Hello,
I was wondering if there is a way to make a prompt for the user (exactly
like raw_input() in Python), the response to which can then be used as an
object.
Thanks,
Abir
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Solved !
the problem was the date 04/02/2012
the "/" made him think there is more folders
thanks
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HI Antony,
I am not sure how you want the result.
Is it something like this? Also, do you have lots of conditions in the array?
> Mydat2
ABC PQR XYZ ELIGIBLE_ABC ELIGIBLE_PQR ELIGIBLE_ABC_XYZ
1 10 20
30 TRUE
2 40 50
Perhaps readline()?
Best,
Michael
On Wed, May 30, 2012 at 2:31 PM, meatloafthefrog
wrote:
> Hello,
>
> I was wondering if there is a way to make a prompt for the user (exactly
> like raw_input() in Python), the response to which can then be used as an
> object.
>
> Thanks,
>
> Abir
>
> --
> View
I have a data frame that has columns Semester, Student ID (SID), Subject,
Grade, Devel (Tor F). Students can have multiple records within a semester.
Right now, the columns are not considered factors.
I want to do an analysis that would show the number of students who received
particular combinat
I think you're looking for xtabs [see the examples; they're quite
good] but I can't be sure: your printed object can't really exist in R
so I'm not sure what you have currently.
Michael
On Wed, May 30, 2012 at 3:25 PM, cassiorx wrote:
> I have a data frame that has columns Semester, Student ID (
On May 30, 2012, at 1:04 PM, ilai wrote:
If you haven't done so you *must* read an Introduction to R. The only
reason this is a problem is Myarray is a character string, not a
function
or expression to be evaluated. I think this will get you what you want
though:
# In the future use the out
On May 30, 2012, at 4:38 PM, R. Michael Weylandt wrote:
Perhaps readline()?
Or possibly ( depending on what exactly the undescribed Python
function does) ...
x <- scan() # defaults to numeric but can be used for character
input with correct parameters
Best,
Michael
On Wed, May 3
On May 30, 2012, at 4:51 PM, R. Michael Weylandt wrote:
I think you're looking for xtabs [see the examples; they're quite
good] but I can't be sure: your printed object can't really exist in R
so I'm not sure what you have currently.
Michael
On Wed, May 30, 2012 at 3:25 PM, cassiorx
wrote:
Hi all,
Given a table like the one below, I want to get a number of vectors equal to
the groups of connected ID (ID are considered connected if they are in the
same row). Each vector should contains all the connected ID .
e.g. In this case: vect1 (1,2,3) vect2 (5,6) vect3 (7,8,9)
If you haven't already look at Introduction to R, please follow this link
"http://cran.r-project.org/doc/manuals/R-intro.pdf";. There are several books
which will teach you R, please look at online retailers like Amazon, Ebay
etc.,
Online search for specific task will also to help you to gather kn
Dear R help,
I have a dataset with 1's and 0's. Here, each row is the observation for an
insect. If the animal is present in light area at a particular time, response
is 1 and if it is present in dark area, the response is 0. I would like to do
some formating on the data for analysis. To be
Hello,
The problem can be solved using graph theory tools.
library(igraph)
edg <- read.table(text="
ID ID2
12
13
23
65
78
89
", header=TRUE)
(G <- graph(t(edg) - 1, directed=TRUE)) # igraph vertices are zero-based
V(G)$name <- 1:9
#V(G)$label <- V(G)$name
#plot(G, lay
Hi A.K.,
Thank you for the example.
Here is one way:
dat[apply(dat, 1, function(x) x[1] == 1 & length(rle(x)$values) > 2), ]
See ?rle and ?apply for more details.
HTH,
Jorge.-
On Wed, May 30, 2012 at 5:45 PM, arun <> wrote:
> Dear R help,
>
> I have a dataset with 1's and 0's. Here, each r
Hello,
Try the following.
ix <- apply(dat, 1, function(x) x[1] == 1 && sum(diff(x) != 0) > 1)
dat[ix, ]
Hope this helps,
Rui Barradas
Em 30-05-2012 22:45, arun escreveu:
Dear R help,
I have a dataset with 1's and 0's. Here, each row is the observation for an insect. If the animal is pres
On Wed, May 30, 2012 at 12:47 PM, Iain Gallagher
wrote:
> Hi Phil
>
> Thanks, but this still doesn't work.
