Hi:
A box plot is based on a five number summary, so you need at a minimum five
observations (and preferably at least twice that) to make a box plot a
viable summary measure for a continuous variable. Consider other graphical
summaries for these data - perhaps a strip chart or a simple scatterplot
No,even there's only one observation,boxplot can still be drawn.
x<-1
boxplot(x)
or
x<-1:3
boxplot(x)
...
2011/3/9 Dennis Murphy
> Hi:
>
> A box plot is based on a five number summary, so you need at a minimum five
> observations (and preferably at least twice that) to make a box plot a
> v
> FWIW, the style for JSS now enforces (via Achimitization) the use of quotes
> as you show above.
>
An excellent candidate for the fortunes package!
best, Ingmar
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https:
On Wed, Mar 9, 2011 at 9:57 AM, Ingmar Visser wrote:
>> FWIW, the style for JSS now enforces (via Achimitization) the use of quotes
>> as you show above.
>>
>
> An excellent candidate for the fortunes package!
>
We should probably address Achim for that. :)
Regards
Liviu
> best, Ingmar
>
>
How can I extract the adjusted R^2 value from an ols object (using rms package)?
library(rms)
x <- rnorm(10)
y <- x + rnorm(10)
ols1 <- ols(y ~ x)
Typing "ols1" displays adjusted R^2 among other things, but how can I
assign it to a variable? I tried str(ols1) but couldn't see where to
go from the
Hi,
If you look in the print.ols function you can see that the adjusted R^2
is not stored in the ols object but calculated on the fly, the relevant
code snippet from that function looks to be:
x <- ols1
stats <- x$stats
resid <- x$residuals
n <- length(resid)
ndf <- stats["d.
Hi,
try this:
d <- rbind(data.frame(M=1, v=1:2, m1), data.frame(M=2, v=1:2, m2))
ggplot(d, aes(v, ymin=lo, y=m, ymax=hi, colour=factor(M))) +
geom_line(position=position_dodge(width=0.1)) +
geom_pointrange(position=position_dodge(width=0.1))
--
Kohske Takahashi
Research Center for Advance
Dear R experts,
I've written some functions in a few source files (such as main.R,
control.R ...).
After loading them into R, how do I retrieve which functions are loaded
from which source file?
For example:
main.R has functions: myPrint(), myScan()
control.R has functions: setPrinter(), se
Hello. I would like to know if there exists in R a function like trunc but
where i can choose how many decimal places can I stay with in the number I
have (sort of the same as the trunc function in excel). I would like, for
example if I have the number 0.974678 and I choose to stay with 3 decimal
p
Hi,
There might be better solution, but I think this works (got it by
searching "source function" with RSiteSearch()):
attr(body(myPrint), "srcfile")
Here is the original answer:
http://finzi.psych.upenn.edu/Rhelp10/2010-February/227805.html
HTH,
Ivan
Le 3/9/2011 10:19, raymondowf a écrit :
Hola Felipe,
Sí, la función es round().
Por cierto, tenemos una lista de ayuda del R en español.
Te puedes suscribir aquí:
https://stat.ethz.ch/mailman/listinfo/r-help-es
Saludos,
Carlos Ortega
www.qualityexcellence.es
On Wed, Mar 9, 2011 at 10:36 AM, Luis Felipe Parra <
felipe.pa...@quantil.
Dear Johan,
A few remarks.
- R-sig-mixed models is a better list for asking questions about mixed model.
- I presume that Nymphs is the number of insects? In that case you need a
generalised linear (mixed) model with poisson family
- What are you interessed in? The variability among genotypes or
Dear Lao and Dennis,
Thanks for your reply, now it is working as expected by using
height=cbind(c(data[1,],data[2,],data[3,])
Gaurav Kumar
www.gauravkumar.org
PhD Student, Chemistry and Biomolecular Sciences, Macquarie , Sydney, Australia.
MS (Computational Biology), NCBS-TIFR, Bangalore, India
On Wed, Mar 09, 2011 at 05:36:35PM +0800, Luis Felipe Parra wrote:
> Hello. I would like to know if there exists in R a function like trunc but
> where i can choose how many decimal places can I stay with in the number I
> have (sort of the same as the trunc function in excel). I would like, for
>
Dear All
I would like to know how can I call user defined R function from JRI. I
stored my function (UCS) in the working directory and I load that function
into the program using
Rengine re=*new* Rengine(args, *false*, *null*); re.eval("source('UCS')")
* *But *re.eval("UCS()")*, is not working.
