Dear all,
When trying to multiply the same matrices repeatedly I get different
results some of the times.
It is not systematic, which is the fact that is giving me more trouble to
try to isolate the problem.
Basically I am doing X %*% B, where X is a Nx2 matrix and B is a vector
with 2 values. I
There has been one update of 'The R Inferno'
made in spring 2011. It is a fairly mild
revision but has changes prompted by a
number of people -- most especially Mark
Difford.
That other Pat Burns may have known about
hockey, but I suspect he was a real laggard
when it came to random portfolios.
I cannot replicate this on, even with 1 milllion reps on:
R version 2.13.1 (2011-07-08)
Platform: i386-pc-mingw32/i386 (32-bit)
or
R Under development (unstable) (2011-08-13 r56733)
Platform: x86_64-pc-mingw32/x64 (64-bit)
Perhaps it is OS dependent (I am away from my linux box at the moment)?
Joshua Wiley vas escriure el dia dt, 13 set 2011:
> I cannot replicate this on, even with 1 milllion reps on:
>
> R version 2.13.1 (2011-07-08)
> Platform: i386-pc-mingw32/i386 (32-bit)
>
> or
>
> R Under development (unstable) (2011-08-13 r56733)
> Platform: x86_64-pc-mingw32/x64 (64-bit)
>
>
Dear R colleagues,
as result of a function a huge list is generated. From this result list
I'd like to extract information.
Think of the list i.e. as an object named "listResult" with the
following form:
[[a]]
[1] [2] [3] [4] [5]
[[b]]
[1] [2] [3] [4] [5]
[[c]]
[1] [2] [3] [4] [5]
where le
On Mon, 12-Sep-2011 at 12:35PM -0700, holly shakya wrote:
|> I have 2 columns for weight. There are NAs in each column but not for the
|> same observation. Some observations have values for both. I would want to
|> prioritize the WT2 values so I would like to do the following:
|>
|> >From this:
On 09/13/2011 03:08 AM, Schatzi wrote:
I updated the code as follows:
dev.new(width=2.5, height=3,mar=c(0,0,0,0))
par(mfrow=c(5,1),mar=c(.5, .5, 1.5, .5), oma=c(.4, 0,.5, 0))
barplot(c(1,1,1,1,1),col=c("white","white","red","white","white"), axes =
FALSE,border=NA)
barplot(c(1,1,1,1,1),col=c("ora
I had a little bit of trouble following what exactly you mean to do
(specifically, I'm having a little bit of trouble understanding your sample
object "listResult" -- is it a list or a set of factors or a list of lists
or something else entirely), but I believe that replacing the `$` operator
with
Hi,
I am new to R. It would be kind if I could get some help on this.
I am using R to estimate Fstats but I am getting following error. a3 is
annual GDP data from 1951 to 2010.
> fs<- Fstats(ecm.model, from=1954, to = 1975,data=a3)
Error in Fstats(ecm.model, from = 1954, to = 1975, data = a3)
Dear List,
I have compiled R on windows 32bit (v 2.12.2). However, I am not
getting the following line:
"Natural language support but running in an English locale" message.
What would be the reason for this behaviour?
-m
PS:
" R version 2.12.2 (2011-02-25)
Copyright (C) 2011 The R Foundati
Hi All,
I am looking for a reference that explains how the randomForest function in
the randomForest package uses the classwt parameter. Here:
http://tolstoy.newcastle.edu.au/R/e4/help/08/05/12088.html
Andy Liaw suggests not using classwt. And according to:
http://r.789695.n4.nabble.com/R-help-
How does sequential classification differ form running a one-off
classifier for each run?
-> Because feedback from the previous round can and needs to be
incorporated into the ext round.
http://lmgtfy.com/?q=R+machine+learning
-> That is a new low. I was hoping to get help, oblivious I was wrong
Thanks for clearing that up
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I'd suggest you read the documentation on Fstats by typing
? Fstats
in your R window. You'll note that from/to are not "time" arguments but
rather indices of the object being passed in. This is the source of your
problem: the documentation also suggests that if you pass from a two-value
vector it
I tried your example code on my laptop running Ubuntu Linux,
and of course it ran --- just as it should (*has* to!) without any
problem; no errors thrown.
