I have a data.frame as the following:
var1var2
9G/G09abd89C/T90
10A/T932C/C
90G/G A/A
. .
. .
. .
10T/C 00G/G90
What I want is to get the letters which are on the left and right of '/'.
for example, for "9G/G09", I only want "G", "G",
You may want to try read.delim if you are having troubles with
read.table.
Jim
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of dhanush
Sent: Thursday, June 03, 2010 4:33 AM
To: r-help@r-project.org
Subject: [R] import text file int
I can get the interactions between factors like this:
> idx=c(1,3,6,9)
> jdx=idx
> levels(interaction(idx,jdx,lex.order=TRUE))
[1] "1.1" "1.3" "1.6" "1.9" "3.1" "3.3" "3.6" "3.9" "6.1" "6.3" "6.6"
"6.9"
[13] "9.1" "9.3" "9.6" "9.9"
This list contains all possible interactions. Whereas I need
Dear R People:
Is there a sig for people using R and C++, please?
Thank you in advance,
Sincerely,
Erin
--
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodg...@gmail.com
___
On Jun 3, 2010, at 2:08 PM, Alex van der Spek wrote:
> I can get the interactions between factors like this:
>
> > idx=c(1,3,6,9)
> > jdx=idx
> > levels(interaction(idx,jdx,lex.order=TRUE))
> [1] "1.1" "1.3" "1.6" "1.9" "3.1" "3.3" "3.6" "3.9" "6.1" "6.3" "6.6" "6.9"
> [13] "9.1" "9.3" "9.6" "9.9
Hi Alex,
Here is a suggestion:
apply(combn(idx, 2), 2, paste, collapse = ".")
See ?combn, ?apply and ?paste for more information.
HTH,
Jorge
On Thu, Jun 3, 2010 at 3:08 PM, Alex van der Spek <> wrote:
> I can get the interactions between factors like this:
>
> > idx=c(1,3,6,9)
> > jdx=idx
>
Perhaps not the best or easiest way, but does:
apply(t(combn(idx,2)),1,paste,collapse='.')
[1] "1.3" "1.6" "1.9" "3.6" "3.9" "6.9"
get you in the right direction?
- Phil Spector
Statistical Computing Facility
On Jun 3, 2010, at 2:10 PM, Erin Hodgess wrote:
> Dear R People:
>
> Is there a sig for people using R and C++, please?
>
> Thank you in advance,
> Sincerely,
> Erin
That subject matter would tend to go to R-Devel:
https://stat.ethz.ch/mailman/listinfo/r-devel
The full list of "official" R
Thank you Greg,
I'll add 180 then.
Thanks for the hint with longer radial.lim arguments it works woderfull.
> The lines function is plotting in Cartesian coordinates, not the polar
> coordinates.
Is there any (lines) function that plots polar coordinates to an existing plot?
Thank you very mu
Better yet, is shorter using tranform instead of summarise:
Data <- read.table(textConnection("variable Year value
EC01 2005 5
EC01 2006 10
AAO1 2005 2
AAO1 2006 4"),header=T)
ddply(Data,.(variable),transform,CUM
Dear R´ers..
In this mock dataset how can I generate a logical variable based on whether
just tes or tes3 are NA in each row??
test<-sample(c("A",NA,"B"),100,replace=T)
test2<-sample(c("A",NA,"B"),100,replace=T)
test3<-sample(c("A",NA,"B"),100,replace=T)
tes<-cbind(test,test2,test3)
sam<-c("t
?any
Not really a reproducible answer, but I think you're looking
for
apply(tes[,sam],1,function(x)any(is.na(x)))
- Phil Spector
Statistical Computing Facility
Department o
Or better yet, you can use transform only (in base):
transform(Data, CUMSUM = cumsum(value))
HTH,
Jorge
On Thu, Jun 3, 2010 at 3:30 PM, Felipe Carrillo <> wrote:
> Better yet, is shorter using tranform instead of summarise:
> Data <- read.table(textConnection("variableYear value
>
Also, in the Rcpp-devel mailing list:
https://lists.r-forge.r-project.org/cgi-bin/mailman/listinfo/rcpp-devel
we do talk a lot about R and C++, mainly because that is what Rcpp is
all about.