Hi Shira,
Check out "venneuler"
http://cran.r-project.org/web/packages/venneuler/index.html
Labelling can be a little tricky, but if you search this forum for
"venneuler" you'll find some tips which helped me.
hth,
karl
On 03/09/2011 02:25 AM, Shira Rockowitz wrote:
I was wondering if an
On 09.03.2011 10:00, Liviu Andronic wrote:
On Wed, Mar 9, 2011 at 9:57 AM, Ingmar Visser wrote:
FWIW, the style for JSS now enforces (via Achimitization) the use of quotes
as you show above.
An excellent candidate for the fortunes package!
We should probably address Achim for that. :)
On 11-03-09 4:41 AM, Ivan Calandra wrote:
Hi,
There might be better solution, but I think this works (got it by
searching "source function" with RSiteSearch()):
attr(body(myPrint), "srcfile")
That's the right way, but it only works if srcrefs (debug information)
is kept. By default source()
On 2011-03-09 01:25, Martyn Byng wrote:
Hi,
If you look in the print.ols function you can see that the adjusted R^2
is not stored in the ols object but calculated on the fly, the relevant
code snippet from that function looks to be:
x<- ols1
stats<- x$stats
resid<- x$residuals
On Mar 09, 2011; 11:09am Mark Seto wrote:
>> How can I extract the adjusted R^2 value from an ols object (using rms
>> package)?
>> library(rms)
>> x <- rnorm(10)
>> y <- x + rnorm(10)
>> ols1 <- ols(y ~ x)
##
ols1$stats
ols1$stats[4]
Regards, Mark.
--
View this message in context:
http:/
Thanks Ivan!
You've solved my problem!!
--
View this message in context:
http://r.789695.n4.nabble.com/Getting-the-source-file-s-name-where-the-custom-function-is-written-tp3343135p3343197.html
Sent from the R help mailing list archive at Nabble.com.
_
Hi Everyone,
I have the following problem:
data <- structure(list(prochi = c("IND1", "IND1", "IND1",
"IND2", "IND2", "IND2", "IND2", "IND3",
"IND4", "IND5"), date_admission = structure(c(6468,
6470, 7063, 9981, 9983, 14186, 14372, 5129, 9767, 11168), class = "Date")),
.Names = c("prochi",
"da
On 2011-03-09 00:17, Lao Meng wrote:
No,even there's only one observation,boxplot can still be drawn.
x<-1
boxplot(x)
or
x<-1:3
boxplot(x)
...
Well, yes, it *can* be drawn. But it shouldn't be.
A boxplot based on fewer than, say, 10 values is
just nonsense. Even 10 is pretty dubious.
Anyway,
Thanks Allen,
my R installation:
platform i686-pc-linux-gnu
arch i686
os linux-gnu
system i686, linux-gnu
status
major 2
minor 11.1
year 2010
month 05
day31
svn rev52157
language R
version.string R ve
Hi all,
I am hoping that someone can help me with a problem I am having with column
headings. I have read a table into R using read.table: the rows are
documents, and the columns are counts of regular expression matches (so that
the column heading is the given regular expression). My problem is
Dear R helpers,
xx = data.frame(country = c("USA", "UK", "Canada"), x = c(10, 50, 20), y =
c(40, 80, 35), z = c(70, 62, 10))
> xx
country x y z
1 USA 10 40 70
2
UK 50 80 62
3 Canada 20 35 10
I need to arrange this as a new data
reshape2 Like this?
> require(reshape2)
Loading required package: reshape2
> melt(xx)
Using country as id variables
country variable value
1 USAx10
2 UKx50
3 Canadax20
4 USAy40
5 UKy80
6 Canaday35
7 U
On Wed, Mar 9, 2011 at 8:52 AM, Matthew DeAngelis wrote:
> Hi all,
>
> I am hoping that someone can help me with a problem I am having with column
> headings. I have read a table into R using read.table: the rows are
> documents, and the columns are counts of regular expression matches (so that
>
Hi,
This might seem like a simple question but at the moment I am stuck for ideas.