>
>
> Here's a reproducible example (was wrapping my head around these functions
> before).
>
> x <- as.data.frame(cbind(rep('a',5), rep('b',5)))
> y <- as.data.frame(cbind(rep('c',5), rep('
Hi,
I have a R Package. It is working, but I can't that it install the
dependencies automatically. When I try to install I receive this message:
> install.packages("./RT4Bio_1.0.tar.gz",dependencies=TRUE)
Installing package(s) into '/usr/local/lib/R/site-library'
(as 'lib' is unspecified)
infer
Iain -
Do you see the same behaviour if you use
z <- unz(pathToZip, 'x.txt')
instead of
z <- unz(pathToZip, 'x.txt','r')
- Phil Spector
Statistical Computing Facility
De
> The code below is used to generate interval censored data but unfortunately
> there is an
> error with the ifelse which i am not able to rectify.
> Can somebody help correct it for me.
Not quickly.
But cut() might do a large part of what you need with a
On May 30, 2012, at 6:36 PM, Ronaldo Reis Júnior wrote:
Hi,
I have a R Package. It is working, but I can't that it install the
dependencies automatically. When I try to install I receive this
message:
install.packages("./RT4Bio_1.0.tar.gz",dependencies=TRUE)
Installing package(s) into '/
Hi,
I have a vector like this:
DF <- c("Aetna, Inc.", "Alexander's Inc.", "Allegheny Energy, Inc")
For each element in the vector I would like to remove the "incorporated"
info, so that my vector looks like this:
DF <- c("Aetna", "Alexander's", "Allegheny Energy")
That means that I have to str
Thanks Jorge,
It worked.
A.K.
From: Jorge I Velez
To: arun
Cc: R help
Sent: Wednesday, May 30, 2012 6:11 PM
Subject: Re: [R] Extracting rows from a dataset
Hi A.K.,
Thank you for the example.
Here is one way:
dat[apply(dat, 1, function(x) x[1] == 1 &
I am a novice user of R and am stumbling on how to order a dataset
produced during my session.
I have a 1863 row X 14 column dataset that I want to put out to a file.
I want the output sorted by the first column and then by the second
column both in ascending order. The first column is chara
Hi all,
I Have a data frame test.. that I would like to convert into a list below
test_ but am unsure how to efficiently do this. I can do it in a for loop
but my data set is huge and it takes forever. Wondering how I can do this
more efficiently. So again how to I go from test.. to test_ bel
I have a huge matrix of unspecified covariates and the corresponding sales
for them. What is the best way to predict the sales from the covariates?
Thanks,
Chris
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How can I perform cluster analysis using the mahalanobis distance instead of
the euclidean distance?
Thank you
Maria Froes
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If you want to sort by the columns with the names 'var1' and 'var2',
you would do:
newdata <- data[order(data$var1, data$var2), ]
On Wed, May 30, 2012 at 6:07 PM, tony.anderson wrote:
> I am a novice user of R and am stumbling on how to order a dataset produced
> during my session.
>
> I have
try this:
> test.. <- data.frame(Apples = c(1,3,0,0,1), Pears = c(0,0,1,0,2), Beans =
+ c(1,2,1,0,0))
>
> lapply(seq(nrow(test..)), function(.row){
+ do.call(c, sapply(names(test..), function(.col){
+ rep(.col, test..[[.col]][.row])
+ }))
+ })
[[1]]
ApplesBeans
"Apples" "Bea
Try this where you qualify how many characters you might match:
> gsub(",{0,1} Inc[.]{0,1}", "", DF)
[1] "Aetna""Alexander's" "Allegheny Energy"
On Wed, May 30, 2012 at 6:05 PM, mdvaan wrote:
> Hi,
>
> I have a vector like this:
>
> DF <- c("Aetna, Inc.", "Alexander's Inc.", "A
On Wed, May 30, 2012 at 4:07 PM, Chris Burns wrote:
> I have a huge matrix of unspecified covariates and the corresponding sales
> for them. What is the best way to predict the sales from the covariates?
>
Don't want to sound rude, but given your very vague problem
specifications, the best way s
Hello,
I have a dataframe (Lx) with 5 Lb, and 5 Lw variables. I want to
create several variables according to the loop presented below (data
attached).