Le 03/06/10 21:21, Marc Schwartz a écrit :
On Jun 3, 2010, at 2:10 PM, Erin Hodgess wrote:
Dear R
If you want a matrix, then just create one from the data you have:
mydata <- matrix(strsplit(x, '\t')[[1]], nrow=1)
On Thu, Jun 3, 2010 at 1:30 PM, Kevin Burnham wrote:
> Would somebody please help me break this row:
>
> "Main Group\t1000\tMP Test\tMP Test, 1\tAudio (1, f1-qaddara.aiff)\tl
> (ta
try this:
> x <- "1234C/Tasdf"
> y <- strsplit(sub("^.*(.)/(.).*", "\\1 \\2", x),' ')[[1]]
> y
[1] "C" "T"
>
On Thu, Jun 3, 2010 at 2:18 PM, karena wrote:
>
> I have a data.frame as the following:
> var1 var2
> 9G/G09 abd89C/T90
> 10A/T9 32C/C
> 90G/G A/A
> . .
> .
Hi there,
One option would be
apply(tes, 1, function(.row) any(is.na(.row[c(1,3)])))
See ?any, ?is.na and ?apply for more information.
HTH,
Jorge
On Thu, Jun 3, 2010 at 3:20 PM, moleps <> wrote:
> Dear R´ers..
>
> In this mock dataset how can I generate a logical variable based on whether
>
On Jun 3, 2010, at 2:20 PM, moleps wrote:
> Dear R´ers..
>
> In this mock dataset how can I generate a logical variable based on whether
> just tes or tes3 are NA in each row??
>
> test<-sample(c("A",NA,"B"),100,replace=T)
> test2<-sample(c("A",NA,"B"),100,replace=T)
> test3<-sample(c("A",NA,"
you probably want to use the apply function:
d=sample(1000,500);
d[sample(500,50)]<-NA; #put 50 NAs into the data
d=data.frame(matrix(d,ncol=50));
names(d)=paste('var',1:50,sep='.')
d
apply(d,1,sum) #are any of the row values NA ?
apply(d,2,function(x)sum(is.na(x))) #how many values for each of
Thanks for your response Joris.
I was aware of the potential for aliasing, although I thought that this was
only a problem when you have missing cell means. It was interesting to read
the vehement argument regarding the Type III sums of squares, and although I
knew that there were different positi
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Gustaf Rydevik
> Sent: Thursday, June 03, 2010 7:24 AM
> To: r-help@r-project.org
> Subject: [R] moving average on irregular time series
>
> Hi all,
>
>
> I wonder if there is
-Any- was my fix... Appreciate it.
//M
On 3. juni 2010, at 21.33, Phil Spector wrote:
> ?any
>
> Not really a reproducible answer, but I think you're looking
> for
>
> apply(tes[,sam],1,function(x)any(is.na(x)))
>
>
> - Phil Spector
>
I would just like to add that when I remove the co-variate of Mean.richness
from the model (i.e. eliminating the non-orthogonality), the aliasing
warning is replaced by the following error message:
"Error in t(Z) %*% ip : non-conformable arguments"
That is when I enter this model:
carbonmean<-lm(C
Hi, I am wondering how I can specify no intercept in a mixed model using
lmer().
Here is an example dataset attached ("test.txt"). There are 3 workers, in 5
days, measured a response variable "y" on independent variable "x". I want to
use a quadratic term (x2 in the dataset) to model the relat
I am developing a S4 class but have had trouble to make setMethod work
in Window 7. I tested an example found in the setMethod manual:
> require(graphics)
> setMethod("plot", signature(x="track", y="missing"),
+ function(x, y, ...) plot(slot(x, "x"), slot(x, "y"), ...)
+ )
It gave
Thanks for your help,
I was able to get someone with root access to execute the yum command for me
and install R on the linux machine and it work!!
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View this message in context:
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Sent from the R help
Hope it helps.
text <- "var1var2
9G/G09abd89C/T90
10A/T932C/C
90G/G A/A"
x <- read.table(textConnection(text), header = T)
x$var1.1 <- sub(".*(.)/.*", "\\1", x$var1)
x$var1.2 <- sub(".*/(.).*", "\\1", x$var1)
x$var2.1 <- sub(".*(.)/.*", "\\1", x$var2)
x$var2.2 <- sub(".*/(.
Thanks for your help.