The columns of my matrix in which some data is stored are of this form:
X1 Y1 X2 Y2 X3 Y3 ... Xn Yn
with n~100. I would like to look at just the X values (i.e. odd column
numbers)
oddvals <- seq(1, ncol(mydata), by=2)
mydata[,oddvals]
On Wed, Mar 9, 2011 at 9:20 AM, Nixon, Matthew wrote:
> Hi,
>
> This might seem like a simple question but at the moment I am stuck for
> ideas. The columns of my matrix in which some data is stored are of this form:
>
> X1 Y1 X2
one way is using the seq(), e.g., say 'm' is your matrix, then try:
m[, seq(1, ncol(m), by = 2)]
I hope it helps.
Best,
Dimitris
On 3/9/2011 3:20 PM, Nixon, Matthew wrote:
Hi,
This might seem like a simple question but at the moment I am stuck for ideas.
The columns of my matrix in which
Hi,
I try to install vegan package on debian linux and I give this error:
=
* installing *source* package 'vegan' ...
** libs
make: *** No rule to make target `cepin.o', needed by `vegan.so'. Stop.
*** arch - Rgnome
Warning in file(con, "r") :
ca
I'm wondering how the cex parameter is used to scale circles (i.e. does it
scale the radius, diameter, area, circumference, etc.?). In my case I'm using
lattice with filled circles (pch=19).
Based on example, it looks like R scales the radius of the circle:
library(lattice)
dta<-data.frame(x
On Wed, 2011-03-09 at 11:41 -0300, Ronaldo Reis-Jr. wrote:
> Hi,
>
> I try to install vegan package on debian linux and I give this error:
Have you got a fortran compiler installed on your system? gcc-gfortran
is the package on my Fedora laptop.
G
> =
R users,
I am trying to generate a randomized weekday survey schedule that ensures even
coverage of weekdays in
the sample, where the distribution of variable DOW is random with respect to
WEEK. To accomplish this I need
to randomly sample without replacement two weekdays per week for each of
Gavin,
yes, I have GCC, Gfortran,
[root@amandix ~]# gcc --version
gcc (Debian 4.5.2-5) 4.5.2
[root@amandix ~]# gfortran --version
GNU Fortran (Debian 4.5.2-5) 4.5.2
[root@amandix ~]# make --version
GNU Make 3.81
I have another linux installed that I dont have any problem, the
installations a
Hello all,
A question for plotting of intamap results :
Is it possible, and in so, how, to specify the cutoff points for changing
colors of plots ?
Using the example :
data(meuse)
meuse$value = log(meuse$zinc)
data(meuse.grid)
coordinates(meuse) = ~x+y
coordinates(meuse.grid) = ~x+y
object = in
Thank you for your prompt reply, I apologize for posting as an R
Commander question. Your response is pointing me in the right
direction, but I am still not quite there. The triangle package has
a qtriangle and dtriangle. The formal arguments are a, b, and c.
(formals(qtriangle)) When I use R
Dear Dick,
> -Original Message-
> From: Richard and Barbara Males [mailto:rbma...@gmail.com]
> Sent: March-09-11 10:54 AM
> To: John Fox
> Cc: r-help@r-project.org
> Subject: Re: [R] R Commander QQ Plot with triangular distribution
>
> Thank you for your prompt reply, I apologize for post
(Just expanding a bit on the previous response)
"weird" is in the eye of the beholder...
A POSIXlt object is actually a list, and subtracting a number from a list
[as in an expression like list(a=1,b=2) - 3] does not make sense. But
POSIXct objects are actually numbers, and adding a number to a n
On 2011-03-09 07:53, Richard and Barbara Males wrote:
Thank you for your prompt reply, I apologize for posting as an R
Commander question. Your response is pointing me in the right
direction, but I am still not quite there. The triangle package has
a qtriangle and dtriangle. The formal argum
Try the posting guide, and do remember to give the 'at a minumum'
information you were asked for.
I suspect this is not a recent version of R (but you were asked to
update before posting). If it is, please explain what
/usr/local/bin/Rgnome is doing in the R installation -- it was last
suppo
'cex' means character expansion. It is linear magnification: that is
all linear dimensions (including height and width) are proportional to
cex).
You are confusing matters by giving a lattice example. 'cex' is a
concept from base graphics (see ?par, which I believe is unambiguous
in saying
Wow, quick response, works perfectly, just as needed.
Thanks to both of you for pointing me in the right direction, and for
your contributions to the R community.
Dick
On Wed, Mar 9, 2011 at 11:21 AM, Peter Ehlers wrote:
> On 2011-03-09 07:53, Richard and Barbara Males wrote:
>>
>> Thank you fo
Hi,
I try with --no-multiarch and it work now.