Lx <- read.csv("Lx.csv", header=T, sep=",")
for (i in 1:20) {
Lx$sb1[i] <- Lx$Lb1[i+1]/Lx$Lb1[i]
Lx$sb2[i] <- Lx$Lb2[i+1]/Lx$Lb2[i]
Lx$sb
Thanks! That works like a charm, but I am not sure if I fully understand the
syntax. I looked at the gsub page but still couldn't figure it out. What
does the pattern part (",{0,1} Inc[.]{0,1}") do? What do the 0 and 1 within
the curly brackets refer to? Also, what if, for example, I would want to
Hi, and thanks in advance.
I have used the following to try to obtain singly-imputed values for missing
data comprising no more than 15%
of any variable in the data:
> library(Hmisc)
> some.df = read.csv("N:/.../some.csv", header = TRUE, stringsAsFactors = TRUE)
> some.trans <- transcan(~ contin
Yea it was meant to be a vague question. I just wanted to see what some of
the answers were. It's for a project for school. We've done k nearest
neighbors, principal component analysis, partial least squares, and we'll
prob throw a random forest in there too.
Thanks
On Wed, May 30, 2012 at 10:
Dear Sebastian,
The following will create the names
paste("sb",1:5,sep="")
paste("sw",1:5,sep="")
paste("Lw",1:5,sep="")
paste("Lb",1:5,sep="")
Then you can easily combine and/or order them in R.
Hope this helps.
Ozgur
-
Ozgur ASAR
Research Assistant
M
There are many resources for learning regular expressions (e.g.
http://gnosis.cx/publish/programming/regular_expressions.html). Once you
understand the basics you will probably be able to refer to the ?regex help
page for specific tools. After you have waded through a tutorial, the following
ex
Hi,
Your mistake seems to be in
sum(v[1:x])
You create "x" as a vector but your treat it as a single number.
v[1:x] expects "x" to be a single number and only considers its first
element which is 1.
If I understand your query correctly, the following might handle your
problem:
sum.vec <-NU
Note that in R >= 2.15 you can also use paste0 for this operation more
efficiently.
Michael
On Thu, May 31, 2012 at 1:58 AM, Özgür Asar wrote:
> Dear Sebastian,
>
> The following will create the names
>
> paste("sb",1:5,sep="")
> paste("sw",1:5,sep="")
> paste("Lw",1:5,sep="")
> paste("Lb",1:5,s
Hello Everyone,
I am a MS students in the Department of Statistics, Biostatistics &
Informatics, in University of Dhaka, Bangladesh. Recently, I am doing thesis on
"D-optimal Designs for Regression models in Biostatistics". In my thesis work,
I am having problem with a particular program where
Hi Tony,
Try this:
dataT<-data.frame(Var1=rep(c("Sole","Lack","ABD","Zad"),rep(5,4)),
Var2=rnorm(20,0.5),Var3=runif(20,0.4))
dataT1<-dataT[with(dataT,order(Var1,Var2,Var3)),]
dataT1
Var1 Var2 Var3
12 ABD -0.19842353 0.4333720
13 ABD 0.14050814 0.9194297
11 ABD 1.07544531 0.453
0 and 1 means zero or 1 match.
Want to remove the word "Energy"?