This sort of thing should not/does not/cannot happen under
``normal circumstances''. There has to be something wrong
somewhere in your setup
On Tue, 2011-09-13 at 13:46 +0800, 'Ben Ford' wrote:
> Hi all,
>
> I am fairly new to R and I am trying to run mvpart and create a MRT using
> explanatory variables and covariables. I've been following the procedures in
> Numerical Ecoogy with R.
>
> The command (no covariables) which works fine
On Mon, 2011-09-12 at 23:35 -0700, Jay wrote:
> How does sequential classification differ form running a one-off
> classifier for each run?
> -> Because feedback from the previous round can and needs to be
> incorporated into the ext round.
>
>
> http://lmgtfy.com/?q=R+machine+learning
> -> That
> Dear All:
>
> I am calculating the relative importance of a regressor in a linear
> model.
> Does anyone know how I can obtain/install the 'pmvd' computation type? I
> am
> a US user.
>
> Regards,
> Y
>
Hi,
Do you have any specific reason to use the "pmvd" method, especially in
the light of
Hi
I'm trying to use ggplot2 to chart a dataset that I've drawn in from
excel. When I run the qplot command, I get the following error
message:
Error: ggplot2 doesn't know how to deal with data of class character
It feels like I need to coerce one of the fields in my data frame.
Here's the cod
Rolf Turner vas escriure el dia dt, 13 set 2011:
>
> I tried your example code on my laptop running Ubuntu Linux,
> and of course it ran --- just as it should (*has* to!) without any
> problem; no errors thrown.
>
> This sort of thing should not/does not/cannot happen under
> ``normal circumstan
You posed a very vague question: what packages are available for
classification tasks. Then you respond by saying that you have done some
searching to no avail on Rseek, not specifying what it
Providing you with answers is purely voluntary for the people on the
mailing list. Sending vague, incomp
Worik,
On Mon, Sep 12, 2011 at 10:54 PM, Worik R wrote:
> Friends
>
> I am looking at Rcpp and I am a bit stuck on a simple matter.
>
Rcpp questions will likely get more attention on the Rcpp-devel list:
http://lists.r-forge.r-project.org/mailman/listinfo/rcpp-devel
> (I am calling R from c++, i
Xavier Fernández i Marín gmail.com> writes:
> Rolf Turner vas escriure el dia dt, 13 set 2011:
>
[snip]
> > This sort of thing should not/does not/cannot happen under
> > ``normal circumstances''. There has to be something wrong
> > somewhere in your setup. Either your hardware or your sof
Xavier Fernández i Marín gmail.com> writes:
> More elements: In python the same algorithm does not show this strange
> behaviour.
>
Is Python using the same BLAS/LAPACK?
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Jay,
I understood your question, but I don't know any package with a classifier
that uses feedback as input.
I'm looking for something similar, but for regression. If you find
something, please let me know.
André Rossi
2011/9/13 Jay
> How does sequential classification differ form running a o
Hi,
I am working with the lattice package and I want to label to groups in the
xyplots with mathematical expressions.
I short example for this
library(lattice)
Case<-factor(rep(1:2,each=300))
xx<-rnorm(600,0,1)
yy<-rnorm(600,0,1)
xyplot(yy~xx|Case)
This results in two scatter plots with label
Hi all,
I copy metafile boxplot from R to Word. Then save as Pdf file. But I found
there are some unexpected black lines in some plots within this PDF file.
Please give me some advice how to get rid of these black lines in PDF files.
Thanks a lot,
Jim
[[alternative HTML version delet
I am trying to perform Singular Value Decomposition (SVD) on a Term Document
Matrix I created using the 'tm' package. Eventually I want to do a Latent
Semantic Analysis (LSA).
