM
>> To: r-help@r-project.org
>> Subject: [R] Re gression using age and Du
I thought this forum is for help. now i know what the statistician in my dept
does all day long
Rolf Turner-3 wrote:
>
>
> On 21/07/2009, at 5:30 AM, 1Rnwb wrote:
>
>>
>> Please explain me as what it means and how this analysis can be
>> done using R
>&g
the
analysis. after all I do have to explain all these things to my boss as
well.
Thanks
Steve Lianoglou-6 wrote:
>
>
> On Jul 20, 2009, at 5:30 PM, 1Rnwb wrote:
>
>> I have read that multiple times without understanding anything.
>
> If that's the case, then per
usually i go thru the manuals of the libraries and the data attached with the
libraries to get the code working for my data. not a good way but usually it
works out.
Nimal Fernando wrote:
>
> Hi
>
> It would be a great help if someone can direct me to access some existing
> R
> codes for fittin
use hilox<-range.x=range(x variable) and hiloy<-range.y=range(y variable)
or store these values in vectors to be later on user as xlim=hilox,
ylim=hiloy
Frank Bloos wrote:
>
> You may want to use the function corner.label from the plotrix-package.
>
> Frank
>
Mark Na 21.07.2009 23:03 >
I am also a newbie, but here are the few thing i do
eo=read.table(file="path where you have saved your text
file/xxx.txt",header=T, )
#this will only read excelfiles saved
as *.csv file
attach(eo)
Hello,
I have to add "Age (bar(x)=14.3) as a title on a chart. I am unable to get
this to working. I have tried bquote, substitute and expression, but they
are only doing a part of the job.
new<-
c(14.3, 18.5, 18.1, 17.7, 18, 15.9, 19.6, 17.3, 17.8, 17.5, 15.4,
16.3, 15, 17.1, 17.1, 16.4, 15.2,
gt; From: [hidden
> > email]<http://user/SendEmail.jtp?type=node&node=4645934&i=0>[mailto:[hidden
> email] <http://user/SendEmail.jtp?type=node&node=4645934&i=1>] On Behalf
> > Of 1Rnwb
> > Sent: Thursday, October 11, 2012 2:32 PM
> > To: [hidden e
Hello
I have a data set like below:
plate.id well.id Group HYB rlt1
1 P1 A1 Control SKOV3hyb 0.190
2 P1 A2 Control SKOV3hyb 0.210
3 P1 A3 Control SKOV3hyb 0.205
4 P1 A4 Control SKOV3hyb 0.206
5 P1 A5 Control SKOV3hyb 0.
Thanks for the help.
Sharad
On Mon, Sep 27, 2010 at 9:12 PM, Remko Duursma [via R] <
ml-node+2716469-935075351-6...@n4.nabble.com
> wrote:
> Try something like this:
>
>
>
> dfr <- read.table(textConnection("plate.id well.id Group HYB
> rlt1
> 1 P1 A1 Control SKOV3hyb 0.
Hello List,
I have a longitudinal samples on multiple individuals, for initial analysis,
i am doing some plots to see how the variable changes with the age. In some
of the individuals one or two data points are missing,
IL1Ra Age.at.Sample.Collection Subject.ID
6.575
Hi The reshape suggestions works great on my previous data, but I am unable
to make is work on the new dataset. It actually works but only gives me the
output of single row, instead of 96 rows.
The dataset has two control groups control 1 and control 2, two disease
groups viz disease 1 and disease
P1 B2 SKOV3hybNANANA
> 7 P1 B3 SKOV3hybNANA 0.371
> 8 P1 B4 SKOV3hybNANANA
> rlt1.control2
> 1NA
> 2NA
> 3 NA
>
Hello all, I am using 'plot' to create standard curves for elisa data. when I
use 'plot' with type='b' i get the points connected with lines and one
straigth line from the lowest datapoint to the highest data point. how can i
avoid/remove it from the figure. i am using R2.9.1, below is the example
Hi
I have a script which is designed to gather data from individual columns
from a file, which is an output from an instrument. the file has multiple
sections and each a section has data under each column (vars), I am using
the name of the column as a variable to gather the column ID using
vidx<
Thanks Jim for the explanation. I will modify the code accordingly
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my question is exactly as described in this post
http://tolstoy.newcastle.edu.au/R/e2/help/07/02/9812.html
i am doing the pattern search using a vector 'vars[vi]' where i cannot use
'^vars[vi]$' for a exact pattern match
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Thanks I agree i did not asked the question correctly, but I solved the issue
using the suggestions from this post.