gsub("( Energy){0,1},{0,1} Inc[.]{0,1}", "", DF)
On Thu, May 31, 2012 at 11:45 AM, mdvaan wrote:
> Thanks! That works like a charm, but I am not sure if I fully understand the
> syntax. I looked at the gsub page but still couldn't
Ozgur -- No, this is not what the OP seems to be asking for (and it's
bad code anyways -- I've mentioned the importance of pre-allocation to
you before):
OP, if I understand you, you are looking for a cumsum() operation:
something like:
t <- rbinom(1000, 1, 0.5)
t[t==0] <- (-1)
cumsum(t)
Alterna
On May 29, 2012, at 17:55 , maxbre wrote:
> Given this example
>
> #start code
>
> a<-c(0,70,50,100,70,650,1300,6900,1780,4930,1120,700,190,940,
>
> 760,100,300,36270,5610,249680,1760,4040,164890,17230,75140,1870,22380,5890,2430)
>
> b<-c(0,0,10,30,50,440,1000,140,70,90,60,60,20,90,180,30,90,
On May 29, 2012, at 17:55 , maxbre wrote:
> Given this example
>
> #start code
>
> a<-c(0,70,50,100,70,650,1300,6900,1780,4930,1120,700,190,940,
>
> 760,100,300,36270,5610,249680,1760,4040,164890,17230,75140,1870,22380,5890,2430)
>
> b<-c(0,0,10,30,50,440,1000,140,70,90,60,60,20,90,180,30,90,
On 30/05/2012 00:23, jalantho...@verizon.net wrote:
I have R 2.15.0 running under Windows 7. I installed the igraph 0.5.4 package from a zip file. When
I attempt to load igraph using "library(igraph)", I get the error package igraph is not
installed for arch=x64. When I repeat this using the 3
On 30/05/2012 04:02, Fabrice Tourre wrote:
Dear list,
I want to run two independent calculation (A, B) and then combined
their results to do a plot in R. Before I just run calculation A
first, then calculation B. It will take some times. I just have one
server with multiple core. I noticed that
See
http://cran.r-project.org/web/checks/check_results_odfWeave.html
which indicates the package has some problems. Hence CRAN does not make
binaries available. Please contact the maintainer.
Best,
Uwe Ligges
On 29.05.2012 16:23, stephenb wrote:
R version 2.15.0 (2012-03-30)
Copyright (C
On 29.05.2012 17:27, Steven Lacey wrote:
Hi,
I am hoping to use the RODBC package to write a dataframe to an Excel .xlsx
file. The dataframe contains at least one field with character elements
that exceed 255 bytes, which appears to be the cell width limit in Excel.
Below is example code and
On 29.05.2012 18:52, Emiliano Zapata wrote:
This is my current version of R:
R version 2.15.0 (2012-03-30)
Copyright (C) 2012 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
Platform: x86_64-pc-mingw32/x64 (64-bit)
OS: Windows
I get the following:
memory.size()
[1] 23.04
me
Dear Alex,
I'm cc'ing this to the mixed models list which is more appropriate for the
question. Please send all follow up posts only to that list.
First a few more general remarks.
- You are using the data argument of glmmPQL. So there is no need to attach()
the data.frame. I recommend avoid to
Hello,
currently I'm working on a model based on Monte-Carlo-Simulations.
I observed that a generated normal distributed times series using
rnorm(100,mean=0,sd=1)
is far away from being not autocorrelated.
Is there any other gerenator implemented in R, which might solve my problem?
--
View this
Please give a reproducible example when making bold statements.
I find no evidence of autocorrelation in
set.seed(12345)
x <- rnorm(100, mean = 0, sd = 1)
acf(x)
x <- rnorm(1e6, mean = 0, sd = 1)
acf(x)
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
Hy guys,
I have built a 3dimentional array that is meant to be a 3D landscape
for my simulation game.
Do you know if there is some package that allow me to plot the image?
I am looking at all 3D plots but nothing seems to be right. Should I
use the rgl package?
Thank you very much
Marianna
_
maybe the package DAKS can be of any help.
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag von Christian Kampichler
Gesendet: Dienstag, 29. Mai 2012 15:50
An: r-help@r-project.org
Betreff: [R] Package for partially ordered sets
Hi All,
Where can i download Rcurl package for windows.
Regards,
Santosh
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R-
> results <- mra(x$w1mcp, filter = "d4", n.levels = 3, boundary =
"periodic", method = "dwt")
> write.csv(results, "c:/mydata.csv")
Error in as.data.frame.default(x[[i]], optional = TRUE) :
cannot coerce class 'structure("mra", package = "wavelets")' into a
data.frame
I am not able to access
Em 29/5/2012 17:42, John Smith escreveu:
Dear R users,
I am trying to use xyplot to draw group mean and CI. The following is the
sample code.
[attached code snipped]
Did you try the plotmeans function from the gplots package?
But I want:
1. Use different colors and symbols to draw indi
Hi,
I am new in R,
i have a matrix like this
MyMatrix <-
*ABC PQRXYZ*
10 2030
40 5060
70 8090
And, i have an array containing some conditions like this,
MyArray <- c("*ABC*>50","*PQR*<50","*ABC*<30 &* XYZ*<40")
"ABC>50"
"PQR<50"
"ABC<30 & XYZ<4
Yes, there was a typo in my message. The problem remains.