There are 5677 documents with 771 terms (the DTM is 771 x 5677). When I try
to do the SVD, it runs out of memory. I am us
Hi Ben, thanks for your reply.
Your suggestion does not work indeed:
lme(y ~ x, random=list(~1|a:b, ~1|b:c), data=mydata)
Error in getGroups.data.frame(dataMix, groups) :
Invalid formula for groups
Here is a reproducible example of my data:
set.seed(123)
library(lme4)
library(nlme)
It *really* does help to read the documentation for functions. Like most
of the functions in vegan that extract information from ordinations,
ordilabel() extracts information for "axes" 1 and 2 only, by default.
Does
ordilabel(pl$arrows, choices = 1:3)
work for you?
G
Thanks for the suggestion
Hello,
I appreciate this is likely to be an easy question. I am trying to obtain
the residuals from a linear regression where the line is forced to have a
1:1 relationship.
An example of the data:
A<-c(0.9803922, 1.3850416, 0.8241758, 0.000, 0.4672897, 1.1904762,
0.000, 0.9456265,
1.51
Hi Arne,
Any success in finding possible solutions for my problem?
I have tried to experiment with size of sample and I get really bad picture.
I can't get it work even if sample is ~ 1000 obs. And it is way less than I
would like to see working, taking into account my full sample size ~ 540 000
Dear All,
I need to fetch GO ontologies for Homo sapiens with their mappings to
corresponding Uniprot identifiers. I would be using this information to
compare result from a clustering algorithm with existing protein complexes.
This would be a test to check how the clustering algorithm accurately
It *really* does help to read the documentation for functions. Like most
of the functions in vegan that extract information from ordinations,
ordilabel() extracts information for "axes" 1 and 2 only, by default.
Does
ordilabel(pl$arrows, choices = 1:3)
work for you?
G
Thanks for the suggestion
I suspect it is to do with your method of creating the dataframe, I would
check to see if the columns in the df are numeric, which you can do by:
is.numeric(flat_data$time)
for each variable, if it is not numeric (and at least one must be a
character, given the error message) then redefine as a
Hi David,
On Tue, Sep 13, 2011 at 6:00 AM, David Menezes
wrote:
> Hi
>
> I'm trying to use ggplot2 to chart a dataset that I've drawn in from
> excel. When I run the qplot command, I get the following error
> message:
>
> Error: ggplot2 doesn't know how to deal with data of class character
>
>
>
Reply to my own question:
This is due to internationalisation support:
http://cims.nyu.edu/cgi-systems/info2html?%28R-admin.info.gz%29Internati
onalization%2520support
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Mehmet Suzen
S
Thank you very much!
foreach(i=1:length(levels)) %do% {listResult[[i]][[input]]} (instead of
listResult[[i]]$input) does the trick!!!
Sorry for being a little bit confuse in describing the problem.
My example object listResult is meant to be a list-object with several
levels. More concrete: it co
Hi Sandeep,
I am not entirely sure about this but you might be interested in using
clValid package. In which Biological measures seems to be good option to
map function with GO terms. I haven't used it myself.
Neetika
On Tue, Sep 13, 2011 at 1:21 PM, Sandeep Amberkar wrote:
> Dear All,
>
> I
On 13/09/2011 8:50 AM, drflxms wrote:
Thank you very much!
foreach(i=1:length(levels)) %do% {listResult[[i]][[input]]} (instead of
listResult[[i]]$input) does the trick!!!
If both i and input were the same type (numeric or character), you could
also use
listResult[[c(i, input)]]
This style
Just to clarify things before trying to answer: by a "1:1 relationship" do
you mean you want the regression slope to be equal to 1 "no matter what"?
Michael
On Tue, Sep 13, 2011 at 7:03 AM, RCulloch wrote:
> Hello,
>
> I appreciate this is likely to be an easy question. I am trying to obtain
>
On Tue, Sep 13, 2011 at 7:32 AM, RCulloch wrote:
> I suspect it is to do with your method of creating the dataframe,
I think the error is actually triggered by quoting the name of the
data.frame in the qplot call.