Does it have something to do with the mcmc package, the coda package, or the
lattice package ?
Jimmy
2010/6/3 Gavin Simpson
> On Wed, 2010-06-02 at 20:29 +0200, Jimmy Söderly wrote:
> > Dear R users,
> >
> > After running Sweave, this is what I get :
> >
> > Warning messa
I'm running an Ubuntu 10.04 system and installed R 2.10.1 through the package
manger. I then installed Rgraphviz 1.24 and graph 1.26 through R.
I'm trying to understand why a complex function my team wrote causes R's memory
footprint viewed through top to increase every time it's run. I traced t
On Thu, 2010-06-03 at 23:44 +0200, Jimmy Söderly wrote:
> Thanks for your help.
>
> Does it have something to do with the mcmc package, the coda package, or the
> lattice package ?
Is there something stopping you checking this for yourself? You have the
code *you* are running, after all, and we d
It appears you are facing a garbage collection issue.
?gc
Corey
On Thu, Jun 3, 2010 at 3:13 PM, Andreas Yankopolus wrote:
> I'm running an Ubuntu 10.04 system and installed R 2.10.1 through the
> package manger. I then installed Rgraphviz 1.24 and graph 1.26 through R.
>
> I'm trying to unders
I should have mentioned in my initial email: running gc() doesn't help.
You can run something like the following and watch memory usage soar:
for (ii in 1:1) {
foo()
gc()
}
Thanks,
Andreas
On Jun 3, 2010, at 18:24, Corey Dow-Hygelund wrote:
> It appears you are facing a garbage col
Could you copy the data?
Data <- data.frame(C.Mean,Mean.richness,Zoop,Diversity,Phyto)
dput(Data)
I have the feeling something's wrong there. I believe you have 48
observations (47df + 1 for the intercept), 2 levels of Diversity, 4 of Phyto
and 48/(3*4)=4 levels of Zoop. But you don't have 3df fo
Thanks! Jorge
Just one more question I don't get it even after checking help
For option, why just using with(d,...), ifelse works on stratum indexed by x
automatically ?
Since in with, we didn't specify the stratum is indexed by x, what if you
have another categorical variable in the data ?
Thanks
I see where my confusion comes from. I counted 4 levels of Phyto, but
you have 8, being 4 in every level of Diversity. There's your
aliasing.
> table(Diversity,Phyto)
Phyto
Diversity M1 M2 M3 M4 P1 P2 P3 P4
H 0 0 0 0 6 6 6 6
L 6 6 6 6 0 0 0 0
There's no ne
Thanks for the tip - this cleans up the code a lot!
Unfortunately, there is no gain in speed.
remko
On Thu, Jun 3, 2010 at 10:46 PM, nikhil kaza wrote:
> Reduce might work. Not sure about the speed advantages though. It does
> simplify code.
>
> Unionall <- function(x) Reduce('union', x)
> le
Hi Anita,
I have to correct myself too, I've been rambling a bit. Off course you don't
delete the variable out of the interaction term when you test the main
effect. What I said earlier didn't really make any sense.
That testing a main effect without removing the interaction term is has a
tricky
Hi,
I'm newish to R, a recent convert from Matlab... So far I'm impressed, and
determined to solve the following problem, which seems like it should be
easy:
I have a long (millions of points) data series recorded with a datalogger
that produced a timestamp in 4 columns: Year, Day of Year, Time in
Dear R´ers,
How can I create one single factor variable from two variables incorporating
all possible combinations of the values??
test<-sample(c("A",NA,"B"),100,replace=T)
test2<-sample(c("E",F,"A"),100,replace=T)
tes<-cbind(test,test2)
pseduocode:
r<-function(test,test2)
r
AE
AF
AA
NA
Hi,
this is what I want to do and what I found prior to ask there, but I wanted
to do that with a vector of several hundreds or thounsands of names. Because
I will have to use different vectors of very big size, my main concern was
how to import this vector from a textfile (so I just have to chang
Hi all,
I have toyed with this for too long today and in the past i used multiple
lines of code to get at what i want. Consider the following:
All i need to do is subset Pc to the values that do not equal Pc.X. The
first attempt doesnt work because i have unequal lengths. The second
attemp
Replace the non-events with NA and then use na.locf from the zoo
package to move the last event date up to give lastEvent.