I use the same R version in both systems:
R version 2.12.2 (2011-02-25)
Copyright (C) 2011 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
Platform: i486-pc-linux-gnu (32-bit)
Now, how to make the --no-multiarch option default to R in
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of Hosack, Michael
> Sent: Wednesday, March 09, 2011 7:34 AM
> To: r-help@R-project.org
> Subject: [R] Complex sampling?
>
> R users,
>
> I am trying to generate a randomized weekda
Hi terdon,
Very happy to help and know it worked.
Honestly, I do not know exactly where the differences are, but it is not
hard to check the sources and compare both algorithms. When doing this, you
can can see that p.adjust() uses vectorization whereas mt.rawp2adjp() does
not. Perhaps that is th
Hello,
I work for a company in which a number of employees use R. Many of them like to
run executables via the system function in such a way that the output of that
executable is displayed in a separate window. To give an example of the
behavior they require, the following command can be run in
Darcy Webber gmail.com> writes:
> Dear R helpers,
>
> I think that this may be a bit of a math question as the more I
> consider it, the harder it seems. I am trying to come up with a way to
> work out the minimum distance between line segments. For instance,
> consider 20 random line segments:
Or, if X1 Y1 X2 Y2... are really your column names
m[, grep("X",colnames(m)) ]
or
m[, grepl("X",colnames(m)) ]
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Dimitris Rizopoulos
Sent: Wednesday, March 09, 2011 9:36 AM
To: Nixon, Ma
> -Original Message-
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org]
> On Behalf Of Hosack, Michael
> Sent: Wednesday, March 09, 2011 7:34 AM
> To: r-help at R-project.org
> Subject: [R] Complex sampling?
>
> R users,
>
> I am trying to generate a randomiz
It sounds like you want a bunch of random permutations of 1:7.
Try order(runif(7))
If you need, say, 10 of them:
as.vector(sapply(1:10,function(i) order(runif(7
Is it more complicated than that?
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org
What I think you need is something along the lines of:
matrix(c(sample(3:7), sample(3:7), sample(3:7), sample(3:7), ...), nrow=2)
now, each column are your random pairs.
-Aaron
On Wed, Mar 9, 2011 at 1:01 PM, Hosack, Michael wrote:
> > -Original Message-
> > From: r-help-bounces at r-
Rex:
sample(n)
is a much better way to get random permutations of 1:n.
To be clear, this is sample(n,replace = FALSE) , the default.
(I have no idea whether this is what the poster needs. I just wanted
to correct the clumsy order(runif) construction).
-- Bert
On Wed, Mar 9, 2011 at 10:28 AM,
Try this:
m <- matrix(rnorm(12), ncol = 4)
m[,c(FALSE, TRUE)]
On Wed, Mar 9, 2011 at 11:20 AM, Nixon, Matthew wrote:
> Hi,
>
> This might seem like a simple question but at the moment I am stuck for
> ideas. The columns of my matrix in which some data is stored are of this
> form:
>
> X1 Y1
Try this:
reshape(xx, direction = "long", varying = list(2:4), idvar = "country")
On Wed, Mar 9, 2011 at 11:15 AM, Vincy Pyne wrote:
> Dear R helpers,
>
> xx = data.frame(country = c("USA", "UK", "Canada"), x = c(10, 50, 20), y =
> c(40, 80, 35), z = c(70, 62, 10))
>
> > xx
>country
See ?aperm for changing the dimensions afterwards.
Uwe Ligges
On 08.03.2011 10:14, Folkes, Michael wrote:
Hello all,
I'm working with a matrix that will have varying dimensions. It will populate
an array such that the number of matrix columns will determine the number of
3rd dimension level
install.packages(, lib='/usr/local/lib/R/site-library')
otherwise you have to ensure that this library is the first one in
.libPaths() and watch out that it is not changed by any of the many
mechanisms that allow for adding libraries to the search path.
Uwe
On 09.03.2011 00:53, Frank Ha
I see something similar on my system. Running your command line, I
can see the command window flashup and then disappear.
> sessionInfo()
R version 2.12.1 (2010-12-16)
Platform: i386-pc-mingw32/i386 (32-bit)
locale:
[1] LC_COLLATE=English_United States.1252 LC_CTYPE=English_United
States.1252
[
I want to thank everyone who offered advice for the assistance, but the
responses so far have not taken into
account that the sampling needs to progress through weeks, retaining
information from one week to the next.