I would
> check to see if the columns in the df are numeric, which you can do by:
On 09/13/2011 05:21 AM, Sandeep Amberkar wrote:
Dear All,
I need to fetch GO ontologies for Homo sapiens with their mappings to
corresponding Uniprot identifiers. I would be using this information to
compare result from a clustering algorithm with existing protein complexes.
This would be a test
On Sep 13, 2011, at 4:11 AM, drflxms wrote:
Dear R colleagues,
as result of a function a huge list is generated. From this result
list
I'd like to extract information.
Think of the list i.e. as an object named "listResult" with the
following form:
[[a]]
[1] [2] [3] [4] [5]
[[b]]
[1] [2]
Dear Ross,
lm(y ~ 0 + offset(x)) will do the trick, but the resulting model has no
coefficient estimates and thus can't be used with abline(). You can, e.g.,
get predictions from the model, but I'm not sure what real use it will be to
you.
I hope this helps,
John
---
Hi there,
did you try saving your graph directly as pdf with R, using ?pdf
What you're describing seems more a Word problem.
JC
2011/9/13 Jin Minming :
> Hi all,
>
> I copy metafile boxplot from R to Word. Then save as Pdf file. But I found
> there are some unexpected black lines in some plots wit
On Sep 13, 2011, at 8:30 AM, Timo Schmid wrote:
Hi,
I am working with the lattice package and I want to label to groups
in the xyplots with mathematical expressions.
I short example for this
library(lattice)
Case<-factor(rep(1:2,each=300))
xx<-rnorm(600,0,1)
yy<-rnorm(600,0,1)
xyplot(yy~
yes, that is correct. The idea being that I want to know the residuals of the
data points compared to a 1:1 line (as shown in the plot), if that makes
sense? I appreciate that this might not be considered a typical approach,
and it would probably take a while to explain (defend) why I am doing it!
Ben Bolker vas escriure el dia dt, 13 set 2011:
> You mentioned that you had compiled R yourself.
> Can you replicate this with a stock R binary, i.e. from a
> Red Hat or Ubuntu repository? If not, can you give details of
> your compilation setup, especially if you are using a specialized
> or
And you can easily get these predictions using the following code :
A <- B
;-)
JC
2011/9/13 John Fox :
> Dear Ross,
>
> lm(y ~ 0 + offset(x)) will do the trick, but the resulting model has no
> coefficient estimates and thus can't be used with abline(). You can, e.g.,
> get predictions from the m
On Sep 13, 2011, at 9:30 AM, David Winsemius wrote:
On Sep 13, 2011, at 8:30 AM, Timo Schmid wrote:
Hi,
I am working with the lattice package and I want to label to groups
in the xyplots with mathematical expressions.
I short example for this
library(lattice)
Case<-factor(rep(1:2,each
On Sep 13, 2011, at 9:34 AM, Jean-Christophe BOUËTTÉ wrote:
And you can easily get these predictions using the following code :
A <- B
I had a similar thought in that: resA_B <- A - B would give the
"residuals" from a line through the origin with a slope of 1. No
regression needed
Jim,
I have seen this outcome as well with graphs from time to time and
agree with Jean-Christophe that the bug seems to creep in at the
Windows / Office level. You do not mention your version of Word, but
I have seen this with Word 2000 and Word 2007 (doc and docx) software
and formats, for examp
Hi All!
I have been messing around with this problem for about a week but to no
avail! The following data has been cut down in order to make my question
reproducible. The alldat data frame includes 2 columns: 1 date column and 1
factor column (equity names)).
mydate<-as.Date(c("2001-07-02","2001
Dear JC,
> -Original Message-
> From: Jean-Christophe BOUËTTÉ [mailto:jcboue...@gmail.com]
> Sent: September-13-11 9:35 AM
> To: John Fox
> Cc: RCulloch; r-help@r-project.org
> Subject: Re: [R] Force regression line to a 1:1 relationship
>
> And you can easily get these predictions using
Dear Ross,
But the residuals are just y - x.