Then simply select those rows whose lastEvent date is at least 14 days
ago or if the row itself is an Event:
> library(zoo) # na.locf
>
> lastEvent <- with(exData, na.locf(ife
Hi,
I made a small table of strings that will serve as variable names for lm models
I will run. The table looks like this:
> varnames
numname
11 zCANTAB_log_IED_totaltrials
22 zCANTAB_log_IED_preED
33zCANTAB_logPALerrors
44
But then you don't apply cumsum within each factor level. Hence the ddply.
Cheers
Joris
On Thu, Jun 3, 2010 at 9:35 PM, Jorge Ivan Velez
wrote:
> Or better yet, you can use transform only (in base):
> transform(Data, CUMSUM = cumsum(value))
> HTH,
> Jorge
>
> On Thu, Jun 3, 2010 at 3:30 PM, Feli
> PcToAdd_<-Pc[!(Pc %in% Pc.X)]
> PcToAdd_
[1] "Res" "Os" "Gov" "Rur"
> PcToAdd_<-subset(Pc,!(Pc %in% Pc.X))
> PcToAdd_
[1] "Res" "Os" "Gov" "Rur"
>
On Fri, Jun 4, 2010 at 1:52 AM, LCOG1 wrote:
>
> Hi all,
> I have toyed with this for too long today and in the past i used multiple
> lines
Thanks Joris, you are absolutely right. Apologies to all for that.
May be this time I can get it right :-)
transform(Data, CUMSUM = do.call(c, with(Data, tapply(value, rev(variable),
cumsum
Regards,
Jorge
On Thu, Jun 3, 2010 at 8:04 PM, Joris Meys <> wrote:
> But then you don't apply cumsu
Hi Jorge,
I found a problem.
I just want to check if the answer is random, I change the code as follows:
> d <- data.frame(x, t)
> y <- with(d, ifelse(t == 0, rbinom(2, 1, 0.5), rnorm(3)))
>
> cbind(x, t,y)
x t y
[1,] 1 0 0.000
[2,] 1 0 0.000
[3,] 1 1 0.8920037
[4,] 1 1
nuncio m wrote:
Hi all,
Is there any way in R to select the order of an ARIMA model
automatically
nuncio
Rob Hyndman's package forecast has a function auto.arima which produces
an automatic arima fit, including for seasonal models.
David Scott
--
___
Hi Carrie,
It works just fine in this case because you have the same number of 0's and
1's within each strata. If that would not be the case, option 1 would not
work. That's why I provided you a second option.
Best,
Jorge
On Thu, Jun 3, 2010 at 7:24 PM, Carrie Li <> wrote:
> Thanks! Jorge
> Ju
Hi Joris,
That seems to have worked and the contrasts look correct.
I have tried comparing the results to what SPSS produces for the same model.
The two programs produce very different results, although the model F
statistics, R squared and adjusted R squared values are identical. The
results are s
Yes, in my case here, each strata has the same number of 0's and 1's. But I
want the y to be randomly generated within each strata, so y should have
some difference across the strata. (at least for the rnorm part we would see
much clear randomness)
(I hope what I am asking here is clear to you. )
SPSS uses a different calculation. As far as I understood, they test main
effects without the covariate. Regarding the difference between my and your
results, did you use sum contrasts?
options(contrasts=c("contr.sum","contr.poly"))
On Fri, Jun 4, 2010 at 2:19 AM, Anita Narwani wrote:
> Hi Joris,
Hi Carrie,
Try running the following:
# function to create y using binomials and normals
# -- this function is based on option 2
makey <- function(d){
spd <- with(d, split(d, x))
do.call(c, lapply(spd, function(comp)
with(comp, ifelse(t == 0, rbinom(sum(t==0), 1, 0.2),
rnor
Check ?"%in%
HTH,
Jorge
On Thu, Jun 3, 2010 at 7:52 PM, LCOG1 <> wrote:
>
> Hi all,
> I have toyed with this for too long today and in the past i used multiple
> lines of code to get at what i want. Consider the following:
>
> All i need to do is subset Pc to the values that do not equal Pc.