I represented that retained information by a vector that when full is equal
Hello Venerable List,
I am trying to loop (I think) an operation through a list of columns in a
dataframe to remove set of #DIV/0! values. I am trying to do this like so:
#Data.frame
test <- read.csv("http://dl.dropbox.com/u/1574243/sample_data.csv";,
header=TRUE, sep=",")
#This removes all the
--
Jonathan P. Daily
Technician - USGS Leetown Science Center
11649 Leetown Road
Kearneysville WV, 25430
(304) 724-4480
"Is the room still a room when its empty? Does the room,
the thing itself have purpose? Or do we, what's the word... imbue it."
- Jubal E
I have a file with a data in columnar format like below:
probeID
rc_AI104113_at
rc_AI178259_f_at
rc_AI179134_i_at
rc_AI179134_f_at
rc_AI104113_at
rc_AA819429_f_at
How can I rewrite it in the format below:
'rc_AI104113_at', 'rc_AI178259_f_at', 'rc_AI179134_i_at',
'rc_AI179134_f_at', 'rc_AI104113_
I tried:
> data(state.x77)
Warning message:
In data(state.x77) : data set 'state.x77' not found
data(iris) seems to work fine, but the other state datasets (which I havenât
every tried before) donât seem to be available
on my windows 7 running R 2.12.2 installation.
?state brings up the sta
Hi,
On Wed, Mar 9, 2011 at 3:35 PM, Fahim Mohammad wrote:
> I have a file with a data in columnar format like below:
>
> probeID
> rc_AI104113_at
> rc_AI178259_f_at
> rc_AI179134_i_at
> rc_AI179134_f_at
> rc_AI104113_at
> rc_AA819429_f_at
>
> How can I rewrite it in the format below:
> 'rc_AI104
On 09/03/2011 2:34 PM, jim holtman wrote:
I see something similar on my system. Running your command line, I
can see the command window flashup and then disappear.
We have had issues in the past with setting the input file handle for
external commands to an empty stream. Then cmd
reads from
Hi Rob,
I'm not sure exactly what state is, but this works:
data(state)
head(state.x77) #or whatever
Best,
Ista
On Wed, Mar 9, 2011 at 3:45 PM, wrote:
> I tried:
>> data(state.x77)
> Warning message:
> In data(state.x77) : data set 'state.x77' not found
>
> data(iris) seems to work fine, b
Hello!
I have a date (a Monday):
date<-20081229
mydates<-as.Date(as.character(date),"%Y%m%d")
What package would allow me to create a vector that starts with that
date (mydates) and contains dates for 51 Mondays that follow it (so,
basically, 51 dates separated by a week)?
Thanks a lot for the
Hi Sam,
How about this?
test[apply(test, 1, function(x) !any(x == '#DIV/0!')), ]
HTH,
Jorge
On Wed, Mar 9, 2011 at 3:29 PM, Sam Albers <> wrote:
> Hello Venerable List,
>
> I am trying to loop (I think) an operation through a list of columns in a
> dataframe to remove set of #DIV/0! values. I
I realize I can do something like this:
date<-20081229
mydates<-as.Date(as.character(date),"%Y%m%d")
for(i in 1:52){ #
mydates<-c(mydates,mydates[length(mydates)]+7)
}
I just thought maybe there is a more elegant way...
Thank you!
Dimitri
On Wed, Mar 9, 2011 at 4:04 PM, Dimitri Liakhovitski
On Wed, Mar 9, 2011 at 3:04 PM, Dimitri Liakhovitski
wrote:
> Hello!
>
> I have a date (a Monday):
>
> date<-20081229
> mydates<-as.Date(as.character(date),"%Y%m%d")
>
> What package would allow me to create a vector that starts with that
> date (mydates) and contains dates for 51 Mondays that fol
Hi there,
I recently switched to Mac and I wonder if there is any way to get the R
console to autocomplete names of list objects or slots of objects. The
command line version allows to type e.g. list$ and two times the tab
button and then comes up with the names of the list objects. Same for slots
Dear all,
When I ran a frailty model like,
model <- coxph(Surv(Day, Indicator) ~ trt + frailty(group,
distribution="gaussian"))
The variance of effect estimate of trt was estimated by conditional model or
marginal model?