Best,
John
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of RCulloch
> Sent: September-13-11 9:19 AM
> To: r-help@r-project.org
> Subject: Re: [R] Force regression line to a 1:1
Hello,
I would like to cut a hclust tree into several groups at a specific
similarity. I assume this can be achieved by specifying the "h" argument
with the specified similarity, e.g.:
clust<-hclust(dist,"average")
cut<-cutree(clust,h=0.65)
Now, I would like to draw rectangles around the branche
Hello!
I have run a simple regression - lm and created a regression object "myreg".
I can see all the coefficients when I print(myreg).
Then I tried to run vif(myreg) from the package "car".
However, it's giving me an error: in vif.lm(regr.f) : there are
aliased coefficients in the model
Very sorr
The error msg is telling you that R cannot evaluate the loss function, so you
should not
expect answers.
You might try examining the data -- Are there NA or Inf entries?
Or prepare a dataframe with just X and Y, sort by X and graph.
Then check the nls computations by sampling, say, every 100 X'
Dear Dimitri,
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Dimitri Liakhovitski
> Sent: September-13-11 10:29 AM
> To: r-help
> Subject: [R] using vif from package "car" - "aliased coefficients in
> the model"
>
> Hello!
>
Hi JC and Bill,
Thanks a lot for your help.
I found that Office 2007 and 2010 both have this problem when I choose to save
as PDF file in Word program. If I copy a graph as bitmap file, then everything
is ok, but not look as nice as metafile. I have tried to use other two tools
(CutePDF and
Hello,
how can I get the similarity value (i.e., the inner cluster similarity) that
was used to cut a hierarchical tree at a specific height?
I would appreciate your help!
Best regards,
Madeleine
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John, you were right.
After I checked: I had MORE predictors that entered the model than
predictors that were left in and that show up in in
summary(myreg)$coeff). That means, some of the predictors were kicked
out from the results.
I have rerun my lm with all the predictors left in and then vif wo
Hi!I'm trying to plot the italian map with provincial administration but I
don't find the right database and packages to do so.Does anyone help me and
tell me how to do???Thanks for your attention
[[alternative HTML version deleted]]
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Hello,
I am trying to use SVM from e1071 package for doing binary classification
and I am having problems in prediction using SVM. I ran a SVM for
X~as.factor(X1)+as.factor(X2)+as.factor(X3),data=data1,cross=10.
str(data1) gives me
data.frame':5040 obs. of 5 variables:
$ X4: int 1 2 3
Hi Ben,
Your suggestions about the offset worked. Thank you!!
Lizzy
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Dear John,
Thank you for that, and for explaining why the abline() command wont/dosen't
work. The approach is based on reviewers comments that I am a tad sceptical
about myself but yet curious enough to test their suggestion..I don't
think it is very straightforward to explain; however, it in
I use ESS and have no problems invoking it when I fire up emacs. When it
loads it tells me, [Previously saved workspace restored]. However, I do not
know how to view that history of commands so I can continue what I was
doing.
Since the buffer begins with ESS, what do I do to view that restor
David & JC,
Excellent point, of course it does - and of course that is (should have
been) obvious!!! That is what I get for taking a reviewers
comment/suggestion as gospel without applying a bit of thought!
I'm off to go and kick myself.
Cheers,
Ross
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htt
Hi there,
I am looking for some help with a loop which uses three list()-objects:
"sequence" has got numbers, "start" and "end" have got the begin/end time
points which should be applied to the numbers in "sequence". length() of all
three objects is identical, length() of vectors stored in "sequen
On Sep 13, 2011, at 9:43 AM, RCulloch wrote:
Dear John,
Thank you for that, and for explaining why the abline() command wont/
dosen't
work. The approach is based on reviewers comments that I am a tad
sceptical
about myself but yet curious enough to test their suggestion..I
don't
think
On Sep 13, 2011, at 11:44 AM, David Winsemius wrote:
On Sep 13, 2011, at 9:43 AM, RCulloch wrote:
Dear John,
Thank you for that, and for explaining why the abline() command
wont/dosen't
work. The approach is based on reviewers comments that I am a tad
sceptical
about myself but yet curi
plot(clust)
rect.hclust(clust, h = 0.65)
Is that what you wanted?