THX
Yao Zhu
Department of Urology
Fudan University Shanghai Cancer Center
Shanghai, China
2010/6/4 Frank E Harrell Jr
> On 06/03/2010 11:32 AM, Joris Meys wrote:
>
>> You're right, it is the same. using I() won't work for the same reason
>> sqrt
>> don't, so :
>>
>> x2<- x^2
>>> lrm(y~x+x2)
Hi there,
May be expand.grid() ?
HTH,
Jorge
On Thu, Jun 3, 2010 at 5:55 PM, moleps <> wrote:
> Dear R´ers,
>
>
> How can I create one single factor variable from two variables
> incorporating all possible combinations of the values??
>
>
> test<-sample(c("A",NA,"B"),100,replace=T)
> test2<-sam
Yes I understood the strangeness of removing a main effect without
interactions that contain it because I did this during my efforts using
model simplification. I had checked out the link you sent a couple of days
ago. It was useful. So does Type II SS remove both the factor and any
interactions co
?ifelse
> t2 <- ifelse(nchar(times)<4, paste(" ", times, sep=""), times)
> strptime(t2, "%H%M")
Nikhil
On Thu, Jun 3, 2010 at 5:21 PM, Peter Moore wrote:
> Hi,
> I'm newish to R, a recent convert from Matlab... So far I'm impressed, and
> determined to solve the following problem, which seems
Minor correction below. Use 0 instead of space if you are using %H
On Thu, Jun 3, 2010 at 8:55 PM, nikhil kaza wrote:
> ?ifelse
>
> > t2 <- ifelse(nchar(times)<4, paste("0", times, sep=""), times)
>
> > strptime(t2, "%H%M")
>
> Nikhil
>
>
>
> On Thu, Jun 3, 2010 at 5:21 PM, Peter Moore wrote:
>
Roni -
Try this:
lm(formula(paste(outcome,'income + covariate1 + coviarate2',sep='~')),
data=my.data) -> model
- Phil Spector
Statistical Computing Facility
Department of
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Peter Moore
> Sent: Thursday, June 03, 2010 2:22 PM
> To: r-help@r-project.org
> Subject: [R] reformat time from hhmm
>
> Hi,
> I'm newish to R, a recent convert from Matlab... S
Ravi,
On 3 June 2010 at 09:43, Ravi Varadhan wrote:
| I have been reading about general purpose GPU (graphical processing units)
| computing for computational statistics. I know very little about this, but
| I read that GPUs currently cannot handle double-precision floating points
| and also tha
Hi Huapeng,
Firstly, it is worth noting that it is often not recommended to
overlay series with different scales, so you should think about other
ways to present your data.
Secondly, when posting here it is much more helpful to provide the
data in a form that can be copied-and-pasted into R: so r
On 06/03/2010 04:54 PM, Remko Duursma wrote:
> Thanks for the tip - this cleans up the code a lot!
> Unfortunately, there is no gain in speed.
Playing a little bit dirty,
punion <-
function(...)
{
n <- nargs()
if (0L == n) new("gpc.poly")
else if (1L == n && is(..1, "gpc.poly")) .
Hi r-users,
I would like to add a plot of vertical line segment with arrow from (77,.6) to
(77,0) and also a horizontal line segment with arrow from (0,0.6) to
(77,.6) . So far this is what I have:
plot(sq, cdf, type="l", lwd=4,col="blue",xaxs="i",yaxs="i", xlab= "Rainfall
(mm)", ylab= "Rand
Tena koe Roslina
?arrows
HTH
Peter Alspach
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Roslina Zakaria
> Sent: Friday, 4 June 2010 3:34 p.m.
> To: r-help@r-project.org
> Subject: [R] horizontal and vertical line wi
Sorry guys
It is a tab delimited text file which I just exported from SAS. I want to
import this in R. Pl let me know what is the delimiter I should use and R
syntax.
Thanks
On Thu, Jun 3, 2010 at 9:20 PM, Sarah Goslee wrote:
> That sounds like a good plan.
>
> What went wrong?
>
> You'r
Hi all,
I'm relatively new to using R, and have been trying to fit an L1
regularization path using coxpath from the glmpath library.
I'm interested in using a cross validation framework, where I crossvalidate
on a training set to select the lambda that achieves the lowest error, then
use that val
Hello Everyone,
I just started a new job & it requires heavy use of R to analyze datasets.