Thanks.
Alex
[[alternative HTML version deleted]]
_
Fellow R programmers,
I'd like to submit SQLDF statements with R objects as column names.
For example, I want to assign "X" to "var1" (var1<-"X") and then refer to
"var1" in the SQLDF statement. SQLDF needs to understand that when I
reference "var1", it should look for "X" in the dataframe.
Th
hi:
when I run the example program on windows XP+NetBeans:
Rserve_0.6-3\Rserve\src\client\javanew\Rserve\test\test.java
{ // test control commands (works only when enabled and in Rserve 0.6-0 and
higher only) - must be the last test since it closes the connection and shuts
down the server
Syst
Hi,
I am processing tick data and my code has stopped working as I have
increased the size of data being processed. Now I am receiving error for
basic tasks in RConsole:
> a = c(1:1000)
Error: evaluation nested too deeply: infinite recursion /
options(expressions=)?
My R code worked fine with 5
Hi,
I am trying to understand how the biplot.prcomp is constructed so I can
manipulate it to emphasise particular observations and reduce the number of
variables shown.
The prcomp model I have ran has cor=TRUE and scale=TRUE
I have worked out from looking at str(prcomp.model) that...
prcomp.mode
Thank you very much, Professor Ripley.
Date: Tue, 8 Mar 2011 22:54:38 -0800
From: ml-node+3342906-500442411-213...@n4.nabble.com
To: jeanne...@hotmail.com
Subject: Re: Any interim update for the basic packages distributed with R?
This is what the R-patched and R-devel versions of R are for.
Hi,
I am using Rattle 2.6.4 with R 2.12.2 on win64, is this a bug ?
Following is the content after execute the associate analysis process:
Summary of the Apriori Association Rules:
Number of Rules: 23351
Summary of the Measures of Interestingness:
support confidence lift
Min.
You might look at the function confusion() in the DAAGxtras package.
John Maindonald email: john.maindon...@anu.edu.au
phone : +61 2 (6125)3473fax : +61 2(6125)5549
Centre for Mathematics & Its Applications, Room 1194,
John Dedman Mathematical Sciences Building (Building 27)
Austr
Dear all,
Probably a rather stupid question, but I couldn't find the answer..
I currently have a dataframe with customers' id's and purchase amount, what
I would like to do is to show the difference between amount purchased
compared to the month before per customer.
I have made some attempts my
It means that dat$v1, dat$v2, . . . are not columns in the data frame df
Specify the formula as v1 ~ v2+v2+v3+v4+v5+factor
Then (assuming that factor is a column object of the right length)
you should be fine.
John Maindonald email: john.maindon...@anu.edu.au
phone : +61 2 (6125)3473
Hi:
I'm not quite sure what you have in mind, but...
Input data strdat.txt:
probeID
rc_AI104113_at
rc_AI178259_f_at
rc_AI179134_i_at
rc_AI179134_f_at
rc_AI104113_at
rc_AA819429_f_at
strg <- paste(scan('strdat.txt', what = '', skip = 1), collapse = ',')
strg
[1]
"rc_AI104113_at,rc_AI178259_f_at,r
The compiler/optimization flags I use (or am experimenting with are) for
the Linux 64bit Intel XE compilers and R-2.12.2 are:
-O3 -ipo -msse3 -fp-model precise
export AR=xiar # not needed when using -ip
instead of -ipo
#export MAIN_LDFLAGS="-limf -lpthread"
Hi,
The r-sig-mac mailing list is probably a better bet for this sort of
question. https://stat.ethz.ch/mailman/listinfo/r-sig-mac
Best,
Ista
On Wed, Mar 9, 2011 at 9:47 AM, Unger, Kristian, Dr.
wrote:
> Hi there,
>
> I recently switched to Mac and I wonder if there is any way to get the R
> cons
For further info, I cannot check my memory usage or even use ls() :
> memory.limit
Error: evaluation nested too deeply: infinite recursion /
options(expressions=)?
> ?memory.limit
Error: evaluation nested too deeply: infinite recursion /
options(expressions=)?