- Original Message -
From: Madeleine Seeland
To: r-help@r-project.org
Cc:
Sent: Tuesday, September 13, 2011 9:25 AM
Subject: [R] help with hclust and cutree
Hello,
I would like to cut a hclust tree into several groups
Hi, I used read.csv(file name, header=T, sep=",") to bring in a csv file I
saved in MS Excel. The strange thing is all the data ended up in one big
column. The number of rows match with the number of observations, but all
the variables got squeezed into one column. Also the first row where the
head
Hello
I wish to extract the row indices from a data.frame in which a column contains
numeric data by calculating the minimum value, but grouped on another column
factor:
An example data.frame:
Codeabsdiff
NY14/3070 2
NY14/3070 4
NY14/3070 1
NY14/5459
Dear R users,
we are trying to build a R package that includes a precompiled shared
library, let's say mylib.so. We created the skeleton of the package
and we moved the mylib.so file into the libs folder that we created at
the same level of the folders man and R. Moreover we created the file
NAMES
Adding to the previous question, I would like to map central Asia along with
those five countries (Kazakhstan, Kyrgyzstan, Uzbekstan, Tajikstan and
Turkmenstan). Please tell us the right data base!!! Thanks a lot!!!
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Hi, I am trying to read a text file located in following paths. I am getting
error if I try to read from long directory.. But if I place the file right
under C, It runs fine. Could anyone tell me how to read table from following
directory path ?
data1 <-read.table("C:\\Documents and Settings Adm
If I create an aggregation like this:
aggregate(lastYear[,8:10],list(Stadium=lastYear$STAD),mean)
I'll get a new data frame, which I can order if I assign it like this:
newFrame <- aggregate(lastYear[,8:10],list(Stadium=lastYear$STAD),mean)
newFrame[order(newFrame$TEMP),]
But.. if I just want t
Dear R cognoscenti,
While having NA as a native type is nifty, it is annoying when making binary
choices.
Question: Is there anything bad about writing comparison functions that
behavior like %in% (which I love) and ignore NAs?
"%>%" <- function(table, x) {
return(which(table > x))
}
Hi Michael,
First of all thanks for your response.
I do know that if I make my stimation on a single data the regression has no
sense but it will be getting sense in the growing next estimations.
I change my asking doubt.
I want to use this regressions as a first filter. Only this.
Can anyone
The following will get you the first stock in each week. Is that useful?
install.packages("surveillance")
library(surveillance)
alldat$year <- isoWeekYear(alldat$mydate)$ISOYear
alldat$week <- isoWeekYear(alldat$mydate)$ISOWeek
alldat <- alldat[order(alldat$year, alldat$week), ]
alldat[!duplicated
It would appear that your file is not a csv file, but we cannot tell for sure
without seeing an example of the data that you are reading in, can you cut and
paste the first few lines of the file? Or post a link to a copy of the file.
If the data is not able to be shared, then create a new (smal
i responded offline the first time, but:
google is your friend: search for R maps and you'll find what I mention
below.
In the future make sure to perform a thorough search of google and the help
forums before you post
That said... you're looking for the maps package
install.packages('maps')
On 13/09/2011 12:42 PM, Timothy Bates wrote:
Dear R cognoscenti,
While having NA as a native type is nifty, it is annoying when making binary
choices.
Question: Is there anything bad about writing comparison functions that
behavior like %in% (which I love) and ignore NAs?
"%>%"<- function(ta
Code <- c(rep("NY14/3070", 3), rep("NY14/5459", 2))
Code <- as.factor(Code)
absdiff <- c(2, 4, 1, 5, 7)
df <- data.frame(Code, absdiff)
which(
paste(df$Code, df$absdiff) ==
paste(
aggregate(df$absdiff, by = list(df$Code), min)$Group.1,
aggregate(df$absdiff, by = list(df$Cod
With the help of Andrie on StackOverflow.com, I was able to learn about
ddply. I have another question that is more trivial and cannot seem to find
help on IRC and do not want to bother Andrie again. I can't seem to figure
out what to google for, so I thought I'd ask here.