I have a data.table that looks like this. It is sorted by ID & Date, there
are about 150 different IDs & the dataset spans 3 million rows. The main
columns of concern are ID, date, and totret. What I need
Try unique and paste.
paste(unique(tes)[,1], unique(tes)[,2], sep = "")
-
A R learner.
--
View this message in context:
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Sent from the R help mailing list archive at Nabble.com.
__
Hello
im trying to plot 3d with scatterplot packages , everything is work on my
program below but my problenm i want to set my pressure level or axis(z-axis)
to reverse like from bottom to top, i used function "rev" but not work just for
2d plots the figure in attachment and the program
Dhanasekaran wrote:
Sorry guys
It is a tab delimited text file which I just exported from SAS. I want to
import this in R. Pl let me know what is the delimiter I should use and R
syntax.
You still don't say the error you're getting when you try your read.table
command.
__
Hello Jeff,
Try this:
test <- data.frame(totret=rnorm(10^7)) #create some sample data
test[-1,"dailyreturn"] <- test[-1,"totret"]/test[-nrow(test),"totret"]
The general idea is to take the column "totret" excluding the first 1,
dividided by "totret" exluding the last row. This gives in effect t
Thanks, I'll have a go and will let you know. I guess that the success has to
do with how efficiently I help them to demonstrate the efficiency of code over
menues. So part of the issue is how I teach them as well...
Dr. Iasonas Lamprianou
Assistant Professor (Educational Research and Evaluat
please look at the error..
> LosA<-read.table("E:\\Temporary
Tasks\\rub\\Los_R\\ca_los.txt",header=T,sep="\t")
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings,
:
line 11022 did not have 87 elements
ca_los.txt is my tab delimited large text file which contains about 16l
Hey Josh,
Thanks for the quick response!
I guess I have to switch from the Java mindset to the matrix/vector mindset
of R.
Your code worked very well, but I just have one problem:
Essentially I have a time series of stock A, followed by a time series of
stock B, etc.
So there are break points
Sir,
I have a problem regarding partitioning a matrix.I state my problem as
follows:
I have a y vector of length say 1000.Variable y has 4 levels say
0,1,2.Corresponding to each y(response), I have a x-vector(explanatory) as a
row of X matrix.Now, I want to partition the X matrix into 3 submatrice
Hey Josh,
Thanks for the quick response!
I guess I have to switch from the Java mindset to the matrix/vector mindset
of R.
Your code worked very well, but I just have one problem:
Essentially I have a time series of stock A, followed by a time series of
stock B, etc.
So there are break points
Martin,
thanks a lot! This speeds things up so much
Do you mind if I bundle your punion function in a package I am
developing (but of course I will name you the author of the function)?
greetings,
Remko
On Fri, Jun 4, 2010 at 12:17 PM, Martin Morgan wrote:
> On 06/03/2010 04:54 PM, Remk
Suman take a look if this suffices your purpous
x <- data.frame(y=as.factor(sample(0:2,1000,replace=TRUE)),x=runif(1000))
x1 <- x[x$y==0,]
x2 <- x[x$y==1,]
x3 <- x[x$y==2,]
On Fri, Jun 4, 2010 at 10:29 AM, suman dhara wrote:
> Sir,
> I have a problem regarding partitioning a matrix.I state my pr
hi,
i'm using /"boxplot()"/ to show some data:
x <- c(0.99, 0.97, 0.91, 0.72, 1.00, 0.99, 1.02, 0.90, 0.91, 0.90, 1.02,
0.90, 1.35, 1.01, 0.92)
boxplot(x)
is it correct when i say: /"Boxes represent interquartile ranges (IQRs);
bold horizontal lines, medians; whiskers, lowest and highest values
Hi there, is there any R package which address the "Text analytics" topic?
It would also be great if someone point me about some good text books on
"Text analytics" and what statistical tools and techniques are generally
used on that field.
Thanks and regards,
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Hey Jeff,
I have a few ideas. Each has some different requirements, and to help
you choose, I bench marked them.
###START###
##Basic data
> test <- data.frame(totret=rnorm(10^7), id=rep(1:10^4, each=10^3),
> time=rep(c(1, rep(0, 999)), 10^4))
##Option 1: probably the most general, but also t
Please I want to perform full data analysis using ARFIMA model but
I dont know the right package that can perform all the necessary
test on the time series data.
ERIC AIDOO
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