http://www.mail-archive.com/r-h...@stat.math.ethz.ch/msg23646.html
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sorry i got clik happy
df2<-df1[, c(3,5,7,9,11,13,15)]
df2<-df2[grep('ID', df2$Group), ]
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the current code is like this
vidx<-grep(paste('^',vars[vi],'$',sep=''),gsub("[[:punct:]]","",strrl1[[datbeg-1]]),ignore.case=T)
where as the old one was
vidx<-grep(vars[vi],gsub("[[:punct:]]","",strrl1[[datbeg-1]]),ignore.case=T)
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If I understand correctly you want to create a new dataframe with selected
columns which can be achieved this was as well, it will right away create a
new dataframe with column headers
df2<-df1[ ,c(3,7,9,11,13,15)]
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I have questions regarding
test=data.frame(cbind(conc=c(25000, 12500, 6250, 3125, 1513, 781, 391,
195, 97.7, 48.4, 24, 12, 6, 3, 1.5, 0.001),
il10=c(330269, 216875, 104613, 51372, 26842, 13256, 7255, 3049, 1849, 743,
480, 255, 241, 128, 103, 50)))
nls(log(il10)~A+(B-A)/(1+(conc/xmid )^scal),da
Thanks Dieter for the help. This is how I want
plot(log(test$conc),fn(test$conc,15,3.5,600,1/2.5),type="l") # looks good
points(log(test$conc),log(test$il10))
regards and happy holidays
sharad
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mtext(4, ylab="your title", font)
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Hello,
I have data in a dataframe with 139104 rows which is multiple of 96x1449. i
have a phenotype file which contains the phenotype information for the 96
samples. the snp name is repeated 1449X96 samples. I haveto merge the two
dataframes based on sid and sen. this is how my two dataframes loo
I have question about log2 transformation and performing mean on log2 data. I
am doing analysis for ELISA data. the OD values and the concentration
values for the standards were log2 transformed before performing the lm. the
OD values for samples were log2 transformed and coefficients of lm were
a
Hello gurus,
I have a dataframe containing two groups viz., 'control' and 'case', each of
these groups contains longitudinal data for 100 subjects. I have to plot all
these subjects on a single chart and then put a regression line for each of
the group for all the subjects. I have written a functi
here is the data set, yes i am doing spagghetti plots for each Subject for
MCP1 with respect to the Age.at.Sample.Collection, with a final of all the
controls and all the cases
Subject.ID sample Group Age.at.Sample.CollectionMCP1
19 00173-0 3455 control11.767282 2
Hello R gurus, I have a data set from which i have to extract the gender and
age matched rows from controls and disease group
disease<-paste(rep(c('y','n'),11))
gender<-paste(rep(c('m','f'),11))
mcp<-rnorm(700,1400)
age<-rnorm(32,34)
dat<-data.frame(disease=disease,sex=gender,Dr_age=age[1:22],MCP=
I hope this modified example will work
set.seed(100)
disease<-paste(rep(c('y','n'),50))
gender<-c(paste(rep(c('m','f'),25)), paste(rep(c('f','m'),25)))
mcp<-rnorm(100, mean=1000,sd=600)
age<-rnorm(100,mean=32,sd=20)
dat<-data.frame(disease=disease,sex=gender,Dr_age=age,MCP=mcp
Thanks, for pointing out the package e1071, the example for matchControls is
exactly what I am looking for, however how can I add additional factors to
match for.
library(e1071)
Age.case <- 40 + 5 * rnorm(50)
Age.cont <- 45 + 10 * rnorm(150)
Age <- c(Age.case, Age.cont)
Sex.case <- sample(c("M", "
click in console window and type rm(list=ls(all=TRUE)),
everything will be gone
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Hello all,
I have arranged my data as per Dennis's suggestion in this post
http://www.mail-archive.com/r-help@r-project.org/msg107156.html.
the posted code works fine but when I try to apply it to my data, i get ">
u2 <- ddply(xxm, .(plateid, cytokine), as.data.frame.function(f))
Error in t.test.f
I knew that the "NA's" in my data were the root cause of the trouble, but did
not find out how to get rid of them. Untill I found your another post
mentioning to use 'na.omit' to remove the lines containing 'NA's" and the
problem got fixed after that.
Thanks for the help and all the trouble you hav
Thanks, I thought that removing the list would take care of it. the question
is I do not see a .Rhistory file in my current working directory, so where
it is stored. it is not visible in C:\Program files\R either. Serarching the
C;\ and D:\ drives shows some old .Rhistory files but not the recent o
I have 120 MS chromatograms containing two columns'Time' and 'Peak height'.
how do in create a msSet file which is required by all the functions of
'msProcess' to process these files.
I would appreciate help very much.
Thanks
Sharad
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I have a data frame like this
xx<-data.frame(cbind(Sample=c('Ctrl_6h','1+0_6h','1+200_6h','1+5k_6h','Ctrl_5K_6h','ConA_6h'),
IFIT1=c(24,25,24.7,24.5,24.2,24.8)))
grep('[[:digit:]]h',xx$Sample)
yy<-xx$Sample
strsplit(yy,"_")
I have to extract the time information separated by '_
Thanks to all of you for the suggestions and corrections.
