Hi Tony,
Try this:
dataT<-data.frame(Var1=rep(c("Sole","Lack","ABD","Zad"),rep(5,4)),
Var2=rnorm(20,0.5),Var3=runif(20,0.4))
dataT1<-dataT[with(dataT,order(Var1,Var2,Var3)),]
dataT1
Var1 Var2 Var3
12 ABD -0.19842353 0.4333720
13 ABD 0.14050814 0.9194297
11 ABD 1.07544531 0.4539302
14 ABD 1.17039127 0.7840392
15 ABD 1.23533897 0.5105670
6 Lack -0.14460512 0.7106342
10 Lack 0.36935316 0.6118821
9 Lack 0.62868056 0.5915753
-----------------------------------------------
A.K.
----- Original Message -----
From: tony.anderson <tony.ander...@noaa.gov>
To: r-help@r-project.org
Cc:
Sent: Wednesday, May 30, 2012 6:07 PM
Subject: [R] Sorting a data set
I am a novice user of R and am stumbling on how to order a dataset produced
during my session.
I have a 1863 row X 14 column dataset that I want to put out to a file. I want
the output sorted by the first column and then by the second column both in
ascending order. The first column is character and the second is numeric (I
hope). I used an "as.numeric" function to assign that variable. Is there a
reason R would not accept "0" or "00" as a numeric value?
I have tried using the order function but the examples I have seen don't seem
to translate for me. I tried something like this assuming my dataset is called
"data".
datanew<-data[order(var1, var2),]
print(datanew)
This generates an "incorrect number of dimensions" error in the order
function. I also tried listing all the variables in the parentheses.
Your help is appreciated.
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