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PLEASE do read the posting guide http://www.R-project.org/posting-g
Geraldine,
They really are the same fit, try...
range(fitted(b)-fitted(b1))
[1] -3.333782e-10 4.173699e-10
... for example.
The edf differences are just down to differences in how identifiability
constraints are handled in the two cases. For b1 the smooths of x2 do
not have centring constr
Hi,
What is quickest way to learn R? I am unnecessarily having fear of learning
R.
rgds
Parag Kulkarni
Haridwar,India
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Hello all,
I have searched and have not yet identified a solution so now I am sending
this message. In short, I need to split my data into training, validation,
and testing subsets that keep all observations from the same sites together
preferably as part of a cross validation procedure. Now fo
Thank you. This version worked.
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide comm
Google.com -> “cran rcurl“
"windows binary not available" -> read me
skip through file, find:
“Packages
GLMMGibbs, RCurl, XMLRPC, XML, gridSVG, survnnet, yags
do not build out of the box or other special in other circumstances.
Nevertheless these are available at
http://www.stats.
these are two great books that helped me significantly.
Verzani, John. 2004. Using R for Introductory Statistics. Chapman & Hall/CRC.
(here-
after JV)
Errata: http://wiener.math.csi.cuny.edu/UsingR/Errata/
John Fox and Sanford Weisberg. An R Companion to Applied Regression. Sage
Publications, T
Well, what do you want it to look like?
My first thought was topography, but that can't be right because you
don't need a three-dimensional array for that.
So tell us more. What does your array contain, what's its structure,
and what kind of visualization are you trying to get?
Sarah
On Wed, Ma
Hi,
On Wed, May 30, 2012 at 7:48 AM, Dinesh Vakamudi
wrote:
>> results <- mra(x$w1mcp, filter = "d4", n.levels = 3, boundary =
> "periodic", method = "dwt")
>> write.csv(results, "c:/mydata.csv")
I have no idea what mra() is - from what package did it come? I see
there's a package named mra, but
Like Thierrey I entirely disagree with you, but there are many PRNGs
in R -- take a look at ?RNGkind to change them.
Michael
On Wed, May 30, 2012 at 7:39 AM, juliane0212 wrote:
> Hello,
>
> currently I'm working on a model based on Monte-Carlo-Simulations.
>
> I observed that a generated normal
On Tue, May 29, 2012 at 11:26 PM, mahdi wrote:
> In our dataset the samples/object are number of patients which is 128 and we
> are dealing with 12,625 genes which is our
> attributes of the dataset. So, it is obvious that if I calculate the
> correlation matrix of (128 * 12,625) the resulted dime
Hi there,
I am not an expert, but simple experimentation using the acf() function
shows that your statement is not true (see ?acf and ?replicate for more
information):
foo <- function(x) acf(x, plot = FALSE)$acf[,,1]
result <- replicate(1, foo(rnorm(100)))
result <- t(apply(result, 1, quantil
You might try looking at demo(persp) as well.
Michael
On Wed, May 30, 2012 at 9:42 AM, Sarah Goslee wrote:
> Well, what do you want it to look like?
>
> My first thought was topography, but that can't be right because you
> don't need a three-dimensional array for that.
>
> So tell us more. What
Tyrell,
If you want to have the folds contain data from only one site at a
time, you can develop a set of row indices and pass these to the index
argument in trainControl. For example
index = list(site1 = c(1, 6, 8, 12), site2 = c(120, 152, 176, 178),
site3 = c(754, 789, 981))
The first fold
Are the x variables all the same? if so, you can give lm a matrix as
the y variable and it will compute all the different regressions for
each column in the y matrix. The summary function will then return a
list with the summary information for each of the regressions.
If the x variables are not
You have already had one response that
interpreted "learn R" as use R to do
statistics. I have a rather different
interpretation of "learn R". An answer
to that interpretation (learn the
mechanics of the language) is:
http://www.burns-stat.com/pages/Tutor/hints_R_begin.html
If you search the w
If you haven't done so you *must* read an Introduction to R. The only
reason this is a problem is Myarray is a character string, not a function
or expression to be evaluated. I think this will get you what you want
though:
# In the future use the output of ?dput to provide data to this list
(MyMa
Dear all,
The code below is used to generate interval censored data but unfortunately
there is an error with the ifelse which i am not able to rectify.