Sharad
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the examples work great but it gives me this error on this file
http://r.789695.n4.nabble.com/file/n3603737/il1ra_L.csv il1ra_L.csv
> Age.co<-c(dat2b$Dr_Age)
> Sex.co<-as.factor(dat2b$Sex)
> casecont.co<-as.factor(dat2b$Self_T1D)
> stat.co<-as.factor(dat2b$status)
>
> m <- matchControls(Sex.co~A
getting errors when running this file
http://r.789695.n4.nabble.com/file/n3605311/il1ra_status.txt
il1ra_status.txt
> Age.co<-c(dat2b$Dr_Age)
> Sex.co<-as.factor(dat2b$Sex)
> casecont.co<-as.factor(dat2b$Self_T1D)
> stat.co<-as.factor(dat2b$status)
>
> m <- matchControls(stat.co~Sex.co+Age.co,
hello gurus,
i have a data frame like this
HTN HTN_FDR Dyslipidemia CAD t1d_ptype[1:25]
1Y YY T1D
2 T1D
3 Ctrl_FDR
4 T1D
5Y
I do not know how to use dput, i am attaching the txt file for the data
http://r.789695.n4.nabble.com/file/n4222616/foo.txt foo.txt
c1<-read.dlim('foo.txt')
c2<-c1
any_comp<-NULL
for( i in 1:dim(c1)[1])
{
num_comp<-0
for (j in 1:dim(c1)[2])
if (c1[i,j]==2) num_comp=num_comp+1 #"Y"
here is the dump and the code once again, sorry for creating so much noise.
c1<-structure(list(HTN = structure(c(2L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L), .Label = c("", "Y"), class = "factor"), HTN_FDR = structure(c(2L,
1L, 1L, 1L, 2L,
Thanks Bill, the output of dput was very similar to your example, I was not
sure so did not put it on the post. however i uploaded the foo.txt file
which contains the part of the data.
sharad
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Sen
this is how the ouput from the code should be
structure(list(HTN = 1:10, HTN_FDR = structure(c(4L, 2L, 1L,
2L, 3L, 1L, 1L, 2L, 3L, 2L), .Label = c("Ctrl_noc", "T1D_noc",
"T1D_oc", "T1d_w"), class = "factor"), Dyslipidemia = structure(c(3L,
2L, 1L, 2L, 4L, 1L, 1L, 2L, 4L, 2L), .Label = c("Ctrl_
Hello Gurus
I have two correlation matrices 'xa' and 'xb'
set.seed(100)
d=cbind(x=rnorm(20)+1,
x1=rnorm(20)+1,
x2=rnorm(20)+1)
d1=cbind(x=rnorm(20)+2,
x1=rnorm(20)+2,
x2=rnorm(20)+2)
xa=cor(d,use='complete')
xb=cor(d1,use='complete')
I want to combine these two to get a third
okay so fixed what i need to do this way
finit=0
for(ri in 1:dim(xa)[1])
{
finit=finit+1
xc[ri,1:finit]<-xa[ri,1:finit]
xc[1:finit,ri]<-xb[1:finit,ri]
}
but getting error in heatmap.2
> mycol <- colorpanel(n=40,low="red",mid="white",high="blue")
> heatmap.2(xc, breaks=pairs.breaks, col=mycol, Ro
Thank you all for your suggestions.
Sharad
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so here is the code I need help to fix the line for 'st' when it reaches
maximum, that's where i am getting stuck.
thanks
Sharad
set.seed(100)
d=data.frame(x=rnorm(20)+5,
x1=rnorm(20)+5,
x2=rnorm(20)+5,
x3=rnorm(20)+5,
x4=rnorm(20)+5,
x5=rnorm(20)+5,
x6=rnorm(20)+5,
x7=rnorm(20)+5,
x8=rno
Thanks Micheal,
that's what I wanted, I did not quite catch which variable is unused.
Another part is I have my variable values in log scale so it generates '0's'
instead of '1', how do i get rid of those cols.
Thanks for you patience
Sharad
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thanks for the help and pointer.
I am modifying it like this
x=which(n[,1]==n[,2])
n=n[-x,]
to get rid of combinations which will generate '0' or ratio of 1.
Thanks once again.
sharad
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Hello gurus,
I have some variables, and i am creating combinations for analysis in the
end i need these variables to be displayed like "LEPTIN+SAA+PTH". currently
i am using loop to perform this. I would appreciate any pointers to do it
without the loop.