I have:
library(plyr)
I suggest changing
Documents and Settings Administrator
to
Documents and Settings\\Administrator
...
JC
2011/9/13 dbonneau :
> Hi, I am trying to read a text file located in following paths. I am getting
> error if I try to read from long directory.. But if I place the file right
> under C, It r
I have read ?zoo but am not sure how to relate the parameters (x,
order.by, frequency, and style) to my data.frame. The structure of the
data.frame is
'data.frame': 11169 obs. of 4 variables:
$ stream : Factor w/ 37 levels "Burns","CIL",..: 1 1 1 1 1 1 1 1 1 1 ...
$ sampdate: Date, format
Dear R users and experts,
I need to modify an exisiting R function from a package. The function/
variable is inside a namespace and I have problems accessing it.
I only need to get access to to corresponding sourcecode. I localised
the "RDX" and "RDB" files. But it seems to be a binary format.
How
The current "classwt" option in the randomForest package has been there since
the beginning, and is different from how the official Fortran code (version 4
and later) implements class weights. It simply account for the class weights
in the Gini index calculation when splitting nodes, exactly as
Hi henri,
R is open source, so you should be able to download the source code of
the package from CRAN.
JC
2011/9/13 Henri Mone :
> Dear R users and experts,
>
> I need to modify an exisiting R function from a package. The function/
> variable is inside a namespace and I have problems accessing i
On Sep 13, 2011, at 12:31 PM, Rawlins, Barry G. wrote:
Hello
I wish to extract the row indices from a data.frame in which a
column contains numeric data by calculating the minimum value, but
grouped on another column factor:
An example data.frame:
Codeabsdiff
NY14/3070
On 13/09/2011 2:28 PM, Henri Mone wrote:
Dear R users and experts,
I need to modify an exisiting R function from a package. The function/
variable is inside a namespace and I have problems accessing it.
I only need to get access to to corresponding sourcecode. I localised
the "RDX" and "RDB" fil
On Sep 13, 2011, at 1:17 PM, bradford wrote:
With the help of Andrie on StackOverflow.com, I was able to learn
about
ddply. I have another question that is more trivial and cannot seem
to find
help on IRC and do not want to bother Andrie again.
It's doubtful that he would have considered
Jean-Christophe BOUËTTÉ gmail.com> writes:
>
> I suggest changing
> Documents and Settings Administrator
> to
> Documents and Settings\\Administrator
>
Please don't cross-post to R-help and Stack Overflow.
People in both places will gladly answer well-posed questions,
but it turns into a was
FYI,
by using
library("R.utils");
pathname <- "C:\\Documents and Settings Administrator\\My
Documents\\My Dropbox\\data.txt";
pathname <- Arguments$getReadablePathname(pathname);
data1 <- read.table(pathname, sep="\t", header=TRUE);
you would get an explanation what is wrong and helps you troubl
Hello All,
I perform a Wilcoxon signed rank test for two sets of data to test whether
they two have significantly different means. I would also like to know the
power of this test.
The third part of this tutorial is similar to what I want except the t
distribution. http://www.cyclismo.org/tutori
> Because in coding, I often end up with big chunks looking like this:
>
> ((mydataframeName$myvariableName > 2 &
> !is.na(mydataframeName$myvariableName)) &
> (mydataframeName$myotherVariableName == "male" &
> !is.na(mydataframeName$myotherVariableName)))
>
> Which is much less readable/maintai
On Tue, 2011-09-13 at 05:18 -0700, Briony wrote:
> It *really* does help to read the documentation for functions. Like most
> of the functions in vegan that extract information from ordinations,
> ordilabel() extracts information for "axes" 1 and 2 only, by default.
It also helps if I read the doc
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