Can somebody help correct it for me.
Thank you
t<-rexp(20,0.2)
v<-c(0,m,999)
y<-function(t,v){
z<-numeric(length(t ((
s<-numeric(leng
Hi,
I'm trying to do a multiple events model using coxph. I need to choose which
covariates stay in the final model and i'm using anova but it seems that it
doesn't work with robust variances as a error message appears when I try to
do it:
/PWPfit<-coxph(Surv(ini,fim,status)~Sexo+Transmissao+Regi
Hi List
I have a series of zip archives each containing several files. One of these
files is called goCats.txt and I would like to read it into R from the archive.
It's a simple tab delimited text file.
pathToZip <-
'/home/iain/Documents/Work/Results/bovineMacRNAData/deAnalysis/afInfection/comm
Hi,
The error with ifelse() seems to be that you have no idea what ifelse() does.
As far as I can tell, you tried to construct code that does something like this:
y<-function(tdata,v){
z <- rep(NA, length(tdata))
s <- z
for(i in 1:length(tdata)) {
for(j in 1:length(v-1)) {
Iain -
Once you specify the file to unzip in the call to unz, there's no
need to repeat the filename in read.table. Try:
z <- unz(pathToZip, 'goCats.txt', 'r')
zT <- read.table(z, header=TRUE, sep='\t')
(Although I can't reproduce the exact error which you saw.)
On 2012-05-30 06:48, Sarah Goslee wrote:
Hi,
On Wed, May 30, 2012 at 7:48 AM, Dinesh Vakamudi
wrote:
results<- mra(x$w1mcp, filter = "d4", n.levels = 3, boundary =
"periodic", method = "dwt")
write.csv(results, "c:/mydata.csv")
I have no idea what mra() is - from what package did it come?
Hi Phil
Thanks, but this still doesn't work.
Here's a reproducible example (was wrapping my head around these functions
before).
x <- as.data.frame(cbind(rep('a',5), rep('b',5)))
y <- as.data.frame(cbind(rep('c',5), rep('d',5)))
write.table(x, 'x.txt', sep='\t', quote=FALSE)
write.table(y, '
Since your code has things like this:
z<-numeric(length(t ((
either you have a serious problem with your email client or you need
to reread some introductory material and take a hard look at your
code.
Also note that g() doesn't work, because it contains the statement
return(m) but m is undefined
Can i know how to identify words ending with "ing", say
"playing","praying","remembering" etc.
I want to remove such words using removeWords function.
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Hi!!
Thanks everybody...
It works with *filname <- paste("C:/Bonos/", gsub("-", "", Sys.date() ) ,
sep="")*
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___
#sample words
words <- c("fixing","Dog","Carting","kite","running","playing")
#find words ending in 'ing'
result <- regexpr("^[a-zA-Z]+ing$",words)
result
[1] 1 -1 1 -1 1 1
attr(,"match.length")
[1] 6 -1 7 -1 7 7
attr(,"useBytes")
[1] TRUE
# you can use result to take out the offending wo
Can i know how to identify words ending with "ing", say
"playing","praying","remembering" etc.
I want to remove such words using removeWords function.
Thanks,
Akshay
IIM Kozhikode
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My query comes from the background that I want to process my text and want to
remove all the proper nouns..
So, by tagPOS i can tag them as /NNP and then can remove those words from
the whole text.
So, if someone tell me How I can do that, that would be very helpful..!!
Thanks
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Thanx a lot Charlie
BUT
What if I have many sentences (not individual words), where I would want to
remove such words ?
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Dear all
I have a fairly funky problem that I think demands some sort of survival
analysis. There are two Red List assessments for mammals: 1986 and 2008.
Some mammals changed their Red List status between those dates. Those
changes can be regarded as "events" and are "interval censored" in the sen
hi,
i am trying to use the write.csv function but to give a dynamic file name
each time a different one
but i am getting an error that he cannot open the file :
TodayDate<-UniqDate[1] ## this gives "04/02/2012"
FileLocation<-"C:\\Trade Doc\\trade log\\Real account\\sys file\\Test
Data\\Data breake
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