> mols=c("LEPTIN","SAA","PTH","sEGFR")
> s
is this what you are looking for
library(lattice)
(Seq <- matrix(c(1, 1, 6, 1, 2, 2, 5, 4, 3, 3, 4, 3,
4, 4, 3, 2, 5, 5, 2, 5, 6, 6, 1, 6), ncol = 6))
plot(Seq[1,], Seq[2,], main = "Sequenz 1 und
Sequenz 2", asp = 1)
abline(a=0,b=1,col='red',lwd=2)
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Hi Joshua,
Thanks for the suggestion.
Sharad
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Hello R gurus,
I have the code below for which i need help and pointers to make it run in
parallel on a dual core win7 computer with R 2.13.x, using foreach,
iterators,doMC.
library(scatterplot3d) # Loads 3D library.
library(fields)
library(MASS)
library(ROCR)
library(verification)
library(caret)
sorry for noise
the simulated data should be like this
d=data.frame(replicate(9, rnorm(40)+10),rep(c('y','n'),20))
colnames(d)<-c("LEPTIN","SAA","PTH","sEGFR","IGFBP6","MMP2","OPG","IGFBP3","PDGFAABB","group")
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if you are a beginer then try this
http://www.stat.pitt.edu/stoffer/tsa2/R_time_series_quick_fix.htm
there are lots of books and their exercises available on the authors
website. also search in google books
http://books.google.com/books?id=0fRcUmyhUIQC&printsec=frontcover&source=gbs_ge_summary_r&c
my modification gives me error
> rows<- c(1:nrow(mat))
> scores <- c()
> labels <-c()
> itr<-1000
> chnksz<-ceiling(itr/getDoParWorkers())
> smpopt=list(chunkSize=chnksz)
> foreach(icount(itr),.combine=cbind,.options.smp=smpopts)%dopar%
+ {
+ train <- sample(rows, length(rows)-1)
+ label =
yes the library(MASS) was loaded.
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If i understand correctly you mean to write the line as below:
foreach(icount(itr),.combine=combine,.options.smp=smpopts,.packages='MASS')%dopar%
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the part of the question dawned on me now is, should I try to do the parallel
processing of the full code or only the iteration part? if it is full code
then I am at the complete mercy of the R help community or I giveup on this
and let the computation run the serial way, which is continuing from p
I would like to know if clogit function can be used as below
clogit(group~., data=dataframe)
When I try to use in above format it takes a long time, I would appreciate
some pointers to get multiple combinations tested.
set.seed(100)
d=data.frame(x=rnorm(20)+5,
x1=rnorm(20)+5,
x2=rnorm(20)+5,
bump
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how can i put the row labels on the left hand of the heatmap in heatmap.2?
abnr<-structure(c(1, 0.678622097406395, 0.670294749652918,
-0.0016314464654279,
-0.000519068106572792, 0.199581999119988, -0.0106623494189115,
0.0840111691399559, -0.0461494399639137, 0.249279171677728, NA,
1, 0.75711406
Hello R gurus,
I have to create 12 plots, I have been using the following script, which
leaves a large white space between two plot. I would appreciate if someone
can suggest an alternative to reduce the white space.
par(mar=c(3,3,.5,.5))
split.screen(c(6,2))# split display into two scree
Hello R Gurus,
I have a matrix for which I am doing a heatmap using heatmap.2. I want to
put the rownames on the lefthand side instead of the right side of the
heatmap. how can i put the rownames on left hand side: I have already tried
axis but could not make it work
ccc<-structure(c(1, 0.283300
9 4.5 2 8 2097693.5 16.528 13
274.5
C7 35 257 4.5 25.517 16.59 12 10
52 10 5 3 7 1456750 24 23 11
70.5
Thanks for the help
1Rnwb wrote:
>
> H
Dear list,
i am a biologist who needs to do some ttest between disease and non disease,
sex, genotype and the serum levels of proteins on a large number of
individuals. i have been using excel for a long time but it is very tedious
and time consuming. i am posting the data below and ask your hel
genotype ,data = data1)
> summary(aov1)
>
>
> If you insist on t.test, here is the way:
> t.test(data ~ gender ,data = data1)
> t.test(data ~ disease ,data = data1)
> t.test(data ~ genotype ,data = data1)
>
>
> Cheers,
> Tal
>
>
>
since the estimation is not done pairwise so i cannot use pairwise.t.test,
how do i apply tukeyHSD
Thomas Petzoldt-4 wrote:
>
> 1Rnwb schrieb:
>> Thanks for the help, but ANOVA will give me a single pvalue, then how i
>> can
>> make sure which group is showing the
Hello R guru's
I am a newbie to R, In my research work I usually generate a lot of ELISA
data in form of absorbance values. I ususally use Excel to calculate the
concentrations of unknown, but it is too tedious and manual especially when
I have 100's of files to process. I would appreciate some h
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