> ls()
Error: evaluation nested too d
> To: r-h...@stat.math.ethz.ch
> From: hwborch...@googlemail.com
> Date: Wed, 9 Mar 2011 17:45:53 +
> Subject: Re: [R] minimum distance between line segments
>
> Darcy Webber gmail.com> writes:
>
> > Dear R helpers,
> >
> > I think that this may b
On Mar 9, 2011, at 21:57 , Ista Zahn wrote:
> Hi Rob,
> I'm not sure exactly what state is, but this works:
>
>
> data(state)
>
> head(state.x77) #or whatever
Actually, you don't even need data(state); state.* are available as lazy-loaded
objects. However, if you do, you get copies of the o
There does seem to be something odd about StructTS, or perhaps the methodology.
Try:
> data(AirPassengers)
> ap <- log10(AirPassengers)-2
> (fit <- StructTS(ts(ap[1:138], freq=12), type="BSM"))
Call:
StructTS(x = ts(ap[1:138], freq = 12), type = "BSM")
Variances:
level slope
Hi Rens,
One way would be
x$difference <- do.call(c, with(x, tapply(amount, customer, function(x) c(0,
diff(x)
x
Take a look at ?tapply and ?aggregate for more information.
HTH,
Jorge
On Wed, Mar 9, 2011 at 10:27 AM, rens_1112 <> wrote:
> Dear all,
>
> Probably a rather stupid question,
On Wed, Mar 9, 2011 at 11:41 AM, Mike Schumacher
wrote:
> Fellow R programmers,
>
> I'd like to submit SQLDF statements with R objects as column names.
>
> For example, I want to assign "X" to "var1" (var1<-"X") and then refer to
> "var1" in the SQLDF statement. SQLDF needs to understand that wh
You're submitting queries for SQLDF to execute as strings. So, if you want
to use a variable column name, sprintf() or paste() your statement together,
like:
sqldf(sprintf('select sum(%s) as XSUM, Y as Y from testdf group by Y',
var1))
--
Robert Tirrell | r...@stanford.edu | (607) 437-6532
Progra
Hi Dennis and Ista,
Thanks a lot.
The solution is great.
Actually I am trying to do bulk select from database and it require where
clause in this form only.
inpData = read.csv('./rugitSrc/testFile.csv', header= TRUE)
idList = as.character(inpData[,1])
1> idList
[1] "rc_AI104113_at" "rc_AI178259
On Wed, Mar 9, 2011 at 4:13 PM, Dimitri Liakhovitski
wrote:
> I realize I can do something like this:
> date<-20081229
> mydates<-as.Date(as.character(date),"%Y%m%d")
> for(i in 1:52){ #
> mydates<-c(mydates,mydates[length(mydates)]+7)
> }
>
> I just thought maybe there is a more elegant way...
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of Hosack, Michael
> Sent: Wednesday, March 09, 2011 11:59 AM
> To: r-help@R-project.org
> Subject: Re: [R] Complex sampling?
>
>
>
> I want to thank everyone who offered advice f
Hi:
Here's another approach:
purchase_amount <- transform(purchase_amount,
diff = with(purchase_amount, ave(amount, customer, FUN =
function(x) c(0, diff(x)
purchase_amount
HTH,
Dennis
On Wed, Mar 9, 2011 at 7:27 AM, rens_1112 wrote:
> Dear all,
>
> Probably a rather stupid quest
Hello,
I have a file that looks like this:
Date,Hour,DA_DMD,DMD,DA_RTP,RTP,,
1/1/2006,1,3393.9,3412,76.65,105.04,,
1/1/2006,2,3173.3,3202,69.20,67.67,,
1/1/2006,3,3040.0,3051,69.20,77.67,,
1/1/2006,4,2998.2,2979,67.32,69.10,,
1/1/2006,5,3005.8,2958,65.20,68.34,,
where the ',' is the separator a
I try to calculate descriptive statistics for one of the variables in the
data frame, however command sapply calculates these statistics for every
value of the variable separately. How to make it calculate range (as well as
other statistics) for all column?
Here are commands and results:
> as1$tr
Thanks Uwe. Too bad there is no system option I can set one time, that will
always take precedence.
Frank
Uwe Ligges-3 wrote:
>
> install.packages(, lib='/usr/local/lib/R/site-library')
>
> otherwise you have to ensure that this library is the first one in
> .libPaths() and watch out th
Easiest is to use 'header = TRUE' and use the data from the file as
the header (remove the skip=1). Let the system determine what it
should be and then you can change it later.
On Wed, Mar 9, 2011 at 5:32 PM, Giovanni Petris wrote:
>
> Hello,
>
> I have a file that looks like this:
>
> Date,Hour
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